Concept explainers
(a)
The equivalent capacitance of the capacitors for the given system.
(a)
Answer to Problem 26P
The equivalent capacitance of the capacitors for the given system is
Explanation of Solution
Write the expression for equivalent capacitance for capacitor of
Here,
Write the expression for equivalent capacitance for capacitor of
Here,
Conclusion:
Substitute
Substitute
Therefore, the equivalent capacitance of the capacitors for the given system is
(b)
The charge on each capacitor.
(b)
Answer to Problem 26P
The charge stored in
Explanation of Solution
The charge remains the same in series connection.
Write the expression for charge stored in
Here,
The charge divides in parallel connection but the potential difference remains the same.
Write the expression to calculate the potential difference across
Here,
Write the expression to calculate the charge stored in the capacitor
Here, the charge stored in capacitor
Write the expression to calculate the charge stored in the capacitor
Here, the charge stored in capacitor
Conclusion:
Substitute
Substitute
Substitute
Substitute
Therefore, the charge stored in
(c)
The potential difference across each capacitor.
(c)
Answer to Problem 26P
The potential difference across each capacitor is
Explanation of Solution
The potential difference remains same in parallel connection.
So, the potential difference across
The capacitors
Write the expression to calculate the potential difference across
Here,
Conclusion:
Substitute
Therefore, the potential difference across each capacitor is
Want to see more full solutions like this?
Chapter 26 Solutions
Physics: for Science.. With Modern. -Update (Looseleaf)
- An arrangement of capacitors is shown in Figure P27.23. a. If C = 9.70 105 F, what is the equivalent capacitance between points a and b? b. A battery with a potential difference of 12.00 V is connected to a capacitor with the equivalent capacitance. What is the energy stored by this capacitor? Figure P27.23 Problems 23 and 24.arrow_forwardFind (a) the equivalent capacitance of the capacitors in Figure P26.26, (b) the charge on each capacitor, and (c) the potential difference across each capacitor.arrow_forwardFigure P27.75 shows four capacitors with CA = 4.00 F, CB = 8.00 F. CC = 6.00 F. and CD = 5.00 F connected across points a and b, which have potential difference Vab = 12.0 V. a. What is the equivalent capacitance of the four capacitors? b. What is the charge on each of the four capacitors?arrow_forward
- Given the arrangement of capacitors in Figure P27.23, find an expression for the equivalent capacitance between points a and b. Figure P27.23 Problems 23 and 24.arrow_forwardFind the equivalent capacitance between points a and b in the combination of capacitors shown in Figure P20.51. Figure P20.51arrow_forwardIn Figure P27.7, capacitor 1 (C1 = 20.0 F) initially has a potential difference of 50.0 V and capacitor 2 (C2 = 5.00 F) has none. The switches are then closed simultaneously. a. Find the final charge on each capacitor after a long time has passed. b. Calculate the percentage of the initial stored energy that was lost when the switches were closed. FIGURE P27.7arrow_forward
- Find the charge on each of the capacitors in Figure P16.43. Figure P16.43arrow_forwardThree capacitors are connected to a battery as shown in Figure P20.50. Their capacitances are C1 = 3C, C2 = C, and C3 = 5C. (a) What is the equivalent capacitance of this set of capacitors? (b) State the ranking of the capacitors according to the charge they store from largest to smallest. (c) Rank the capacitors according to the potential differences across them from largest to smallest. (d) What If? Assume C3 is increased. Explain what happens to the charge stored by each capacitor. Figure P20.50arrow_forwardFind the charge on each of the capacitors in Figure P16.43. Figure P16.43arrow_forward
- A pair of capacitors with capacitances CA = 3.70 F and CB = 6.40 F are connected in a network. What is the equivalent capacitance of the pair of capacitors if they are connected a. in parallel and b. in series?arrow_forwardFour capacitors are connected as shown in Figure P20.45. (a) Find the equivalent capacitance between points a and b. (b) Calculate the charge on each capacitor, taking Vab = 15.0 V. Figure P20.45arrow_forwardFour capacitors are connected as shown in Figure P25.11. (a) Find the equivalent capacitance between points a and b. (b) Calculate the charge on each capacitor, taking Vab = 15.0 V. Figure P25.11arrow_forward
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning