ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI
ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI
6th Edition
ISBN: 9781319306946
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 22, Problem 22.82AP
Interpretation Introduction

(a)

Interpretation:

The synthesis of 3methylcyclopentanol from the reaction of 2cyclopentenone is to be stated.

Concept introduction:

In organic chemistry, the class of functional group which is derived from conjugated diene by replacing one double bond with a carbonyl group is known as enone. The dienone compound is in conjugation to each other.

Expert Solution
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Answer to Problem 22.82AP

The synthesis of 3methylcyclopentanol from the reaction of 2cyclopentenone is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  1

Explanation of Solution

The reaction of 2cyclopentenone with halogen acids, gives addition product. This undergoes Wurtz reaction followed by reduction reaction with NaBH4, and forms the desired product. The synthesis of 3methylcyclopentanol from the reaction of 2cyclopentenone is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  2

Figure 1

Conclusion

The synthesis of 3methylcyclopentanol from the reaction of 2cyclopentenone is shown in Figure 1.

Interpretation Introduction

(b)

Interpretation:

The synthesis of 1,3,3trimethylcyclohexanol from 3methylcyclohexenone is to be stated.

Concept introduction:

In organic chemistry, the class of functional group which is derived from conjugated diene by replacing one double bond with a carbonyl group. The dienone compound is in conjugation to each other.

Expert Solution
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Answer to Problem 22.82AP

The synthesis of 1,3,3trimethylcyclohexanol from 3-methyl-2-cyclohexenone is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  3

Explanation of Solution

The reaction of 3-methyl-2-cyclohexenone with Grignard reagent gives 1, 3-dimethylcyclohex-2-enol followed. Alkylation of 1, 3-dimethylcyclohex-2-enol by NaBH4 gives the desired product. The synthesis of 1,3,3trimethylcyclohexanol from 3methylcyclohexenone is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  4

Figure 2

Conclusion

The synthesis of 1,3,3trimethylcyclohexanol from 3-methyl-2-cyclohexenone is shown in Figure 2.

Interpretation Introduction

(c)

Interpretation:

The synthesis of 2benzylcyclohexanone from diethyl heptanedioate is to be stated.

Concept introduction:

An ester is a derivative of carboxylic which is obtained by replacing the OH group with OR group where R is any hydrocarbon chain. It is represented by the formula RCOOR. An ester is formed by the reaction of carboxylic with alcohol in the presence of an acid catalyst. This reaction is known as Fischer Esterification. The reverse of esterification reaction is known as acidic hydrolysis. When ester undergoes hydrolysis in the base, it is known as saponification.

Expert Solution
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Answer to Problem 22.82AP

The synthesis of 2benzylcyclohexanone from diethyl heptanedioate is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  5

Explanation of Solution

Diethyl heptanedioate in presence of NaOEt/H3O+ results in the formation of ethyl 2-oxocyclohexanecarboxylic acid. Ethyl 2-oxocyclohexanecarboxylic acid reacts with NaOEt and PhCH2Br to form ethyl 1-benzyl-2-oxocyclohexanecarboxylic acid which on reaction with NaOH, H2O and H3O+,heat results in the formation of desired product, 2-benzylcyclohexanone. The synthesis of 2benzylcyclohexanone from diethyl heptanedioate is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  6

Figure 3

Conclusion

The synthesis of 2benzylcyclohexanone from diethyl heptanedioate is shown in Figure 3.

Interpretation Introduction

(d)

Interpretation:

The synthesis of 2,2dimethylpropane1,3diol from diethyl malonate is to be stated.

Concept introduction:

An ester is a derivative of carboxylic which is obtained by replacing the OH group with OR group where R is any hydrocarbon chain. It is represented by the formula RCOOR. An ester is formed by the reaction of carboxylic with alcohol in the presence of an acid catalyst. This reaction is known as Fischer Esterification. The reverse of esterification reaction is known as acidic hydrolysis. When ester undergoes hydrolysis in the base, it is known as saponification.

Expert Solution
Check Mark

Answer to Problem 22.82AP

The synthesis of 2,2dimethylpropane1,3diol from diethyl malonate is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  7

Explanation of Solution

The reaction of diethyl malonate in presence of base and then CH3I forms methyl monosusbtituted product. It further reacts with a base and then with CH3I forms methyl disubstituted product. Then it undergoes reduction reaction which leds to the formation of the desired product. The synthesis of 2,2dimethylpropane1,3diol from diethyl malonate is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  8

Figure 4

Conclusion

The synthesis of 2,2dimethylpropane1,3diol from diethyl malonate is shown in Figure 4.

