   Chapter 27, Problem 84PE

Chapter
Section
Textbook Problem

What angle is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity in half?

To determine

The angle between the direction of polarized light and the axis of polarizing filter

Explanation

Given info:

Intensity of transmitted wave is half of the incident wave

Formula used:

The intensity of the transmitted wave is related to the incident wave by

I=Iocos2θ

Here,

I is the intensity of transmitted light

Io is the intensity of incident wave

θ is the angle between the direction of polarized light and the axis of polarizing filter

Calculation:

Let the intensity of the incident wave is Io , then according to the question the intensity of the transmitted wave is Io/2

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