Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Textbook Question
Chapter 23, Problem 5RQ
Which operations shown in Figure 23.3 do not form a chip?
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Chapter 23 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 23 - How is the tool-work relationship in turning...Ch. 23 - What different kinds of surfaces can be produced...Ch. 23 - How does form turning differ from ordinary...Ch. 23 - What is the basic difference between facing and a...Ch. 23 - Which operations shown in Figure 23.3 do not form...Ch. 23 - Why is it difficult to make heavy cuts if a form...Ch. 23 - Show how equation 23.6 is an approximate equation.Ch. 23 - Why is the spindle of the lathe hollow?Ch. 23 - What function does a lathe carriage have?Ch. 23 - Why is feed specified for a boring operation...
Ch. 23 - Why are depths of cut in boring usually smaller...Ch. 23 - How can work be held and supported in a lathe?Ch. 23 - How is a workpiece that is mounted between centers...Ch. 23 - What will happen to the workpiece when turned, if...Ch. 23 - Why is it not advisable to hold hot-rolled steel...Ch. 23 - How does a steady rest differ from a follow rest?Ch. 23 - What are the advantages and disadvantages of a...Ch. 23 - Why should the distance the cutting tool overhangs...Ch. 23 - Prob. 19RQCh. 23 - How can a tapered part be turned on a lathe?Ch. 23 - Why might it be desirable to use a heavy depth of...Ch. 23 - If the rpm for a facing cut (assuming given work...Ch. 23 - Why is it usually necessary to take relatively...Ch. 23 - How does the corner radius of the tool influence...Ch. 23 - What effect does a BUE have on the diameter of the...Ch. 23 - How does the multiple-spindle screw machine differ...Ch. 23 - Why does boring ensure concentricity between the...Ch. 23 - Why are vertical spindle machines better suited...Ch. 23 - Prob. 29RQCh. 23 - Prob. 30RQCh. 23 - In which figures in this chapter is a dead center...Ch. 23 - Prob. 32RQCh. 23 - In which figures in this chapter showing setups do...Ch. 23 - How many form tools are being utilized in the...Ch. 23 - Prob. 35RQCh. 23 - Select the speed, feed, and depth of cut for...Ch. 23 - Calculate the rpm NS to run the spindle on a lathe...Ch. 23 - The lathe in problem 2 has rpm settings of 20, 30,...Ch. 23 - Calculate the cutting time if the length of cut is...Ch. 23 - Calculate the metal removal rate for machining at...Ch. 23 - Determine the speed, feed, and depth of cut when...Ch. 23 - At a speed of 90 fpm, feed of 0.030 ipr, and depth...Ch. 23 - Calculate the cutting time for a 4-in. length of...Ch. 23 - For a boring operation at V=90,fr=0.030, and...Ch. 23 - A cutting speed of 100 sfpm has been selected for...Ch. 23 - The following data apply for machining a part on a...Ch. 23 - A finish cut for a length of 10 in. on a diameter...Ch. 23 - A workpiece 10 in. in diameter is to be faced down...Ch. 23 - A hole 89 mm in diameter is to be drilled and...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- What is chip load?arrow_forward4:(a). In Orthogonal Cutting Model, why chip thickness after cut is greater than chip thickness beforearrow_forwardAssume that, in orthogonal cutting, the rake angle, oz,is 20° and the friction angle, B, is 35° at the chip-tool interface.Determine the percentage change in chip thickness when the friction angle is 50°. (Note: do not use Eq. (21.3)arrow_forward
- Estimate the time required to face mill a 10-inch long, 2-inch wide block of brass with a 6-inch diameter cutter with 10 high-speed steel inserts.arrow_forward44. In Orthogonal Cutting Model, why chip thickness after cut is greater than chip thickness before cut? explain.arrow_forwardIn an orthogonal machining with a tool of 9 degree orthogonal rake angle, the uncut chip thickness is 0.2mm. The chip thickness fluctuates between 0.25 mm and 0.4 mm. The ratio of the maximum shear angle to the minimum shear angle during machining isarrow_forward
- In an orthogonal cutting operation an 8 mm deep groove is to be turned on a 50 mm diameter steel bar. Spindle speed is 300 rpm and a feed rate of 0.25 mm/rev is given to the tool. Produced chips have a width of 2 mm. Calculate the material removal rate at the beginning and at the end of the cut. Can u help me please?arrow_forwardA two-spindle drill cuts two holes at the same time, one 1/2 inch and one 3/4 inch. The workpiece is 1.0 inches thick. Both drills have point angles of 118 degrees and the cutting speed for the material is 300 ft/min. The rotational speed of each drill can be set individually but the feed rate for both holes must be set to the same value because they move together into the material. The feed rate is set so that the total metal removal rate of both drills combined does not exceed 1.50 in3/min. Determine (a) maximum feed rate (in/min) that can be used, (b) individual feeds (in/rev) for each hole, and (c) cutting time for the operation.arrow_forwardWhich option about chief elements in metal cutting is wrong? a)Chip width is the distance between D and d along the cutting surface b)The cutting speed is expressed in mm per revolution c)Feed s is the tool distance moved along the axis per revolution of the work d)Depth of cut t is the distance between D and darrow_forward
- In an orthogonal turning process, the chip thickness is 0.32 mm , feed is 0.2 mm/rev, then calculate the cutting ratio.arrow_forward1. “Milling is an intermitted cutting operation”. Explain it.arrow_forwardIn a machine test, a cutting speed of 100 m/min indicated the tool life as 16 min and a cutting speed of 200 m/min indicated the tool life as 4 min. Calculate the values of n and C.arrow_forward
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