Interpretation Introduction

(e)

Interpretation:

The synthesis of 4aminobutanol from ethyl acrylate is to be stated.

Concept introduction:

An ester is a derivative of carboxylic acid which is obtained by replacing the OH group with OR group where R is any hydrocarbon chain. It is represented by the formula RCOOR. An ester is formed by the reaction of carboxylic with alcohol in the presence of an acid catalyst. This reaction is known as Fischer Esterification. The reverse of esterification reaction is known as acidic hydrolysis. When ester undergoes hydrolysis in the base, it is known as saponification.

Expert Solution
Check Mark

Answer to Problem 22.82AP

The synthesis of 4aminobutanol from ethyl acrylate is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  9

Explanation of Solution

The reaction of ethyl acrylate with ammonia forms amide derivative. It undergoes reduction reaction with LiAlH4 followed by addition reaction with HBr in peroxides which forms 4bromobutan1amine. Then it reacts with potassium cyanide followed by hydrolysis and decarboxylation. It results in the formation of 4aminobutanol. The synthesis of 4aminobutanol from ethyl acrylate is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  10

Figure 5

Conclusion

The synthesis of 4aminobutanol from ethyl acrylate is shown in Figure 5.

Interpretation Introduction

(f)

Interpretation:

The synthesis of N1,N1diethylpropane1,3diamine from acrylonitrile is to be stated.

Concept introduction:

In organic chemistry, the compound with the molecular formula CH2=CHCN is known as acrylonitrile. It shows similar chemical properties to alkene and cyanide compounds. It is used to synthesis polyacrylonitrile polymer.

Expert Solution
Check Mark

Answer to Problem 22.82AP

The synthesis of N1,N1diethylpropane1,3diamine from acrylonitrile is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  11

Explanation of Solution

The reaction of acrylonitrile with LiAlH4 followed by addition reaction with HBr in peroxides forms 3bromopropanamine. Then it reacts with KCN followed by LiAlH4 and then amine alkylation reaction. it forms the desired product. The synthesis of N1,N1diethylpropane1,3diamine from acrylonitrile is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  12

Figure 6

Conclusion

The synthesis of N1,N1diethylpropane1,3diamine from acrylonitrile is shown in Figure 6.

Interpretation Introduction

(g)

Interpretation:

The synthesis of 2phenylbutanoicacid from phenylacetic acid is to be stated.

Concept introduction:

Carboxylic acid is a class of organic compound contains a COOH group attached with a hydrocarbon chain. They occur widely in nature that includes amino acid, acetic acid (vinegar) and so on. Deprotonation of carboxylic acid gives carboxylate anion which is mostly present in soaps. The name of these compounds ends with a suffix oicacid or icacid.

Expert Solution
Check Mark

Answer to Problem 22.82AP

The synthesis of 2phenylbutanoicacid from phenylacetic acid is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  13

Explanation of Solution

Esterification of phenylacetic acid forms ethyl 2 phenylacetate. Then it reacts with sodium ethoxide and ethyl iodide to form ethyl 2 phenylbutanoate. It undergoes saponification followed by acidic treatment to form the desired product. The synthesis of 2phenylbutanoicacid from phenylacetic acid is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  14

Figure 7

Conclusion

The synthesis of 2phenylbutanoicacid from phenylacetic acid is shown in Figure 7.

Interpretation Introduction

(h)

Interpretation:

The synthesis of 1,3diphenylbutan1one from acetophenone is to be stated.

Concept introduction:

In Aldol condensation reaction, the base abstracts an acidic proton from the α carbon atom to form enolate. This enolate or enol reacts with carbonyl compound that leads to the formation of β-hydroxyaldehyde or β-hydroxyketone which on further dehydration gives the conjugated enone.

Expert Solution
Check Mark

Answer to Problem 22.82AP

The synthesis of 1,3diphenylbutan1one from acetophenone is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  15

Explanation of Solution

The reaction of acetophenone in presence of base abstracts a α proton. It attacked on another acetophenone followed by hydrolysis it forms β hydroxyaldehyde. It undergoes dehydration reaction followed by hydrogenation forms the desired product. The synthesis of 1,3diphenylbutan1one from acetophenone is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  16

Figure 8

Conclusion

The synthesis of 1,3diphenylbutan1one from acetophenone is shown in Figure 8.

Interpretation Introduction

(i)

Interpretation:

The synthesis of deuterium substituted diphenylethanol from phenylacetic acid is to be stated.

Concept introduction:

Carboxylic acid is a class of organic compound that contains a COOH group attached with a hydrocarbon chain. They occur widely in nature that includes amino acid, acetic acid (vinegar) and so on. Deprotonation of carboxylic acid gives carboxylate anion which is mostly present in soaps. The name of these compounds ends with a suffix oicacid or icacid.

