ORG.CHEM W/TEXT+SOLU.MANUAL
ORG.CHEM W/TEXT+SOLU.MANUAL
15th Edition
ISBN: 9780393252125
Author: KARTY
Publisher: W.W.NORTON+CO.
Question
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Chapter 21, Problem 21.86P
Interpretation Introduction

(a)

Interpretation:

The synthesis of ethyl acetate using only acetic acid as the source of carbon is to be proposed.

Concept introduction:

A carboxylic acid is a fairly stable compound and does not readily undergo nucleophilic addition to form a new CC bond. However, it can be converted to a much less stable derivative like acid chloride using inorganic reagents such as SOCl2. Acid chloride being the least stable acid derivative readily undergoes a variety of nucleophilic addition or substitution reactions to form a new CC bond involving its carbonyl carbon.

Expert Solution
Check Mark

Answer to Problem 21.86P

Ethyl acetate can be synthesized using only acetic acid as the source of carbon in the following way.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  1

Explanation of Solution

The synthesis of ethyl acetate from acetic acid can be designed using retrosynthetic analysis.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  2

The transform is an undoing of nucleophilic substitution at the carbonyl carbon.

In the forward direction, it can be achieved by reacting to acyl chloride with ethanol, both of which derived from acetic acid. The first one can be synthesized by reacting acetic acid with SOCl2. Ethanol can be obtained by reducing acetic acid with LiAlH4.

Thus the synthesis of ethyl acetate can be carried out as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  3

Conclusion

The synthesis of ethyl acetate was proposed based on conversion of acetic acid to acid chloride followed by nucleophilic addition.

Interpretation Introduction

(b)

Interpretation:

The synthesis of butan-2-ol using only acetic acid as the source of carbon is to be proposed.

Concept introduction:

A carboxylic acid is a fairly stable compound and does not readily undergo nucleophilic addition to form a new CC bond. However, it can be converted to a much less stable derivative like acid chloride using inorganic reagents such as SOCl2. Acid chloride being the least stable acid derivative readily undergoes a variety of nucleophilic addition reactions to form a new CC bond involving its carbonyl carbon.

Expert Solution
Check Mark

Answer to Problem 21.86P

Butan-2-ol can be synthesized using only acetic acid as the source of carbon as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  4

Explanation of Solution

Butan-2-ol is a four carbon alcohol. Retrosynthetic analysis suggests the undoing of the C2-C3 bond. The corresponding precursors can be acid chloride and lithium diethyl cuprate.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  5

The acid chloride can be obtained by treating acetic acid with SOCl2. Lithium diethylcuprate can be obtained by reduction of the acid to ethanol followed by conversion to ethyl bromide using PBr3, treatment of the bromide with lithium and finally with copper(I) iodide. The reaction between acid chloride and lithium diethylcuprate will yield butanone which can be reduced with NaBH4 to butan-2-ol.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  6

Conclusion

The synthesis of butan-2-ol was proposed based on the conversion of acetic acid to acid chloride followed by nucleophilic addition and reduction.

Interpretation Introduction

(c)

Interpretation:

The synthesis of 3-methylpentan-3-ol using only acetic acid as the source of carbon is to be proposed.

Concept introduction:

A carboxylic acid is a fairly stable compound and does not readily undergo nucleophilic addition to form a new CC bond. However, it can be converted to a much less stable derivative like acid chloride using inorganic reagents such as SOCl2. Acid chloride being the least stable acid derivative readily undergoes a variety of nucleophilic addition reactions to form a new CC bond involving its carbonyl carbon.

Expert Solution
Check Mark

Answer to Problem 21.86P

3-Methylpentan-3-ol can be synthesized using only acetic acid as the source of carbon as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  7

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  8

Explanation of Solution

3-Methylpentan-3-ol is a six-carbon compound. Therefore, its synthesis from acetic acid will involve three moles of acetic acid.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  9

The first transform breaks up the bond between one ethyl group and the carbon bonded to the OH group. This fragment can come from ethyl lithium while the larger one would be butanone. Butanone, in turn, can be derived from ethyl acetate and ethyl lithium. Thus, the synthesis in the forward direction can be carried out as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  10

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  11

Conclusion

The synthesis of 3-methylpentan-3-ol was proposed based on the conversion of acetic acid to ethyl acetate followed by nucleophilic addition.

Interpretation Introduction

(d)

Interpretation:

The synthesis of butan-2-one using only acetic acid as the source of carbon is to be proposed.

