College Physics (10th Edition)
10th Edition
ISBN: 9780321902788
Author: Hugh D. Young, Philip W. Adams, Raymond Joseph Chastain
Publisher: PEARSON
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Chapter 28, Problem 12CQ
To determine
Which has more energy hydrogen atom with electron in high or low shell, and which moves faster.
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So Determine the distance between the electron and proton in an atom if the potential energy ?U of the electron is 15.4 eV (electronvolt, 1 eV =1.6×10−19=1.6×10−19 J). Give your answer in Angstrom (1 A = 10-10 m)
Can the electron in the ground state of hydrogen absorb a photon of energy less than 13.6 eV? Can it absorb a photon of energy greater than 13.6 eV? Explain.
I am struggling with getting this question done and need some help solving it, explain and make sure the answer is 100% correct.
When a fast electron (i.e., one moving at a relativistic speed) passes by a heavy atom, it interacts with the atom's electric field. As a result, the electron's kinetic energy is reduced; the electron slows down. In the meantime, a photon of light is emitted. The kinetic energy lost by the electron equals the energy E� of a photon of radiated light:
Eγ=K−K′��=�−�′,
where K� and K′�′ are the kinetic energies of the electron before and after radiation, respectively.
This kind of radiation is called bremsstrahlung radiation, which in German means "braking radiation" or "deceleration radiation." The highest energy of a radiated photon corresponds to the moment when the electron is completely stopped.
Part A.
Given an electron beam whose electrons have kinetic energy of 4.00 keVkeV , what is the minimum wavelength λmin�min of light radiated by such beam…
Chapter 28 Solutions
College Physics (10th Edition)
Ch. 28 - Prob. 1CQCh. 28 - Prob. 2CQCh. 28 - Prob. 3CQCh. 28 - Prob. 4CQCh. 28 - Prob. 5CQCh. 28 - Prob. 6CQCh. 28 - Prob. 7CQCh. 28 - Prob. 8CQCh. 28 - Prob. 9CQCh. 28 - Prob. 10CQ
Ch. 28 - Prob. 11CQCh. 28 - Prob. 12CQCh. 28 - Prob. 1MCPCh. 28 - Prob. 2MCPCh. 28 - Prob. 3MCPCh. 28 - Prob. 4MCPCh. 28 - Prob. 5MCPCh. 28 - Prob. 6MCPCh. 28 - Prob. 7MCPCh. 28 - Prob. 8MCPCh. 28 - Prob. 9MCPCh. 28 - Prob. 10MCPCh. 28 - Prob. 11MCPCh. 28 - Prob. 12MCPCh. 28 - Prob. 1PCh. 28 - Prob. 2PCh. 28 - Prob. 3PCh. 28 - Prob. 4PCh. 28 - Prob. 5PCh. 28 - Prob. 6PCh. 28 - Prob. 7PCh. 28 - Prob. 8PCh. 28 - Prob. 9PCh. 28 - Prob. 10PCh. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Prob. 13PCh. 28 - Prob. 14PCh. 28 - Prob. 15PCh. 28 - Prob. 16PCh. 28 - Prob. 17PCh. 28 - Prob. 18PCh. 28 - Prob. 19PCh. 28 - Prob. 20PCh. 28 - Prob. 21PCh. 28 - Prob. 22PCh. 28 - Prob. 23PCh. 28 - Prob. 24PCh. 28 - Prob. 25PCh. 28 - Prob. 26PCh. 28 - Prob. 27PCh. 28 - Prob. 28PCh. 28 - Prob. 29PCh. 28 - Prob. 30PCh. 28 - Prob. 31PCh. 28 - Prob. 32PCh. 28 - Prob. 33PCh. 28 - Prob. 34PCh. 28 - Prob. 35PCh. 28 - Prob. 36PCh. 28 - Prob. 37PCh. 28 - Prob. 38PCh. 28 - Prob. 39PCh. 28 - Prob. 40PCh. 28 - Prob. 41PCh. 28 - Prob. 42PCh. 28 - Prob. 43PCh. 28 - Prob. 44PCh. 28 - Prob. 45PCh. 28 - Prob. 46PCh. 28 - Prob. 47PCh. 28 - Prob. 48PCh. 28 - Prob. 49PCh. 28 - Prob. 50GPCh. 28 - Prob. 51GPCh. 28 - Prob. 52GPCh. 28 - Prob. 53GPCh. 28 - Prob. 54GPCh. 28 - Prob. 55GPCh. 28 - Prob. 56GPCh. 28 - Prob. 57GPCh. 28 - Prob. 58GPCh. 28 - Prob. 59GPCh. 28 - Prob. 61GPCh. 28 - Prob. 62GPCh. 28 - Prob. 63GPCh. 28 - Prob. 64GPCh. 28 - Prob. 65GPCh. 28 - Prob. 66PPCh. 28 - Prob. 67PPCh. 28 - Prob. 68PPCh. 28 - Prob. 69PPCh. 28 - Prob. 70PPCh. 28 - Prob. 71PPCh. 28 - Prob. 72PPCh. 28 - Prob. 73PPCh. 28 - Prob. 74PP
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- (Bonus 7 pts) (a) Let's reconsider particle-in-a-box model (with 12 electrons) in question 1 by modifying a rectangular particle-in-a-box. When the height of box in Q1 is reduced to a half (see below), construct an energy-level diagram showing the relative energy ordering of the lowest 8 molecular orbitals when this cube is a xa x 0.5a. Label the levels in terms of their quantum numbers and Eo (Eo = h2/8ma²). Be alert for degeneracies. S Fe Fe 0.5a E3D 111: 6 to 211=96 121=9E. 112: 136. 221-126. h² n 5:蒜(++) h² 8m h² 8m ha Bmaz (4) (n} + (0.5a)2 n? + वर 0-2592) + n + 42) = E (n² + n²² + 4 m²) E = 120f6€ = GE 125.arrow_forwardAn electron is in the nth Bohr orbit of the hydrogen atom. n3 (a) Show that the period of the electron is T = to n³ and determine the numerical value of to. 153 as (b) On average, an electron remains in the n = 2 orbit for approximately 8 us before it jumps down to the n = 1 (ground-state)orbit. How many revolutions does the electron make in the excited state? 8.26e+09 × (c) Define the period of one revolution as an electron year, analogous to an Earth year being the period of the Earth's motion around the Sun. Explain whether we should think of the electron in the n = 2 orbit as "living for a long time."arrow_forwardIf the electron in a hydrogen atom obeyed classical mechanics instead of quantum mechanics, would it emit a continuous spectrum or a line spectrum? Explain.arrow_forward
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