Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Chapter 23, Problem 10P
A cutting speed of 100 sfpm has been selected for a turning cut. The workpiece is 8 in. (203.2 mm) long and a feed of 0.020 in. (0.51 mm) per revolution is used. Using cutting speeds and feeds, calculate the machining time to turn the bar.
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In orthogonal turning of a low carbon steel bar of diameter 150 mm with uncoated carbide tool. the cutting velocity is 90 m/min The feed is 0.24 mm/rev and the depth of cut is 2 mm. The chip thickness obtained is 0.48 mm If the orthogonal rake angle is zero and the principal cutting edge angle is 90°
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In orthogonal turning of a bar 100 mm diameter with a feed of 0.25 mm/rev., depth of cut = 4 mm, cutting velocity = 90 m/min. it is observed that the main cutting force is perpendicular to friction force acting at the chip tool interface and cutting force is 1500 N. find (i) rake angle (ii) normal force.
Chapter 23 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 23 - How is the tool-work relationship in turning...Ch. 23 - What different kinds of surfaces can be produced...Ch. 23 - How does form turning differ from ordinary...Ch. 23 - What is the basic difference between facing and a...Ch. 23 - Which operations shown in Figure 23.3 do not form...Ch. 23 - Why is it difficult to make heavy cuts if a form...Ch. 23 - Show how equation 23.6 is an approximate equation.Ch. 23 - Why is the spindle of the lathe hollow?Ch. 23 - What function does a lathe carriage have?Ch. 23 - Why is feed specified for a boring operation...
Ch. 23 - Why are depths of cut in boring usually smaller...Ch. 23 - How can work be held and supported in a lathe?Ch. 23 - How is a workpiece that is mounted between centers...Ch. 23 - What will happen to the workpiece when turned, if...Ch. 23 - Why is it not advisable to hold hot-rolled steel...Ch. 23 - How does a steady rest differ from a follow rest?Ch. 23 - What are the advantages and disadvantages of a...Ch. 23 - Why should the distance the cutting tool overhangs...Ch. 23 - Prob. 19RQCh. 23 - How can a tapered part be turned on a lathe?Ch. 23 - Why might it be desirable to use a heavy depth of...Ch. 23 - If the rpm for a facing cut (assuming given work...Ch. 23 - Why is it usually necessary to take relatively...Ch. 23 - How does the corner radius of the tool influence...Ch. 23 - What effect does a BUE have on the diameter of the...Ch. 23 - How does the multiple-spindle screw machine differ...Ch. 23 - Why does boring ensure concentricity between the...Ch. 23 - Why are vertical spindle machines better suited...Ch. 23 - Prob. 29RQCh. 23 - Prob. 30RQCh. 23 - In which figures in this chapter is a dead center...Ch. 23 - Prob. 32RQCh. 23 - In which figures in this chapter showing setups do...Ch. 23 - How many form tools are being utilized in the...Ch. 23 - Prob. 35RQCh. 23 - Select the speed, feed, and depth of cut for...Ch. 23 - Calculate the rpm NS to run the spindle on a lathe...Ch. 23 - The lathe in problem 2 has rpm settings of 20, 30,...Ch. 23 - Calculate the cutting time if the length of cut is...Ch. 23 - Calculate the metal removal rate for machining at...Ch. 23 - Determine the speed, feed, and depth of cut when...Ch. 23 - At a speed of 90 fpm, feed of 0.030 ipr, and depth...Ch. 23 - Calculate the cutting time for a 4-in. length of...Ch. 23 - For a boring operation at V=90,fr=0.030, and...Ch. 23 - A cutting speed of 100 sfpm has been selected for...Ch. 23 - The following data apply for machining a part on a...Ch. 23 - A finish cut for a length of 10 in. on a diameter...Ch. 23 - A workpiece 10 in. in diameter is to be faced down...Ch. 23 - A hole 89 mm in diameter is to be drilled and...
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- A 78 mm thick plate is to be milled down to a thickness of 60 mm using an 80 mm face milling cutter. Calculate the processing time if the cutting depth is 6 mm, the feed/rev is 1.1 mm and the cutting speed is 15 m/min, and if the over run for a 620 mm long plate is 10 mm.arrow_forwardAssuming that the coefficient of friction is 0.25, calculate the maximum depth of cut forturning a hard aluminium alloy on a 15-kW lathe (with a mechanical efficieny of 80%) at awidth of cut of 6 mm, rake angle of 0˚, and a cutting speed of 90 m/min, shear strength of 150 MPa.arrow_forwardIn machining a mild steel work piece with carbide tool, the life of the tool was found to be 1 hour and 40 minutes, at a spindle speed of 25 m/min. Calculate the tool life if it has to be operated at a speed of 30% higher than the initial cutting speed. Also calculate the cutting speed if the tool is required to have a life of 2 hours and 45 minutes. Assume Taylor’s exponent value n is 0.28.arrow_forward
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