Concept introduction:

A carboxylic acid is a fairly stable compound and does not readily undergo nucleophilic addition to form a new CC bond. However, it can be converted to a much less stable derivative like acid chloride using inorganic reagents such as SOCl2. Acid chloride being the least stable acid derivative readily undergoes a variety of nucleophilic addition reactions to form a new CC bond involving its carbonyl carbon.

Expert Solution
Check Mark

Answer to Problem 21.86P

Butan-2-one can be synthesized using only acetic acid as the source of carbon as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  12

Explanation of Solution

Butan-2-one is a four carbon compound. It can be synthesized with two moles of acetic acid. One mole is reduced with LiAlH4 to ethanol. Ethanol is then converted to ethyl bromide with PBr3. Reacting ethyl bromide with lithium and then copper(I) iodide will provide the nucleophile needed to add to the acid chloride. The acid chloride is derived from acetic acid by treatment with SOCl2.

Thus, butan-2-one can be synthesized as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  13

Conclusion

The synthesis of butan-2-one was proposed based on conversion of acetic acid to acid chloride followed by nucleophilic addition.

Interpretation Introduction

(e)

Interpretation:

The synthesis of ethanamine using only acetic acid as the source of carbon is to be proposed.

Concept introduction:

A carboxylic acid is a fairly stable compound and does not readily undergo nucleophilic addition to form a new CC bond. However, it can be converted to a much less stable derivative like acid chloride using inorganic reagents such as SOCl2. Acid chloride being the least stable acid derivative readily undergoes a variety of nucleophilic addition reactions to form a new CC bond involving its carbonyl carbon.

Expert Solution
Check Mark

Answer to Problem 21.86P

Ethanamine can be synthesized using only acetic acid as the source of carbon as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  14

Explanation of Solution

Ethanamine has only two carbons, the same as acetic acid. So it can be synthesized using only one mole of acetic acid. The first reaction is the conversion of the acid to acid chloride. The acid chloride can then be treated with ammonia to produce acetamide. The amide on reduction with LiAlH4 followed by acid workup will produce ethanamine.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  15

Conclusion

The synthesis of ethanamine was proposed based on the conversion of acetic acid to acid chloride followed by nucleophilic substitution and reduction.

Interpretation Introduction

(f)

Interpretation:

The synthesis of N-ethylacetamide using only acetic acid as the source of carbon is to be proposed.

Concept introduction:

A carboxylic acid is a fairly stable compound and does not readily undergo nucleophilic addition to form a new CC bond. However, it can be converted to a much less stable derivative like acid chloride using inorganic reagents such as SOCl2. Acid chloride being the least stable acid derivative readily undergoes a variety of nucleophilic addition reactions to form a new CC bond involving its carbonyl carbon.

Expert Solution
Check Mark

Answer to Problem 21.86P

N-ethylacetamide can be synthesized using only acetic acid as the source of carbon as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  16

Explanation of Solution

N-ethylacetamide is a four carbon compound. It can be synthesized using two moles of acetic acid, One mole can be converted to ethanamine as shown in part (e). The other one can be converted to acid chloride. The reaction between acid chloride and ethanamine will then yield N-ethylacetamide.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  17

Conclusion

The synthesis of N-ethylacetamide was proposed based on the conversion of acetic acid to acid chloride followed by nucleophilic substitution.

Interpretation Introduction

(g)

Interpretation:

The synthesis of N, N-diethylacetamide using only acetic acid as the source of carbon is to be proposed.

Concept introduction:

A carboxylic acid is a fairly stable compound and does not readily undergo nucleophilic addition to form a new CC bond. However, it can be converted to a much less stable derivative like acid chloride using inorganic reagents such as SOCl2. Acid chloride being the least stable acid derivative readily undergoes a variety of nucleophilic addition reactions to form a new CC bond involving its carbonyl carbon.

Expert Solution
Check Mark

Answer to Problem 21.86P

N, N-diethylacetamide can be synthesized using only acetic acid as the source of carbon as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  18

Explanation of Solution

N, N-diethylacetamide is a six carbon compound and will require three moles of acetic acid. The reaction can start with the synthesis of N-ethylacetamide as shown in part (f). Reducing this with LiAlH4 will produce diethylamine. Diethylamine can serve as the nucleophile in a reaction with acid chloride derived from acetic acid. The substitution of the chloride will form the desired product.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 21, Problem 21.86P , additional homework tip  19

Conclusion

The synthesis of N, N-diethylacetamide was proposed based on conversion of acetic acid to acid chloride followed by nucleophilic addition.

