‘ Number of alpha emission and amount of radiation in Ci ’ should be identified. Concept introduction: Polonium is disintegrated and emitting alpha particles. Therefore, the disintegrated mass can be calculated by subtracting the mass left of Po from initial mass of Po as following. m 0 − m And thus, by multiplying the disintegrated mass with the Avogadro’s number of 218 g of Po, the number of emission can be determined. Given: T 1 / 2 = 3 min t = 25 min

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Answer 1

Question

Chapter 20, Problem 82E

Interpretation Introduction

Interpretation:

‘ Number of alpha emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Polonium is disintegrated and emitting alpha particles. Therefore, the disintegrated mass can be calculated by subtracting the mass left of Po from initial mass of Po as following.

m₀ − m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 218 g of Po, the number of emission can be determined.

Given:

$T_{1 / 2}$ = 3 min

t = 25 min

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Answer 2

Question

Chapter 20, Problem 82E

Interpretation Introduction

Interpretation:

‘ Number of alpha emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Polonium is disintegrated and emitting alpha particles. Therefore, the disintegrated mass can be calculated by subtracting the mass left of Po from initial mass of Po as following.

m₀ − m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 218 g of Po, the number of emission can be determined.

Given:

$T_{1 / 2}$ = 3 min

t = 25 min

Expert Solution & Answer

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Answer 3

Question

Chapter 20, Problem 82E

Interpretation Introduction

Interpretation:

‘ Number of alpha emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Polonium is disintegrated and emitting alpha particles. Therefore, the disintegrated mass can be calculated by subtracting the mass left of Po from initial mass of Po as following.

m₀ − m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 218 g of Po, the number of emission can be determined.

Given:

$T_{1 / 2}$ = 3 min

t = 25 min

Expert Solution & Answer

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Answer 4

Question

Chapter 20, Problem 82E

Interpretation Introduction

Interpretation:

‘ Number of alpha emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Polonium is disintegrated and emitting alpha particles. Therefore, the disintegrated mass can be calculated by subtracting the mass left of Po from initial mass of Po as following.

m₀ − m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 218 g of Po, the number of emission can be determined.

Given:

$T_{1 / 2}$ = 3 min

t = 25 min

Expert Solution & Answer

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Answer 5

Chapter 20, Problem 82E

Interpretation Introduction

Interpretation:

‘ Number of alpha emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Polonium is disintegrated and emitting alpha particles. Therefore, the disintegrated mass can be calculated by subtracting the mass left of Po from initial mass of Po as following.

m₀ − m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 218 g of Po, the number of emission can be determined.

Given:

$T_{1 / 2}$ = 3 min

t = 25 min

Answer 6

Chapter 20, Problem 82E

Interpretation Introduction

Interpretation:

‘ Number of alpha emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Polonium is disintegrated and emitting alpha particles. Therefore, the disintegrated mass can be calculated by subtracting the mass left of Po from initial mass of Po as following.

m₀ − m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 218 g of Po, the number of emission can be determined.

Given:

$T_{1 / 2}$ = 3 min

t = 25 min

Answer 7

Chapter 20, Problem 82E

Interpretation Introduction

Interpretation:

‘ Number of alpha emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Polonium is disintegrated and emitting alpha particles. Therefore, the disintegrated mass can be calculated by subtracting the mass left of Po from initial mass of Po as following.

m₀ − m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 218 g of Po, the number of emission can be determined.

Given:

$T_{1 / 2}$ = 3 min

t = 25 min

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 20 - Prob. 1E Ch. 20 - Prob. 2E Ch. 20 - Prob. 3E Ch. 20 - Prob. 4E Ch. 20 - Prob. 5E Ch. 20 - Prob. 6E Ch. 20 - Prob. 7E Ch. 20 - Prob. 8E Ch. 20 - Prob. 9E Ch. 20 - Prob. 10E

Solution Summary: The author explains that the number of alpha emission and amount of radiation in Ci should be identified.

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Chapter 20 Solutions