The mass defect and nuclear binding energy concept, mass number for nuclear binding energy per nucleon peak should be identified and significance of this should be identified. Concept introduction: Mass defect can be calculated by subtracting the total mass of product from total mass of reactant. For example: 13 Al 27 2 He 4 → 15 Psup + 0 n 1 m Al = 26.981538 u m He = 4.002603 u m p = 29.981801 u m n = 1.008664 u m Reactant = m A1 + m He = 30.984141 u m Product = m p + m n = 30.990465 u Change in mass = 30.99.465 u − 30.984141 u = 0.006324 u The mass defect is 0.006324 u

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Answer 1

Question

Chapter 20, Problem 21E

Interpretation Introduction

Interpretation:

The mass defect and nuclear binding energy concept, mass number for nuclear binding energy per nucleon peak should be identified and significance of this should be identified.

Concept introduction:

Mass defect can be calculated by subtracting the total mass of product from total mass of reactant.

For example:

₁₃Al²⁷ ₂He⁴ → ₁₅Psup + ₀n ¹

m_Al = 26.981538 u

m_He = 4.002603 u

m_p = 29.981801 u

m_n = 1.008664 u

m_Reactant = m_A1 + m_He = 30.984141 u

m_Product = m_p + m_n = 30.990465 u

Change in mass = 30.99.465 u − 30.984141 u = 0.006324 u

The mass defect is 0.006324 u

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Answer 2

Question

Chapter 20, Problem 21E

Interpretation Introduction

Interpretation:

The mass defect and nuclear binding energy concept, mass number for nuclear binding energy per nucleon peak should be identified and significance of this should be identified.

Concept introduction:

Mass defect can be calculated by subtracting the total mass of product from total mass of reactant.

For example:

₁₃Al²⁷ ₂He⁴ → ₁₅Psup + ₀n ¹

m_Al = 26.981538 u

m_He = 4.002603 u

m_p = 29.981801 u

m_n = 1.008664 u

m_Reactant = m_A1 + m_He = 30.984141 u

m_Product = m_p + m_n = 30.990465 u

Change in mass = 30.99.465 u − 30.984141 u = 0.006324 u

The mass defect is 0.006324 u

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Answer 3

Question

Chapter 20, Problem 21E

Interpretation Introduction

Interpretation:

The mass defect and nuclear binding energy concept, mass number for nuclear binding energy per nucleon peak should be identified and significance of this should be identified.

Concept introduction:

Mass defect can be calculated by subtracting the total mass of product from total mass of reactant.

For example:

₁₃Al²⁷ ₂He⁴ → ₁₅Psup + ₀n ¹

m_Al = 26.981538 u

m_He = 4.002603 u

m_p = 29.981801 u

m_n = 1.008664 u

m_Reactant = m_A1 + m_He = 30.984141 u

m_Product = m_p + m_n = 30.990465 u

Change in mass = 30.99.465 u − 30.984141 u = 0.006324 u

The mass defect is 0.006324 u

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Answer 4

Question

Chapter 20, Problem 21E

Interpretation Introduction

Interpretation:

The mass defect and nuclear binding energy concept, mass number for nuclear binding energy per nucleon peak should be identified and significance of this should be identified.

Concept introduction:

Mass defect can be calculated by subtracting the total mass of product from total mass of reactant.

For example:

₁₃Al²⁷ ₂He⁴ → ₁₅Psup + ₀n ¹

m_Al = 26.981538 u

m_He = 4.002603 u

m_p = 29.981801 u

m_n = 1.008664 u

m_Reactant = m_A1 + m_He = 30.984141 u

m_Product = m_p + m_n = 30.990465 u

Change in mass = 30.99.465 u − 30.984141 u = 0.006324 u

The mass defect is 0.006324 u

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Answer 5

Chapter 20, Problem 21E

Interpretation Introduction

Interpretation:

The mass defect and nuclear binding energy concept, mass number for nuclear binding energy per nucleon peak should be identified and significance of this should be identified.

Concept introduction:

Mass defect can be calculated by subtracting the total mass of product from total mass of reactant.

For example:

₁₃Al²⁷ ₂He⁴ → ₁₅Psup + ₀n ¹

m_Al = 26.981538 u

m_He = 4.002603 u

m_p = 29.981801 u

m_n = 1.008664 u

m_Reactant = m_A1 + m_He = 30.984141 u

m_Product = m_p + m_n = 30.990465 u

Change in mass = 30.99.465 u − 30.984141 u = 0.006324 u

The mass defect is 0.006324 u

Answer 6

Chapter 20, Problem 21E

Interpretation Introduction

Interpretation:

The mass defect and nuclear binding energy concept, mass number for nuclear binding energy per nucleon peak should be identified and significance of this should be identified.

Concept introduction:

Mass defect can be calculated by subtracting the total mass of product from total mass of reactant.

For example:

₁₃Al²⁷ ₂He⁴ → ₁₅Psup + ₀n ¹

m_Al = 26.981538 u

m_He = 4.002603 u

m_p = 29.981801 u

m_n = 1.008664 u

m_Reactant = m_A1 + m_He = 30.984141 u

m_Product = m_p + m_n = 30.990465 u

Change in mass = 30.99.465 u − 30.984141 u = 0.006324 u

The mass defect is 0.006324 u

Answer 7

Chapter 20, Problem 21E

Interpretation Introduction

Interpretation:

The mass defect and nuclear binding energy concept, mass number for nuclear binding energy per nucleon peak should be identified and significance of this should be identified.

Concept introduction:

Mass defect can be calculated by subtracting the total mass of product from total mass of reactant.

For example:

₁₃Al²⁷ ₂He⁴ → ₁₅Psup + ₀n ¹

m_Al = 26.981538 u

m_He = 4.002603 u

m_p = 29.981801 u

m_n = 1.008664 u

m_Reactant = m_A1 + m_He = 30.984141 u

m_Product = m_p + m_n = 30.990465 u

Change in mass = 30.99.465 u − 30.984141 u = 0.006324 u

The mass defect is 0.006324 u

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 20 - Prob. 1E Ch. 20 - Prob. 2E Ch. 20 - Prob. 3E Ch. 20 - Prob. 4E Ch. 20 - Prob. 5E Ch. 20 - Prob. 6E Ch. 20 - Prob. 7E Ch. 20 - Prob. 8E Ch. 20 - Prob. 9E Ch. 20 - Prob. 10E

Solution Summary: The author explains the difference between mass defect and nuclear binding energy. Mass defect is the change in mass observed in a nuclear reaction.

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Chapter 20 Solutions