COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 28, Problem 9QAP
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3- a) The distance to Alpha Centauri (the nearest large star to Earth) is 4.37 Ly (Light Years). What is the distance in miles (given that one Ly = 5.88 x 1012 miles?)
b) Present rocket ship speeds are roughly 100,000 miles per hour, which is the same as 8.766 x 108 miles per year. At this speed, and using the distance you calculated in (a), how many years would it take to travel to Alpha Centauri?
When we look out into the universe, we see into the past. John Dobson, founder of the San Francisco Sidewalk Astronomers, says that we cannot even see the backs of our own hands now—in fact, we can’t see anything now. Do you agree? Explain.
Chapter 28 Solutions
COLLEGE PHYSICS
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- If there is no observable edge to the universe, can we determine where its center of expansion is? Explain.arrow_forwardConstruct Your Own Problem Consider a supermassive black hole near the center of a galaxy. Calculate the radius of such an object based on its mass. You must consider how much mass is reasonable for these large objects, and which is now nearly directly observed. (Information on black holes posted on the Web by NASA and other agencies is reliable, for example.)arrow_forwardIf a galaxy is 153 Mpc away flora us, how fast do we expect it to be moving and in what direction?arrow_forward
- Why couldn’t atomic nuclei exist when the e of the Universe was less than 2 minutes?arrow_forwardIf some unknown cause of red shiftsuch as light becoming "?red" from traveling long distances through empty spaceis discovered, what effect would there be on cosmology?arrow_forwardShow that the velocity of a star orbiting its galaxy in a circular oibit is inversely proportional to the square root of its orbital radius, assuming the mass of the stars inside its orbit acts like a single mass at the center of the galaxy. You may use an equation from a previous chapter to support your conclusion, but you must justify its use and define all terms used.arrow_forward
- Show that the velocity of a star orbiting its galaxy in a circular orbit is inversely proportional to the square root of its orbital radius, assuming the mass of the stars inside its orbit acts like a single mass at the center of the galaxy. You may use an equation from a previous chapter to support your conclusion, but you must justify its use and define all terms used.arrow_forwardOur solar system orbits the center of the Milky Way galaxy. Assuming a circular orbit 30,000 ly in radius and an orbital speed of 250 km/s, how many years does it take for one revolution? Note than this is approximate, assuming constant speed and circular orbit, but it is representative of the time for our system and local stars to make one revolution around the galaxy.arrow_forwardOn average, how far away are galaxies that are moving away from us at 2.0% of the speed of light?arrow_forward
- Construct Your Own Problem Consider a star moving in a circular orbit at the edge at a galaxy. Construct a problem in which you calculate the mass of that galaxy in kg and in multiples of the solar mass based on the velocity of the star and its distance from the center of the galaxy. Figure 34.26 Distances to nearby stars are measured using triangulation, also called the parallax method. The angle of line of sight to the star is measured at intervals six momma apart, and the distance is calculated by using the known diameter of the Earth's orbit. This can be done for stars up to about 500 ly away.arrow_forwardHow can Earth be located at the center of the observable Universe if you accept the cosmological principle?arrow_forwardState three experimental findings that support the Big Bang model of the universe.arrow_forward
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