Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Chapter 23, Problem 5P
Calculate the metal removal rate for machining at a speed of 80 fpm, feed of 0.030 ipr, at a depth of 0.625 in. Use any data from Problem 4 that you need.
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Find the machining time required to turn a mild steel rod from 65mm to 58 mm over a length of 100 mm by using a carbide insert. If the approach length and over run length is taken as 5 mm, Cutting speed as 20 m/min and feed is =0.2 mm/rev, and the depth of cut is 0.5mm
Assume that, in orthogonal cutting, the rake angle is 20 and the friction angle is 35 at thechip-tool interface. Determine the percentage change in chip thickness when the frictionangle is 50. Note that Merchant’s equation is more preferable.
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Chapter 23 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 23 - How is the tool-work relationship in turning...Ch. 23 - What different kinds of surfaces can be produced...Ch. 23 - How does form turning differ from ordinary...Ch. 23 - What is the basic difference between facing and a...Ch. 23 - Which operations shown in Figure 23.3 do not form...Ch. 23 - Why is it difficult to make heavy cuts if a form...Ch. 23 - Show how equation 23.6 is an approximate equation.Ch. 23 - Why is the spindle of the lathe hollow?Ch. 23 - What function does a lathe carriage have?Ch. 23 - Why is feed specified for a boring operation...
Ch. 23 - Why are depths of cut in boring usually smaller...Ch. 23 - How can work be held and supported in a lathe?Ch. 23 - How is a workpiece that is mounted between centers...Ch. 23 - What will happen to the workpiece when turned, if...Ch. 23 - Why is it not advisable to hold hot-rolled steel...Ch. 23 - How does a steady rest differ from a follow rest?Ch. 23 - What are the advantages and disadvantages of a...Ch. 23 - Why should the distance the cutting tool overhangs...Ch. 23 - Prob. 19RQCh. 23 - How can a tapered part be turned on a lathe?Ch. 23 - Why might it be desirable to use a heavy depth of...Ch. 23 - If the rpm for a facing cut (assuming given work...Ch. 23 - Why is it usually necessary to take relatively...Ch. 23 - How does the corner radius of the tool influence...Ch. 23 - What effect does a BUE have on the diameter of the...Ch. 23 - How does the multiple-spindle screw machine differ...Ch. 23 - Why does boring ensure concentricity between the...Ch. 23 - Why are vertical spindle machines better suited...Ch. 23 - Prob. 29RQCh. 23 - Prob. 30RQCh. 23 - In which figures in this chapter is a dead center...Ch. 23 - Prob. 32RQCh. 23 - In which figures in this chapter showing setups do...Ch. 23 - How many form tools are being utilized in the...Ch. 23 - Prob. 35RQCh. 23 - Select the speed, feed, and depth of cut for...Ch. 23 - Calculate the rpm NS to run the spindle on a lathe...Ch. 23 - The lathe in problem 2 has rpm settings of 20, 30,...Ch. 23 - Calculate the cutting time if the length of cut is...Ch. 23 - Calculate the metal removal rate for machining at...Ch. 23 - Determine the speed, feed, and depth of cut when...Ch. 23 - At a speed of 90 fpm, feed of 0.030 ipr, and depth...Ch. 23 - Calculate the cutting time for a 4-in. length of...Ch. 23 - For a boring operation at V=90,fr=0.030, and...Ch. 23 - A cutting speed of 100 sfpm has been selected for...Ch. 23 - The following data apply for machining a part on a...Ch. 23 - A finish cut for a length of 10 in. on a diameter...Ch. 23 - A workpiece 10 in. in diameter is to be faced down...Ch. 23 - A hole 89 mm in diameter is to be drilled and...
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- 2 1.23 Tool life can be almost infinite at low cutting speeds.Would you then recommend that all machining be done at low speeds? Explain.arrow_forwardIn orthogonal turning of a bar 100 mm diameter with a feed of 0.25 mm/rev., depth of cut = 4 mm, cutting velocity = 90 m/min. it is observed that the main cutting force is perpendicular to friction force acting at the chip tool interface and cutting force is 1500 N. find (i) rake angle (ii) normal force.arrow_forwardIn face milling, assume that the Diameter of the cutter is 200 mm, the width of the block is 60 mm, and the length of the block is 344 mm, if the depth of cut is 3 mm, = 0.6 mm/min, and N = 100 rpm. The cutter has 12 inserts, and the workpiece material is bronze. Calculate the estimated power required, the cutting force, and the torque.arrow_forward
- Calculate the machining time required for making 60 holes on an MS plate of 80 mm thickness with a drillbit of diameter 20 mm with a cutting speed V= 40 m/min, the feed f = 0.2 mm/rev. (Assume approach length,A and over run O as 2mm and point angle as 110o). Calculate material removal rate.arrow_forwardA tool with zero rake angle used in orthogonal cutting when its clearance angle a is changed from 10 to 7 deg, Calculate the approximate % change in the life of the tool.arrow_forwardIn orthogonal turning of a low carbon steel bar of diameter 150 mm with uncoated carbide tool. the cutting velocity is 90 m/min The feed is 0.24 mm/rev and the depth of cut is 2 mm. The chip thickness obtained is 0.48 mm If the orthogonal rake angle is zero and the principal cutting edge angle is 90° Calculate the shear angle in degree.arrow_forward
- A steel rod 250 mm long and 200 mm in diameter is being reduced to 190 mm in diameter all over its length in one travel. The machine spindle rotates at 500 rpm, whereas the tool is moving at an axial feed of 0.5 mm/rev; calculate the following: Material removal rate (mm3/min) Consumed gross power in Nm/s if cutting force is 477.5N and mechanical efficiency is 90% Cutting time plzz complete in 30 minutesarrow_forward5.) Calculate the machining time required to reduce from 60mm diameter shaft to 50mm diameter, for a length of 1500mm with depth of cut 2mm for rough cut and 1mm for finish cut. Cutting speed and feed may be assumed as 30m/min and 0.5mm/rev respectively.arrow_forwardMake a figure and explain how shear plane angle effect the power requirements in the machining. How can you reduce the power requirements during machining in orthogonal cutting? plzz do it in 45 minutesarrow_forward
- Q#2 “Milling is an intermitted cutting operation”. Explain it.arrow_forwardAssume that, in orthogonal cutting, the rake angle, oz,is 20° and the friction angle, B, is 35° at the chip-tool interface.Determine the percentage change in chip thickness when the friction angle is 50°. (Note: do not use Eq. (21.3)arrow_forwardCalculate the time required for completing a 5mm deep finishing cut on a 150mm wide, 600mmlong face of a 25mm thick steel block using a face milling cutter of 150mm diameter with 6teeth. The cutting condition are Vc =1.5m/sec and fz = 0.1mm.arrow_forward
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