Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 20.SE, Problem 67AP
Interpretation Introduction

a)

Organic Chemistry, Chapter 20.SE, Problem 67AP , additional homework tip  1

Interpretation:

Two 1HNMR spectra belonging to crotonic acid (trans-CH3CH=CHCOOH) and methacrylic acid (H2C=C (CH3) COOH) are given. Which corresponds to which is to be explained.

1HNMR: Spectrum (a): 1.91 δ (Rel.area: 3.00), 5.83 δ (Rel.area: 1.00), 7.10 δ (Rel.area: 1.00), 12.21 δ (Rel.area: 1.00).

Concept introduction:

Crotonic acid (trans-CH3CH=CHCOOH) and methacrylic acid (H2C=C (CH3) COOH) can be easily distinguished by looking the signal for the methyl protons in these two compounds.

To explain:

Of the two 1HNMR spectra given, which belongs to crotonic acid (trans-CH3CH=CHCOOH) and methacrylic acid (H2C=C (CH3) COOH).

Interpretation Introduction

b)

Organic Chemistry, Chapter 20.SE, Problem 67AP , additional homework tip  2

Interpretation:

Two 1HNMR spectra belonging to crotonic acid (trans-CH3CH=CHCOOH) and methacrylic acid (H2C=C (CH3) COOH) are given. Which corresponds to which is to be explained.

1HNMR: Spectrum (b): 1.93 δ (Rel.area: 3.00), 5.66 δ (Rel.area: 1.00), 6.25 δ (Rel.area: 1.00), 12.24 δ (Rel.area: 1.00).

Concept introduction:

Crotonic acid (trans-CH3CH=CHCOOH) and methacrylic acid (H2C=C (CH3) COOH) can be easily distinguished by looking the signal for the methyl protons in these two compounds.

To explain:

Of the two 1HNMR spectra given, which belongs to crotonic acid (trans-CH3CH=CHCOOH) and methacrylic acid (H2C=C (CH3) COOH).

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Chapter 20 Solutions

Organic Chemistry

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