Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133559897
Author: KALPAKJIAN
Publisher: PEARSON
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Chapter 23, Problem 43QTP
A high-strength cast-iron bar 8 in. in diameter is being turned on a lathe at a depth of cut d = 0.050 in. The lathe is equipped with a 15-hp electric motor and has a
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in shaft turning Steel raw material, diameter 40 mm., length 200 mm. to obtain a lathe workpiece diameter 35 mm., length 150 mm, as shown in the figure, with a cutting speed of 25 m/min and a rough-cutting feed rate (f) 0.2 mm/rev. The feed rate for finishing (f) 0.1 mm per revolution determines a depth for rough turning of not more than 1 mm and a depth for finishing of not more than 0.5 mm.
Find 1) the speed of rotation used per minute.
2) Details of turning Such as how many rounds of rough turning, how many rounds of fine turning?
3) From the available data Find the approximate turning time in minutes.
A student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy = 1200ksi If the width of cut is 0.30 inand the student set a rake angle of 0and a cutting speed of 200fl / min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?
Estimate the moment, thrust force and power required for 15mm drill having a feed of 0.35 mm/rev, turningat 80 rpm, cutting a steel of Brinell hardness 250. Assume Material factor K = 1.20 and web thickness w =0.14 D. Check the values with that obtained with empirical formula.
Chapter 23 Solutions
Manufacturing Engineering & Technology
Ch. 23 - Describe the types of machining operations that...Ch. 23 - What is turning? What kind of chips are produced...Ch. 23 - What is the thrust force in turning? What is the...Ch. 23 - What are the components of a lathe?Ch. 23 - (a) What is a tracer lathe? (b) What is an...Ch. 23 - Describe the operations that can be performed on a...Ch. 23 - Why were power chucks developed?Ch. 23 - Explain why operations such as boring on a lathe...Ch. 23 - Why are turret lathes typically equipped with more...Ch. 23 - Describe the differences between boring a...
Ch. 23 - How is drill life determined?Ch. 23 - What is the difference between a conventional...Ch. 23 - Why are reaming operations performed?Ch. 23 - Explain the functions of the saddle on a lathe.Ch. 23 - Describe the relative advantages of (a)...Ch. 23 - Explain how external threads are cut on a lathe.Ch. 23 - Prob. 17RQCh. 23 - Explain the reasoning behind the various design...Ch. 23 - Note that both the terms tool strength and...Ch. 23 - (a) List and explain the factors that contribute...Ch. 23 - Explain why the sequence of drilling, boring, and...Ch. 23 - Why would machining operations be necessary even...Ch. 23 - A highly oxidized and uneven round bar is being...Ch. 23 - Describe the difficulties that may be encountered...Ch. 23 - (a) Does the force or torque in drilling change as...Ch. 23 - Explain the similarities and differences in the...Ch. 23 - Describe the advantages and applications of having...Ch. 23 - Assume that you are asked to perform a boring...Ch. 23 - Explain the reasons for the major trend that has...Ch. 23 - Describe your observations concerning the contents...Ch. 23 - The footnote to Table 23.12 states that as the...Ch. 23 - In modern manufacturing, which types of metal...Ch. 23 - Sketch the tooling marks you would expect if a...Ch. 23 - What concerns would you have in turning a powder...Ch. 23 - The operational severity for reaming is much lower...Ch. 23 - Review Fig. 23.6, and comment on the factors...Ch. 23 - Explain how gun drills remain centered during...Ch. 23 - Comment on the magnitude of the wedge angle on the...Ch. 23 - If inserts are used in a drill bit (see Fig....Ch. 23 - Refer to Fig. 23.11b, and in addition to the tools...Ch. 23 - Calculate the same quantities as in Example 23.1...Ch. 23 - Estimate the machining time required to rough turn...Ch. 23 - A high-strength cast-iron bar 8 in. in diameter is...Ch. 23 - A 0.30-in.-diameter drill is used on a drill press...Ch. 23 - In Example 23.4, assume that the workpiece...Ch. 23 - For the data in Problem 23.45, calculate the power...Ch. 23 - A 6-in.-diameter aluminum cylinder 10 in. in...Ch. 23 - A lathe is set up to machine a taper on a bar...Ch. 23 - Assuming that the coefficient of friction is 0.25,...Ch. 23 - A 3-in.-diameter, gray cast iron cylindrical part...Ch. 23 - Would you consider the machining processes...Ch. 23 - Would it be difficult to use the machining...Ch. 23 - If a bolt breaks in a hole, it typically is...Ch. 23 - An important trend in machining operations is the...Ch. 23 - Review Fig. 23.8d, and explain if it would be...Ch. 23 - Boring bars can be designed with internal damping...Ch. 23 - A large bolt is to be produced from extruded...Ch. 23 - Make a comprehensive table of the process...
