Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 25.SE, Problem 30MP
Interpretation Introduction

Concept introduction:

The scheme of reactions is an instance of Glucose–Galactose interconversion, specifically in LIVER.

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One step in glycolysis is the conversion of fructose-6-phosphate to fructose-1,6-bisphosphate. The direct reaction of fructose-6-phosphate with inorganic phosphate fructose-6-phosphate + Pi ⇌ fructose-1,6-bisphosphate + H₂O is very unfavorable, with ∆G'°= 16.3 kJ/mol and K'eq = 1.39×10⁻³. However, in glycolysis the reaction is coupled to ATP hydrolysis: fructose-6-phosphate + ATP ⇌ fructose-1,6-phosphate + ADP and the reaction if favorable. What is the equilibrium [fructose-1,6-bisphosphate]/[fructose-6-phosphate] ratio in the coupled reaction when [ATP] = [ADP]? For ATP hydrolysis ∆G'°= -30.5 kJ/mol at 25°C.
TPP is a coenzyme for transketolase, the enzyme that catalyzes the conversion of a ketopentose (xylulose5-phosphate) and an aldopentose (ribose-5-phosphate) to an aldotriose (glyceraldehyde-3-phosphate) and a ketoheptose (sedoheptulose-7-phosphate). Notice that the total number of carbons in the reactants and products is the same (5 + 5 = 3 + 7). Propose a mechanism for this reaction.
In one of the steps in this pathway fructose 1,6-biphosphate (F1,6BP) is converted to gylceraldehyde-3-phosphate (G-3-p) and dihydroxyacetone phosphate (DHAP). This reaction is catalyzed by the enzyme aldolase.  For this reaction at 25 celcuius and Ph7 we have:  Keq= 10-4M and Delta G = +5456 cal/mol  Calculate the following:  The concentration of F1, 6BP, DHAP and G-3-P at equilibrium when the initial F1,6BP is (A) 1M, (b) 10-2 M, (c) 2 X 10*4 M and (d) 10-5 M.    I been trying to solve this problem but I dont even know where to begin with. Atleast help me with problem A, I would be able to guide myself through.

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