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Chapter 21 Solutions

ORG.CHEM W/TEXT+SOLU.MANUAL

Ch. 21 - Prob. 21.11PCh. 21 - Prob. 21.12PCh. 21 - Prob. 21.13PCh. 21 - Prob. 21.14PCh. 21 - Prob. 21.15PCh. 21 - Prob. 21.16PCh. 21 - Prob. 21.17PCh. 21 - Prob. 21.18PCh. 21 - Prob. 21.19PCh. 21 - Prob. 21.20PCh. 21 - Prob. 21.21PCh. 21 - Prob. 21.22PCh. 21 - Prob. 21.23PCh. 21 - Prob. 21.24PCh. 21 - Prob. 21.25PCh. 21 - Prob. 21.26PCh. 21 - Prob. 21.27PCh. 21 - Prob. 21.28PCh. 21 - Prob. 21.29PCh. 21 - Prob. 21.30PCh. 21 - Prob. 21.31PCh. 21 - Prob. 21.32PCh. 21 - Prob. 21.33PCh. 21 - Prob. 21.34PCh. 21 - Prob. 21.35PCh. 21 - Prob. 21.36PCh. 21 - Prob. 21.37PCh. 21 - Prob. 21.38PCh. 21 - Prob. 21.39PCh. 21 - Prob. 21.40PCh. 21 - Prob. 21.41PCh. 21 - Prob. 21.42PCh. 21 - Prob. 21.43PCh. 21 - Prob. 21.44PCh. 21 - Prob. 21.45PCh. 21 - Prob. 21.46PCh. 21 - Prob. 21.47PCh. 21 - Prob. 21.48PCh. 21 - Prob. 21.49PCh. 21 - Prob. 21.50PCh. 21 - Prob. 21.51PCh. 21 - Prob. 21.52PCh. 21 - Prob. 21.53PCh. 21 - Prob. 21.54PCh. 21 - Prob. 21.55PCh. 21 - Prob. 21.56PCh. 21 - Prob. 21.57PCh. 21 - Prob. 21.58PCh. 21 - Prob. 21.59PCh. 21 - Prob. 21.60PCh. 21 - Prob. 21.61PCh. 21 - Prob. 21.62PCh. 21 - Prob. 21.63PCh. 21 - Prob. 21.64PCh. 21 - Prob. 21.65PCh. 21 - Prob. 21.66PCh. 21 - Prob. 21.67PCh. 21 - Prob. 21.68PCh. 21 - Prob. 21.69PCh. 21 - Prob. 21.70PCh. 21 - Prob. 21.71PCh. 21 - Prob. 21.72PCh. 21 - Prob. 21.73PCh. 21 - Prob. 21.74PCh. 21 - Prob. 21.75PCh. 21 - Prob. 21.76PCh. 21 - Prob. 21.77PCh. 21 - Prob. 21.78PCh. 21 - Prob. 21.79PCh. 21 - Prob. 21.80PCh. 21 - Prob. 21.81PCh. 21 - Prob. 21.82PCh. 21 - Prob. 21.83PCh. 21 - Prob. 21.84PCh. 21 - Prob. 21.85PCh. 21 - Prob. 21.86PCh. 21 - Prob. 21.87PCh. 21 - Prob. 21.88PCh. 21 - Prob. 21.89PCh. 21 - Prob. 21.90PCh. 21 - Prob. 21.91PCh. 21 - Prob. 21.92PCh. 21 - Prob. 21.93PCh. 21 - Prob. 21.94PCh. 21 - Prob. 21.95PCh. 21 - Prob. 21.96PCh. 21 - Prob. 21.97PCh. 21 - Prob. 21.98PCh. 21 - Prob. 21.1YTCh. 21 - Prob. 21.2YTCh. 21 - Prob. 21.3YTCh. 21 - Prob. 21.4YTCh. 21 - Prob. 21.5YTCh. 21 - Prob. 21.6YTCh. 21 - Prob. 21.7YTCh. 21 - Prob. 21.8YTCh. 21 - Prob. 21.9YTCh. 21 - Prob. 21.10YTCh. 21 - Prob. 21.11YTCh. 21 - Prob. 21.12YT
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