Expert Solution
Check Mark

Answer to Problem 22.82AP

The synthesis of di-deuterium substituted diphenyl ethanol from phenylacetic acid is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  17

Explanation of Solution

Reaction of 2-phenylacetic acid with ethanol and acid gives ethyl 2-phenylacetate. It reacts with heavy water in the presence of D3O+ to undergo a deuterium exchange reaction to form deutrated ethyl 2-phenylacetate. It undergoes reduction to form deutrated alcohol. This alcohol undergoes oxidation in the presence of PCC to form a deutrated aldehyde which on reaction with phenyl magnesium bromide gives the desired product. The synthesis of deuterium substituted diphenyl ethanol from phenylacetic acid is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  18

Figure 9

Conclusion

The synthesis of deuterium substituted diphenyl ethanol from phenylacetic acid is shown in Figure 9.

Interpretation Introduction

(j)

Interpretation:

The synthesis of tetra-deuterium substituted product from cyclohexanone is to be stated.

Concept introduction:

In organic chemistry, the carbonyl compound is a class of functional group which contains a C=O group. They are of two types, aldehyde CHO and ketone RC=OR. They are the oxidized product of alcohol. Tollens reagent test confirms the presence of aldehyde group only.

Expert Solution
Check Mark

Answer to Problem 22.82AP

The synthesis of tetra-deuterium substituted product from cyclohexanone is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  19

Explanation of Solution

The reaction of cyclohexanone with D2O/D3O+ followed by Wittig reaction forms the desired product. The synthesis of tetra-deuterium substituted product from cyclohexanone is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  20

Figure 10

Conclusion

The synthesis of tetra-deuterium substituted from cyclohexanone is shown in Figure 10.

Interpretation Introduction

(k)

Interpretation:

The synthesis of CH3OPhCOCH2OPh from acetyl chloride is to be stated.

Concept introduction:

Friedel Craft acylation is an electrophilic aromatic substitution reaction. In this reaction, the synthesis of the monoacylated product takes place from the reaction between aromatic rings and acyl chlorides. The organic reaction in which an organohalide is reacted with alcohols or phenols to form ethers is Willamson synthesis reaction.

Expert Solution
Check Mark

Answer to Problem 22.82AP

The synthesis of CH3OPhCOCH2OPh from acetyl chloride is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  21

Explanation of Solution

The reaction of phenol with methyl halide forms methylphenyl ether. It reacts with acetyl chloride followed by chlorination in sunlight. Then it reacts with phenol to give the desired product. The synthesis of CH3OPhCOCH2OPh from acetyl chloride is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  22

Figure 11

Conclusion

The synthesis of CH3OPhCOCH2OPh from acetyl chloride is shown in Figure 11.

Interpretation Introduction

(l)

Interpretation:

The synthesis of 4methylnonan5one from diethyl malonate is to be stated.

Concept introduction:

An ester is a derivative of carboxylic which is obtained by replacing the OH group with OR group where R is any hydrocarbon chain. It is represented by the formula RCOOR. An ester is formed by the reaction of carboxylic acid with alcohol in the presence of an acid catalyst. This reaction is known as Fischer Esterification. The reverse of esterification reaction is known as acidic hydrolysis. When ester undergoes hydrolysis in the base, it is known as saponification.

Expert Solution
Check Mark

Answer to Problem 22.82AP

The synthesis of 4methylnonan5one from diethyl malonate is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  23

Explanation of Solution

Methylation of diethyl malonate in the presence of sodium ethoxide and CH3I gives diethyl 2-methylmalonate. The conjugate addition of enolate formed by the reaction of diethyl 2-methylmalonate with sodium ethoxide on 4-methylhept-1-en-3-one gives a diester compound. It undergoes saponification followed by acidic treatment to give a diacid. This diacid undergoes decarboxylation under heating conditions to give the desired product. The synthesis of 4methylnonan5one from diethyl malonate is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  24

Figure 12

Conclusion

The synthesis of 4methylnonan5one from diethyl malonate is shown in Figure 12.

Interpretation Introduction

(m)

Interpretation:

The synthesis of 3(2oxocyclopentyl)propanoicacid from ethyl2oxocyclopentanecarboxylate is to be stated.

Concept introduction:

An ester is a derivative of carboxylic which is obtained by replacing the OH group with OR group where R is any hydrocarbon chain. It is represented by the formula RCOOR. An ester is formed by the reaction of carboxylic with alcohol in the presence of an acid catalyst. This reaction is known as Fischer Esterification. The reverse of esterification reaction is known as acidic hydrolysis. When ester undergoes hydrolysis in the base, it is known as saponification.

