Three plausible termination steps for the reaction in Equation 25-32 are to be drawn. Concept introduction: A hydrogen halide adds across the double bond of an alkene in a Markovnikov fashion under normal conditions. H + adds to the less alkyl-substituted C atom whereas the halide anion adds to the more alkyl-substituted C atom. The reason is that the first step of the mechanism is protonation of the C=C double bond, which proceeds to give the more stable carbocation intermediate. If a small amount of peroxide ( RO-OR ) is present, however, then the major product is produced according to anti-Markovnikov addition. The H atom adds to the more substituted C , and the halide atom adds to the less substituted one. Peroxides are radical initiators because they contain a weak O-O bond. Hence, the reaction in Equation 25-32 proceeds by radical mechanism.

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Answer 1

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Chapter 25, Problem 25.21YT

Interpretation Introduction

Interpretation:

Three plausible termination steps for the reaction in Equation 25-32 are to be drawn.

Concept introduction:

A hydrogen halide adds across the double bond of an alkene in a Markovnikov fashion under normal conditions. H+ adds to the less alkyl-substituted C atom whereas the halide anion adds to the more alkyl-substituted C atom. The reason is that the first step of the mechanism is protonation of the C=C double bond, which proceeds to give the more stable carbocation intermediate. If a small amount of peroxide (RO-OR) is present, however, then the major product is produced according to anti-Markovnikov addition. The H atom adds to the more substituted C, and the halide atom adds to the less substituted one. Peroxides are radical initiators because they contain a weak O-O bond. Hence, the reaction in Equation 25-32 proceeds by radical mechanism.

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Answer 2

Question

Chapter 25, Problem 25.21YT

Interpretation Introduction

Interpretation:

Three plausible termination steps for the reaction in Equation 25-32 are to be drawn.

Concept introduction:

A hydrogen halide adds across the double bond of an alkene in a Markovnikov fashion under normal conditions. H+ adds to the less alkyl-substituted C atom whereas the halide anion adds to the more alkyl-substituted C atom. The reason is that the first step of the mechanism is protonation of the C=C double bond, which proceeds to give the more stable carbocation intermediate. If a small amount of peroxide (RO-OR) is present, however, then the major product is produced according to anti-Markovnikov addition. The H atom adds to the more substituted C, and the halide atom adds to the less substituted one. Peroxides are radical initiators because they contain a weak O-O bond. Hence, the reaction in Equation 25-32 proceeds by radical mechanism.

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Answer 3

Question

Chapter 25, Problem 25.21YT

Interpretation Introduction

Interpretation:

Three plausible termination steps for the reaction in Equation 25-32 are to be drawn.

Concept introduction:

A hydrogen halide adds across the double bond of an alkene in a Markovnikov fashion under normal conditions. H+ adds to the less alkyl-substituted C atom whereas the halide anion adds to the more alkyl-substituted C atom. The reason is that the first step of the mechanism is protonation of the C=C double bond, which proceeds to give the more stable carbocation intermediate. If a small amount of peroxide (RO-OR) is present, however, then the major product is produced according to anti-Markovnikov addition. The H atom adds to the more substituted C, and the halide atom adds to the less substituted one. Peroxides are radical initiators because they contain a weak O-O bond. Hence, the reaction in Equation 25-32 proceeds by radical mechanism.

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Answer 4

Question

Chapter 25, Problem 25.21YT

Interpretation Introduction

Interpretation:

Three plausible termination steps for the reaction in Equation 25-32 are to be drawn.

Concept introduction:

A hydrogen halide adds across the double bond of an alkene in a Markovnikov fashion under normal conditions. H+ adds to the less alkyl-substituted C atom whereas the halide anion adds to the more alkyl-substituted C atom. The reason is that the first step of the mechanism is protonation of the C=C double bond, which proceeds to give the more stable carbocation intermediate. If a small amount of peroxide (RO-OR) is present, however, then the major product is produced according to anti-Markovnikov addition. The H atom adds to the more substituted C, and the halide atom adds to the less substituted one. Peroxides are radical initiators because they contain a weak O-O bond. Hence, the reaction in Equation 25-32 proceeds by radical mechanism.

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Answer 5

Chapter 25, Problem 25.21YT

Interpretation Introduction

Interpretation:

Three plausible termination steps for the reaction in Equation 25-32 are to be drawn.

Concept introduction:

A hydrogen halide adds across the double bond of an alkene in a Markovnikov fashion under normal conditions. H+ adds to the less alkyl-substituted C atom whereas the halide anion adds to the more alkyl-substituted C atom. The reason is that the first step of the mechanism is protonation of the C=C double bond, which proceeds to give the more stable carbocation intermediate. If a small amount of peroxide (RO-OR) is present, however, then the major product is produced according to anti-Markovnikov addition. The H atom adds to the more substituted C, and the halide atom adds to the less substituted one. Peroxides are radical initiators because they contain a weak O-O bond. Hence, the reaction in Equation 25-32 proceeds by radical mechanism.

Answer 6

Chapter 25, Problem 25.21YT

Interpretation Introduction

Interpretation:

Three plausible termination steps for the reaction in Equation 25-32 are to be drawn.

Concept introduction:

A hydrogen halide adds across the double bond of an alkene in a Markovnikov fashion under normal conditions. H+ adds to the less alkyl-substituted C atom whereas the halide anion adds to the more alkyl-substituted C atom. The reason is that the first step of the mechanism is protonation of the C=C double bond, which proceeds to give the more stable carbocation intermediate. If a small amount of peroxide (RO-OR) is present, however, then the major product is produced according to anti-Markovnikov addition. The H atom adds to the more substituted C, and the halide atom adds to the less substituted one. Peroxides are radical initiators because they contain a weak O-O bond. Hence, the reaction in Equation 25-32 proceeds by radical mechanism.

Answer 7

Chapter 25, Problem 25.21YT

Interpretation Introduction

Interpretation:

Three plausible termination steps for the reaction in Equation 25-32 are to be drawn.

Concept introduction:

A hydrogen halide adds across the double bond of an alkene in a Markovnikov fashion under normal conditions. H+ adds to the less alkyl-substituted C atom whereas the halide anion adds to the more alkyl-substituted C atom. The reason is that the first step of the mechanism is protonation of the C=C double bond, which proceeds to give the more stable carbocation intermediate. If a small amount of peroxide (RO-OR) is present, however, then the major product is produced according to anti-Markovnikov addition. The H atom adds to the more substituted C, and the halide atom adds to the less substituted one. Peroxides are radical initiators because they contain a weak O-O bond. Hence, the reaction in Equation 25-32 proceeds by radical mechanism.

Answer 8

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Answer 11

Ch. 25 - Prob. 25.1P Ch. 25 - Prob. 25.2P Ch. 25 - Prob. 25.3P Ch. 25 - Prob. 25.4P Ch. 25 - Prob. 25.5P Ch. 25 - Prob. 25.6P Ch. 25 - Prob. 25.7P Ch. 25 - Prob. 25.8P Ch. 25 - Prob. 25.9P Ch. 25 - Prob. 25.10P

Solution Summary: The author explains that hydrogen halide adds across the double bond of an alkene in a Markovnikov fashion under normal conditions.

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