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- A student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy= 1200 ksi. If the width of cut is 0.30 in. and the student set a rake angle of 0° and a cutting speed of 200 ft/ min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?arrow_forwardA 200 mm long magnesium alloy bar, 63 mm in diameter is turned on a lathe using a high speed steel cutter travelling at 180 mm/min. The spindle rotates at 450 rpm and lathe is equipped with a 10 kW motor, operating at a mechanical efficiency of 92%. The final diameter of the magnesium alloy bar is 59,5 mm. Indicate with a sketch the recommend size and location of the following tool angles: back rake, side rake, end relief, side relief and side and end cutting edge. Calculate the cutting time for the machining process.Calculate the required cutting force.arrow_forwardA slab-milling operation is carried out on a 200 mm long, 80-mm-wide annealed mild-steel workpiece having a feedrate of 0.1 mm/tooth and a depth of cut of 4.0 mm. The cutter of 50 mm diameter has 18 straight teeth and rotates at 135 rpm. The given specific energy for this material is 3.5 W s/mm3 and the slab mill is wider than the workpiece to be machined. Calculate:‧ the material-removal rate;‧ the power and torque required for this operation;‧ the cutting time. (243 mm/min, 77760 mm3/min, 4.5 kW, 52.8 s)arrow_forward
- An orthogonal cutting operation is being carried out under the following conditions: t0=0.38 mm, tc=0.65 mm, width of the cut= 2.5 mm, V=3.5 m/s, rake angle=6°, Fc= 515 N, and Ft=210 N. Calculate the percentage of the total energy that is dissipated in the shear plane.arrow_forwarda) Define specific energy for plane strain machining (cutting). b) In plane-strain orthogonal machining, the two main sources of energy dissipation are deformation along the shear plane (~70%) and friction at the tool-chip contact along the rake face (~30%). Consider plane-strain machining of a rigid perfectly-plastic work material whose uniaxial yield stress is 700 MPa, and is independent of strain rate and temperature. A tool of zero-degree rake angle is employed. Measurements showed the (deformed) chip thickness to be twice that of the undeformed chip thickness. Based on the aforementioned distribution of energy, estimate the specific energy for this process.arrow_forwardWhat force is required to punch a ½ - inch hole on a 3/8 thick plate if the ultimate shearing strength of the plate strength of the plate is 42000 psi and a factor of safety of 2?arrow_forward
- Please give the correct solution A cylinder of 25 mm diameter and 100 mm length is turned with a tool, for which the relation VT0.25 = 55 is applicable. The cutting velocity is 22 m/min. For a tool feed of 0.046 mm/rev, the number of tool regrinds required to produce 425 cylinders is?arrow_forward2 1.60 For a turning operation using a ceramic cutting tool, if the speed is increased by 50% , by what factor must the feed rate be modified to obtain a constant tool life? Use n = 0.5 and y = 0.6.arrow_forwardSuppose in a face milling operation, the dimensions of the workpiece are 5 inches by 10 inches. The cutter is 6 inches in diameter, has 8 teeth, and rotates at 300 rpm. The depth of cut is 0.125 inches and the feedrate is 0.005 inches / tooth. Assume that the specific power requirement for this material is 2 hp min / in3 and that only 75% of the cutter diameter is involved in cutting. Calculate (a) the required power, and (b) the material removal rate.arrow_forward
- 1. A 7.5 -mm-diameter drill is used on a drill press operating at 300 rpm. If the feed is 0.125 mm/rev, what is the MRR? What is the MRR if the drill diameter is doubled? 2. Assume that the work piece material is high-strength aluminum alloy and the spindle is running at N = 500 rpm. Estimate the torque required for this operation.arrow_forwardNote: Read the question carefully and give me right solutions according to the question. In orthogonal cutting of steel tube of 150 mm diameter and 2 mm thick, the cutting force was 130 kg and feed force was 35 kg for chip thickness of 0.3mm. The orthogonal cut was taken at 60 meter per minute with a feed of 0.14 mm/rev. If the back rack angle of the cutting tool was - 8 o (minus 8 degree), then calculate the shear strain and strain energy per unit volume.arrow_forwardA 78 mm thick plate is to be milled down to a thickness of 60 mm using an 80 mm face milling cutter. Calculate the processing time if the cutting depth is 6 mm, the feed/rev is 1.1 mm and the cutting speed is 15 m/min, and if the over run for a 620 mm long plate is 10 mm.arrow_forward
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