Algebra 1
Algebra 1
1st Edition
ISBN: 9780078884801
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 3, Problem 10MCQ
To determine

The solution of the equation 4x−24=0 .

Expert Solution & Answer
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Answer to Problem 10MCQ

  x=6

Explanation of Solution

Given:

The equation 4x−24=0 .

Concept used:

•To get rid of a number in addition from one side, subtract the same number from both sides of equal sign

•To get rid of a number in subtraction from one side , add the same number both sides of equal sign.

•To get rid of a number in multiplication from one side, divide the same number from both side of a equal sign.

•To get rid of a number in division from one side, multiply the same number both sides of equal sign.

Rules of Addition and /Subtraction:

• two numbers with similar sign always get added and the resulting will carry the similar sign.

• two number with opposite sign always get subtractedand the resulting will carry the sign of larger number.

Rules of Multiplication/Division:

• the product/quotient of two similar sign numbers is always positive.

• the product/quotient of two numbers with sign is always negative.

Calculation:

In order to solve the given equation 4x−24=0 , for the unknown variable , isolate the variable term x on one side by performing some basic algebraic operations to get rid of the other numbers and term associated with it.

Here to isolate x on left side first add 24 on both side of the equation and after that divide by 4 on both side of the equation and then simplify further as shown below,

  4x−24=04x−24+24=244x4=244x=6

Thus, the solution of the given equation is x=6 .

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Chapter 3, Problem 9MCQ
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Chapter 3, Problem 11MCQ

Chapter 3 Solutions

Algebra 1

Ch. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 58PPSCh. 3.1 - Prob. 60HPCh. 3.1 - Prob. 68STPCh. 3.1 - Prob. 1ACYPCh. 3.1 - Prob. 1BCYPCh. 3.1 - Prob. 2CYPCh. 3.1 - Prob. 3CYPCh. 3.1 - Prob. 4ACYPCh. 3.1 - Prob. 4BCYP
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Prob. 15HPCh. 3.6 - Prob. 16HPCh. 3.6 - Prob. 17HPCh. 3.6 - Prob. 18HPCh. 3.6 - Prob. 1ACYPCh. 3.6 - Prob. 1BCYPCh. 3.6 - Prob. 1CCYPCh. 3.6 - Prob. 2ACYPCh. 3.6 - Prob. 2BCYPCh. 3.6 - Prob. 19STPCh. 3.6 - Prob. 20STPCh. 3.6 - Prob. 21STPCh. 3.6 - Prob. 22STPCh. 3.6 - Prob. 23SRCh. 3.6 - Prob. 24SRCh. 3.6 - Prob. 25SRCh. 3.6 - Prob. 26SRCh. 3.6 - Prob. 27SRCh. 3.6 - Prob. 28SRCh. 3.6 - Prob. 29SRCh. 3.6 - Prob. 30SCh. 3.6 - Prob. 31SCh. 3.6 - Prob. 32SCh. 3.6 - Prob. 33SCh. 3.6 - Prob. 34SCh. 3.6 - Prob. 35SCh. 3 - Prob. 1QCCh. 3 - Prob. 2QCCh. 3 - Prob. 3QCCh. 3 - Prob. 4QCCh. 3 - Prob. 5QCCh. 3 - Prob. 6QCCh. 3 - Prob. 13QCCh. 3 - Prob. 14QCCh. 3 - Prob. 15QCCh. 3 - Prob. 16QCCh. 3 - Prob. 17QCCh. 3 - Prob. 18QCCh. 3 - Prob. 19QCCh. 3 - Prob. 20QCCh. 3 - Prob. 21QCCh. 3 - Prob. 22QCCh. 3 - Prob. 23QCCh. 3 - Prob. 1MCQCh. 3 - Prob. 2MCQCh. 3 - Prob. 3MCQCh. 3 - Prob. 4MCQCh. 3 - Prob. 5MCQCh. 3 - Prob. 6MCQCh. 3 - Prob. 9MCQCh. 3 - Prob. 10MCQCh. 3 - Prob. 11MCQCh. 3 - Prob. 12MCQCh. 3 - 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