Becker's World of the Cell (9th Edition)
9th Edition
ISBN: 9780321934925
Author: Jeff Hardin, Gregory Paul Bertoni
Publisher: PEARSON
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Chapter 25, Problem 25.4CC
Summary Introduction
To determine: Whether the given information can be used to determine the order of genes A, B, and C on the same chromosome.
Introduction: Genes lying closely together on the same chromosome can be used to observe a pattern of segregation. Experiments conducted on fruit flies by Morgan depicted that the distance between the two genes lying on the same chromosome may give a measure of the frequency of their recombination. Genes lying far apart from each other show more chances of being separated by a crossover.
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Below are the recombination frequencies between pairs of genes A, B, C and D. Based on this, what order do the genes have on a chromosome?
Consider the genetic map below. (a) In a total of 1000 observed progeny, how many would be expected to be parental, non-recombinant? (b) If the total number of observed double-crossover recombinant progeny is 0, what is the interference? Show step by step
A-------10cm-----B—2.5cm----C
Explain why the value of the recombination frequencybetween any two genes is limited to 50%.
Chapter 25 Solutions
Becker's World of the Cell (9th Edition)
Ch. 25 - Cloning can be done by somatic cell nuclear...Ch. 25 - If the DNA content of a diploid cell in the G1...Ch. 25 - Prob. 25.3CCCh. 25 - Prob. 1QCh. 25 - Prob. 25.4CCCh. 25 - What do you think would happen to a pathogenic...Ch. 25 - Prob. 25.6CCCh. 25 - The Truth About Sex. For each of the following...Ch. 25 - Ordering the Phases of Meiosis. Drawings of...Ch. 25 - Telling Them Apart. Briefly describe how you might...
Ch. 25 - Prob. 25.4PSCh. 25 - More about DNA. Let X be the amount of DNA present...Ch. 25 - Meiotic Mistakes. Infants born with Patau syndrome...Ch. 25 - Prob. 25.7PSCh. 25 - QUANTITATIVE Punnett Squares as Genetic Tools. The...Ch. 25 - QUANTITATIVE Genetic Mapping. The following table...Ch. 25 - Prob. 25.10PSCh. 25 - Prob. 25.11PS
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Given the experimental set up below, and knowing the genes for stalked eyes (st) and black bodies (b) are on the same chromosome and recessive to wild type (un-stalked eyes and light body). F2= a=489, b=56, c=497, d=49 A) How many recombinant animals are in the F2 generation? B) ( How far apart, (as both a % recombination and in map units) are the stalk eyed and black bodied genes on this chromosome?arrow_forwardIn your own words, explain why a testcross cannot produce more than 50% recombinant offspring. When a testcross does produce 50% recombinant offspring, what does this result mean?arrow_forwardConsider the genetic map below. (a) In a total of 1000 observed progeny, how many would be expected to be parental, non-recombinant? (b) If the total number of observed double-crossover recombinant progeny is 0, what is the interference? Show step by step work for full credit. A-------10cm-----B—2.5cm----Carrow_forward
- Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?arrow_forwardPart A: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be AB? Enter your answer as a decimal to three places (for example: 0.120). Part B: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be Ab? Part C: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be aB? Part D: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a signal plant will be ab?arrow_forwardIn most tests of genetic linkage, the number of double crossovers is less than the number expected due to what effect, which limits the number of crossovers that can occur in a short length of chromosome?arrow_forward
- Why is random assortment of chromosomes necessary? What can we expect if this does not occur?arrow_forwardIn linkage mapping, how do we measure the distance between genes on a chromosome? options: A) The number of gametes used is proportional to the percent recombination in offspring. B) The number of offspring produced is equal to the percent recombination during crossover. C) The number of chromosomes resulting from crossover is equal to the distance the genes are apart in any one gamete. D) The percentage of recombinant offspring is directly proportional to how far apart the genes are on the chromosome.arrow_forwardConsider two loci A and B that are 30 cM apart on chromosome 1 in the fruit fly. A paracentric inversion is found to span about half of the distance between these loci, but not include either A or B. What is the approximate recombination frequency expected for these loci in … flies that are heterozygous for this inversion? RF(A-B) for heterozygous flies is … flies that are homozygous for this inversion? RF(A-B) for homozygous flies is …arrow_forward
- To determine the recombination frequency between body color and wing genes in flies, you perform several crosses where you cross an F1 having red body and smooth wings with a yellow-bodied, crinkle-winged fly. You get the following results. What is the distance between the genes for body color and wing surface in map units?arrow_forwardOn an episode of the science fiction television program Doctor Who, the “Progenation Machine” can take a tissue sample from an individual, duplicate all their chromosomes many times, then assemble a new individual with a complete set of homologous pairs by randomly selecting two of each set of chromosomes. If this actually worked, and wasn’t just a fictional construct, what is the maximum number of genetically distinct individuals that could be produced in this way from a humanarrow_forwardIn a species of rat, the map unit distance between genes A, B, C and D were asfollows: (in the picture) (a) What is the order of these genes on the chromosome? (b) What is the map unit distance between B and D?arrow_forward
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