Chapter 25, Problem 58A

To determine

To calculate:Potential difference when the primary and secondary circuits are reversed.

Answer to Problem 58A

Potential difference when the primary and secondary circuits are reversed is $72$ V.

Explanation of Solution

Given:

  $V_s=8.0$ V

  $V_s=8.0$ V

Formula Used:

  $\frac{N_s}{N_p}=\frac{V_s}{V_p}$

where,

  $V_s$ = Effective potential difference of secondary coil

  $N_p$ = Number of turns of primary coil

  $V_p$ = Effective potential difference of primary coil

  $N_s$ = No of turns of secondary coil

Calculation:

The turns ratio can be given as,

  $\begin{array}{l}\frac{N_s}{N_p}=\frac{V_s}{V_p}\\ =\frac{8.0}{\begin{array}{l}24\\ =\frac{1.0}{\begin{array}{l}3.0\\ \end{array}}\end{array}}\end{array}$

After reversing it would be = $=\frac{3.0}{1.0}$

Thus potential difference when the primary and secondary circuits are reversed can be calculated as,

  $\frac{N_s}{N_p}=\frac{V_s}{V_p}$

Rearranging the equation,

  $V_s=\frac{N_s}{N_p}{V}_p$

Substituting the values in above formula,

  $=\left(\frac{3.0}{1.0}\right)(24)$

  $=72$ V

Conclusion:

Hencepotential difference when the primary and secondary circuits are reversed is $=72$ V.