COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Question
Chapter 24, Problem 102QAP
To determine
(a)
The magnification of the 36-in refractor.
To determine
(b)
Explain the negative sign meaning in magnification equation.
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A student makes a microscope using an objective lens and an eyepiece. If she moves the lenses closer together, does the microscope’s magnification increase or decrease? Explain.
A patient goes to the optometrist and complains that her contact lenses don’t work well any more, because even when she is wearing them, she is no longer able to focus on objects closer than about 30 cm. People with “normal vision” can focus on objects as close as 25 cm.
- Is the patient near-sighted or far-sighted?
- The optometrist inspects the contacts and finds that they have a focal length of +40 cm. Assuming the contacts worked correctly when she first got them, what was the patient’s near point at the time her old prescription was made?
- What should be the focal length for the new contact lenses prescribed by the optometrist?
Problem Solving
a. A child with nearsighted can read a book at a near point 1 meter. In order to read at a normal reading distance of 25 cm, determine the power of the lens must use by the child.
Chapter 24 Solutions
COLLEGE PHYSICS
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- A cataract-impaired lens in an eye may be surgically removed and replaced by a manufactured lens. The focal length required for the new lens is determined by the lens-lo-retina distance, which is measured by a sonar-like device, and by the requirement that the implant provide for correct distance vision. (a) If the distance from lens to retina is 22.4 mm, calculate the power of the implanted lens in diopters. (b) Since there is no accommodation and the implant allows for correct distance vision, a corrective lens for close work or reading must be used. Assume a reading distance of 33.0 cm, and calculate the power of the lens in the reading glasses.arrow_forwardConstruct Your Own Problem Consider a telescope of the type used by Galileo, having a convex objective and a concave eyepiece as illustrated in part (a) of Figure 2.40. Construct a problem in which you calculate the location and size of the image produced. Among the things to be considered are the focal lengths of the lenses and their relative placements as well as the size and location of the object. Verify that the angular magnification is greater than one. That is, the angle subtended at the eye by the image is greater than the angle subtended by the object.arrow_forwardDuring LASIK eye surgery (laser-assisted in situ keratomileusis), the shape of the cornea is modified by vaporizing some of its material. If the surgery is performed to correct for nearsightedness, how does the cornea need to be reshaped?arrow_forward
- A cataract-impaired lens in an eye may be surgically removed and replaced by a manufactured lens. The focal length required for the new lens is determined by the lens-lo-retina distance, which is measured by a sonar-like device, and by the requirement that the implant provide for correct distance vision. (a) If the distance from lens to retina is 22.4 mm, calculate the power of the implanted lens in diopters. (b) Since there is no accommodation and the implant allows for correct distance vision, a corrective lens for close work or reading must be used. Assume a reading distance of 33.0 cm, and calculate the power of the lens in the reading glasses.arrow_forwardUnreasonable Results Your friends show you an image through a microscope. They tell you that the microscope has an objective with a 0.500-cm focal length and an eyepiece with a 5.00-cm focal length. The resulting overall magnification is 250,000. Are these viable values for a microscope? Unless otherwise stated, the lens-to-retina distance is 2.00 cm.arrow_forwardWill the focal length of a lens change when it is submerged in water? Explain.arrow_forward
- To fit a contact lens to a patient's eye, a keratometer can be used to measure the curvature of the corneathe front surface of the eye. This instrument places an illuminated object of known .size at a known distance p from the cornea, which then reflects some light from the object, forming an image of it The magnification M of the image is measured by using a small viewing telescope that allows a comparison of the image formed by the cornea with a second calibrated image projected into the field of view by a prism arrangement. Determine the radius of curvature of the cornea when p = 30.0 cm and M = 0.013 0.arrow_forwardCan an image be larger than the object even though its magnification is negative? Explain.arrow_forwardWhy is your vision so blurry when you open your eyes while swimming under water? How does a face mask enable clear vision?arrow_forward
- Andy decides to use an old pair of eyeglasses to make some optical instruments. He knows that the near point in his left eye is 50.0 cm and the near point in his right eve is 100 cm. (a) What is the maximum angular magnification he can produce in a telescope? (b) If he places the lenses 10.0 cm apart, what is the maximum overall magnification he can produce in a microscope? Hint: Go back to basics and use the thin lens equation to solve part (b).arrow_forwardA person with a nearsighted eye has near and far points of 16 cm and 25 cm, respectively. (a) Assuming a lens is placed 2.0 cm from the eye, what power must the lens have to correct this condition? (b) Suppose contact lenses placed directly on the cornea are used to correct the person's eyesight. What is the power of the lens required in this case, and what is the new near point? Hint: The contact lens and the eyeglass lens require slightly different powers because they are at different distances from the eye.arrow_forwardUnreasonable Results Your friends show you an image 1hrough a microscope. They tell you that the microscope has an objective with a 0.500 cm focal length and an eyepiece with a 5.00 cm focal laugh. The resulting overall magnification is 250,000. Are 1hese viable values for a microscope?arrow_forward
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Convex and Concave Lenses; Author: Manocha Academy;https://www.youtube.com/watch?v=CJ6aB5ULqa0;License: Standard YouTube License, CC-BY