EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 25, Problem 25.18P
Interpretation Introduction
(a)
Interpretation:
Concept Introduction:
The energy change for any reaction can be calculated as the sum of the energy changes for other reactions.
Interpretation Introduction
(b)
Interpretation:
It is to be explained why the hydrolysis of phosphocreatine releases a lot of energy.
Concept Introduction:
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Chapter 25 Solutions
EBK ORGANIC CHEMISTRY
Ch. 25 - Prob. 25.1PCh. 25 - Prob. 25.2PCh. 25 - Prob. 25.3PCh. 25 - Prob. 25.4PCh. 25 - Prob. 25.5PCh. 25 - Prob. 25.6PCh. 25 - Prob. 25.7PCh. 25 - Prob. 25.8PCh. 25 - Prob. 25.9PCh. 25 - Prob. 25.10P
Ch. 25 - Prob. 25.11PCh. 25 - Prob. 25.12PCh. 25 - Prob. 25.13PCh. 25 - Prob. 25.14PCh. 25 - Prob. 25.15PCh. 25 - Prob. 25.16PCh. 25 - Prob. 25.17PCh. 25 - Prob. 25.18PCh. 25 - Prob. 25.19PCh. 25 - Prob. 25.20PCh. 25 - Prob. 25.21APCh. 25 - Prob. 25.22APCh. 25 - Prob. 25.23APCh. 25 - Prob. 25.24APCh. 25 - Prob. 25.25APCh. 25 - Prob. 25.26APCh. 25 - Prob. 25.27APCh. 25 - Prob. 25.28APCh. 25 - Prob. 25.29APCh. 25 - Prob. 25.30APCh. 25 - Prob. 25.31APCh. 25 - Prob. 25.32APCh. 25 - Prob. 25.33APCh. 25 - Prob. 25.34APCh. 25 - Prob. 25.35APCh. 25 - Prob. 25.36APCh. 25 - Prob. 25.37APCh. 25 - Prob. 25.38APCh. 25 - Prob. 25.39APCh. 25 - Prob. 25.40AP
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- Another step in the metabolism of glucose, which occurs after the formation of glucose6-phosphate, is the conversion of fructose6-phosphate to fructose1,6-bisphosphate(bis meanstwo): Fructose6-phosphate(aq) + H2PO4(aq) fructose l,6-bisphosphate(aq) + H2O() + H+(aq) (a) This reaction has a Gibbs free energy change of +16.7 kJ/mol of fructose6-phosphate. Is it endergonic or exergonic? (b) Write the equation for the formation of 1 mol ADP fromATR for which rG = 30.5 kJ/mol. (c) Couple these two reactions to get an exergonic process;write its overall chemical equation, and calculate theGibbs free energy change.arrow_forwarda Calculate K1, at 25C for phosphoric acid: H3PO4(aq)H+(aq)+H2PO4(aq) b Which thermodynamic factor is the most significant in accounting for the fact that phosphoric acid is a weak acid? Why ?arrow_forwardThe value of ΔG° for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate (GAP) is 7.53 kJ/mol. If the concentration of dihydroxyacetone phosphate at equilibrium is 2.85 mM, what is the concentration of glyceraldehyde-3-phosphate?Assume a temperature of 25.0 °C.[GAP] = ???? mMarrow_forward
- 11. What is the ΔHº-value for the dissolution of NaOH (s) to yield 1.00... m NaOH (aq), given: Na (s) + 1/2 O2 (g) + 1/2 H2 (g) → NaOH (s) ΔHfº = -425.9 kJ/mol Na (s) + 1/2 O2 (g) + 1/2 H2 (g) → NaOH (aq, 1 m) ΔHfº = -469.2 kJ/mol Multiple Choice -895.1 kJ/mol -43.3 kJ/mol +1.102 kJ/mol +43.3 kJ/mol +895.1 kJ/molarrow_forwardGiven that the reaction of 4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 3 H20 (g) ΔΗ - - 906 kJ What would AH for NO (g) + ? H20 (g) → NH3 (g) + O2 (g) be? 2. 906 kJ 226.5 kJ -226.5kJ 453 kJarrow_forwardCalculate the equilibrium constant for the phosphorylation of glucose to glucose 6-phosphate at 37.0 °C. K'eq = 4.74 x10-3 In the rat hepatocyte, the physiological concentrations of glucose and P₁ are maintained at approximately 4.8 mM. What is the equilibrium concentration of glucose 6-phosphate (G6P) obtained by the direct phosphorylation of glucose by P₁? [G6P]: 8.75 X10-8 M-1 Incorrect Marrow_forward
- 5. One reaction that occurs in human metabolism is HO₂CCH₂CH₂CHCO₂H(aq) + NH3(aq)= | NH₂ Glutamic acid H₂NCCH₂CH₂CHCO₂H(aq) + H₂O(l) | NH₂ Glutamine For this reaction 4G° = 14 kJ at 25°C. a. Calculate K for this reaction at 25°C. b. In a living cell this reaction is coupled with the hydrolysis of ATP. (ATP(aq) + H₂O(l) → ADP(aq) + H₂PO4 (aq) AG°= -30.5 kJ/mol) Calculate 4G and K at 25°C for the following reaction Glutamic acid(aq) + ATP(aq) + NH3(aq) Glutamine(aq) + ADP(aq) + H₂PO4 (aq) [the hydrolysis of ATP] Cells use the hydrolysis of ATP, as a source of energy. Symbolically, this reaction can be written as ATP(aq) + H₂O(ADP(aq) + H₂PO4 (aq) *ATP: adenosine triphosphate. *ADP: adenosine diphosphate. AG-30.5 kJarrow_forward3. Compute the equilibrium constant (Keq) for the synthesis of glucose-1-phosphate at 37\deg C, based on the reaction: Glucose + HPO4^2- Glucose-1-phosphate + H2O,arrow_forwardHO AG° = HOT HO OH a form of glucose OH a form ß form H - Which of the two forms is most stable: HO HO HO OH B form of glucose H COH At equilibrium at 25 °C, the two forms are present in a ratio of approximately 64 : 36. Calculate the standard free energy (AG°) difference that corresponds to this equilibrium ratio (i.e. more stable form : less stable form). Kcal/molarrow_forward
- Consider the following reaction: H2 + Br2 →. HBr ΔH = -43 kcal/mol ΔS = 0.0272 kcal/mol What is the ΔG value for the reaction at 300 K?arrow_forwardThe Ka of HCHO2 is 1.8 x 10-4. Calculate the ΔGº (in kJ/mol) for the acid dissociation reaction at 25ºCarrow_forwardWhat does δ1.9 and δ2.8 ppm stand representarrow_forward
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