Explanation If we consider after starting the radioactive disintegration of a certain nucleus after the time gap ‘t’ the number of atom disintegrate is ‘N’. Then for small gap of time ‘dt’ the disintegration of the atom will be ‘dN’. Then as per the law of radioactive disintegration the rate of decay ( − d N d t ) of the atom will be equivalent to the number of atom present at the moment. so, − d N d t ∞ N or, − d N d t = λ N (Where λ is a constant called disintegration constant or decay constant). The value of the decay constant is fixed for a radioactive material. The half life time of a radioactive material is the time required to disintegrate half of the material. It is expressed by: t 1 / 2 = 0.693 λ Given: The volume, pressure and temperature of gas sample is 1.50 L, 745 mm Hg and 25 °C and the gas sample contains 3.55% radon-220 by volume. Radon-220 is an alpha emitter with half-life of 55.6 s. Formula used: i) t 1 / 2 = 0.693 λ ii) t = 2.303 λ × log N o N iii) PV = nRT Calculation: In the gas sample volume of Radon-220 is V = 1...

Laboratory Manual For Chemistry: Structure And Properties (2nd Edition)

2nd Edition

ISBN: 9780134616452

Author: Nivaldo J. Tro, Daphne Norton

Publisher: PEARSON

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Writing and Balancing Nuclear Equations

A nuclear equation is a symbolic representation of a nuclear reaction using certain symbols. It is studied in nuclear chemistry and nuclear physics.

Question

Chapter 20, Problem 93E

Interpretation Introduction

To determine: Number of alpha particle emitted from the gas sample.

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Chapter 20, Problem 92E

Chapter 20, Problem 94E

Chapter 20 Solutions

Laboratory Manual For Chemistry: Structure And Properties (2nd Edition)

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A sample of rock was found to contain 8.23 mg of rubidium-87 and 0.47 mg of strontium-87.. (a) Calculate the age of the rock if the half-life of the decay of rubidium by emission is 4.71010 y. (b) If some S3887r was initially present in the rock, would the rock be younger, older, or the same age as the age calculated in (a)? Explain your answer.

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