Expert Solution
Check Mark

Answer to Problem 22.82AP

The synthesis of 3(2oxocyclopentyl)propanoicacid from diethyl malonate is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  25

Explanation of Solution

The hydrolysis reaction of ethyl2oxocyclopentanecarboxylate followed by decarboxylation reaction forms cyclopentanone which reacts with ethyl iodide in NaH/THF followed by chlorination reaction. Further, it reacts with KCN that on hydrolysis reaction forms the desired product. The synthesis of 3(2oxocyclopentyl)propanoicacid from ethyl2oxocyclopentanecarboxylate is shown below.

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI, Chapter 22, Problem 22.82AP , additional homework tip  26

Figure13

Conclusion

The synthesis of 3(2oxocyclopentyl)propanoicacid from diethyl malonate is shown in Figure 13.

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Chapter 22 Solutions

ORGANIC CHEMISTRY (LL)+ SAPLING ACC >BI

Ch. 22 - Prob. 22.11PCh. 22 - Prob. 22.12PCh. 22 - Prob. 22.13PCh. 22 - Prob. 22.14PCh. 22 - Prob. 22.15PCh. 22 - Prob. 22.16PCh. 22 - Prob. 22.17PCh. 22 - Prob. 22.18PCh. 22 - Prob. 22.19PCh. 22 - Prob. 22.20PCh. 22 - Prob. 22.21PCh. 22 - Prob. 22.22PCh. 22 - Prob. 22.23PCh. 22 - Prob. 22.24PCh. 22 - Prob. 22.25PCh. 22 - Prob. 22.26PCh. 22 - Prob. 22.27PCh. 22 - Prob. 22.28PCh. 22 - Prob. 22.29PCh. 22 - Prob. 22.30PCh. 22 - Prob. 22.31PCh. 22 - Prob. 22.32PCh. 22 - Prob. 22.33PCh. 22 - Prob. 22.34PCh. 22 - Prob. 22.35PCh. 22 - Prob. 22.36PCh. 22 - Prob. 22.37PCh. 22 - Prob. 22.38PCh. 22 - Prob. 22.39PCh. 22 - Prob. 22.40PCh. 22 - Prob. 22.41PCh. 22 - Prob. 22.42PCh. 22 - Prob. 22.43PCh. 22 - Prob. 22.44PCh. 22 - Prob. 22.45PCh. 22 - Prob. 22.46PCh. 22 - Prob. 22.47PCh. 22 - Prob. 22.48PCh. 22 - Prob. 22.49PCh. 22 - Prob. 22.50PCh. 22 - Prob. 22.51PCh. 22 - Prob. 22.52PCh. 22 - Prob. 22.53PCh. 22 - Prob. 22.54PCh. 22 - Prob. 22.55APCh. 22 - Prob. 22.56APCh. 22 - Prob. 22.57APCh. 22 - Prob. 22.58APCh. 22 - Prob. 22.59APCh. 22 - Prob. 22.60APCh. 22 - Prob. 22.61APCh. 22 - Prob. 22.62APCh. 22 - Prob. 22.63APCh. 22 - Prob. 22.64APCh. 22 - Prob. 22.65APCh. 22 - Prob. 22.66APCh. 22 - Prob. 22.67APCh. 22 - Prob. 22.68APCh. 22 - Prob. 22.69APCh. 22 - Prob. 22.70APCh. 22 - Prob. 22.71APCh. 22 - Prob. 22.72APCh. 22 - Prob. 22.73APCh. 22 - Prob. 22.74APCh. 22 - Prob. 22.75APCh. 22 - Prob. 22.76APCh. 22 - Prob. 22.77APCh. 22 - Prob. 22.78APCh. 22 - Prob. 22.79APCh. 22 - Prob. 22.80APCh. 22 - Prob. 22.81APCh. 22 - Prob. 22.82APCh. 22 - Prob. 22.83APCh. 22 - Prob. 22.84APCh. 22 - Prob. 22.85APCh. 22 - Prob. 22.86APCh. 22 - Prob. 22.87APCh. 22 - Prob. 22.88APCh. 22 - Prob. 22.89APCh. 22 - Prob. 22.90APCh. 22 - Prob. 22.91APCh. 22 - Prob. 22.92APCh. 22 - Prob. 22.93APCh. 22 - Prob. 22.94APCh. 22 - Prob. 22.95APCh. 22 - Prob. 22.96APCh. 22 - Prob. 22.97APCh. 22 - Prob. 22.98AP
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