Chapter 21, Problem 97A

To determine

The capacitance of the given system.

Answer to Problem 97A

  $2.00\times {10}^{-10}\text{}\text{F}$

Explanation of Solution

Given:

The given system acts a parallel plate capacitor, with the charge on the plates as, $q=0.060\mu \text{C}$

The potential applied across the capacitor system, $\Delta V=300\text{V}$

Formula used:

The capacitance is given by,

  $C=\frac{q}{\Delta V}$

Where,

  $\Delta V$ is the potential difference and q is the charge stored in the capacitor.

Calculation:

Using the above formula, the capacitance of the system will be,

  $\begin{array}{c}q=C\Delta V\\ 0.06\times {10}^{-6}=C\left(300\right)\\ =2.00\times {10}^{-10}\text{}\text{F}\end{array}$

Conclusion:

Hence, the capacitance of the system is $2.00\times {10}^{-10}\text{}\text{F}$ .