Algebra 1
Algebra 1
1st Edition
ISBN: 9780078884801
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Question
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Chapter 3.4, Problem 9CYU

(a)

To determine

Write a direct variation equation relating your post to message receives. Then graph the equation.

(a)

Expert Solution
Check Mark

Answer to Problem 9CYU

The equation y=125x

Explanation of Solution

Given:

Number of messages post = 5 and number of messages receives = 12

Concept Used:

Let the number of message post is x and number of message receive is y

Y is directly varies with x.

We can write direct variation equation that relates x and y is y=kx

k is the constant of variation.

Calculation:

Direct variation equation that relates x and y is y=kx

Given:

Number of messages post = 5 and number of messages receives = 12

  Whenx=5,theny=12

  yxy=kxk=constantofvariation12=k·5125=5k5[Divideeachsideby5]k=125y=125x

The equation that relates the number of message receive to the post is y=125x

The slope of the equation y=125x is 125 .Write the slope as

    Write the slope as

      riserun=125

    Graph (0,0).

    From there move up 12 units and right 5 units to find another point.

    Then draw a line containing the points.

    Algebra 1, Chapter 3.4, Problem 9CYU

Thus, the equation y=125x

(b)

To determine

Find the number of messages you need to post to receive 96 messages.

(b)

Expert Solution
Check Mark

Answer to Problem 9CYU

You need to post 40 messages to receive 96 messages.

Explanation of Solution

Given: The equation y=125x

Concept Used:

To find the number of messages you need to post to receive 96 messages, we need to plug in y = 96 and solve for x.

Calculation:

  y=125xTheoriginalequation96=125xy=96512·96=512·125x[Multiplybothsidesby512]40=xx=40

So, you need to post 40 messages to receive 96 messages.

Thus, you need to post 40 messages to receive 96 messages.

Chapter 3 Solutions

Algebra 1

Ch. 3.1 - Prob. 5ACYPCh. 3.1 - Prob. 5BCYPCh. 3.1 - Prob. 5CCYPCh. 3.1 - Prob. 1CYUCh. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42PPSCh. 3.1 - Prob. 43PPSCh. 3.1 - Prob. 44PPSCh. 3.1 - Prob. 45PPSCh. 3.1 - Prob. 46PPSCh. 3.1 - 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Prob. 15HPCh. 3.6 - Prob. 16HPCh. 3.6 - Prob. 17HPCh. 3.6 - Prob. 18HPCh. 3.6 - Prob. 1ACYPCh. 3.6 - Prob. 1BCYPCh. 3.6 - Prob. 1CCYPCh. 3.6 - Prob. 2ACYPCh. 3.6 - Prob. 2BCYPCh. 3.6 - Prob. 19STPCh. 3.6 - Prob. 20STPCh. 3.6 - Prob. 21STPCh. 3.6 - Prob. 22STPCh. 3.6 - Prob. 23SRCh. 3.6 - Prob. 24SRCh. 3.6 - Prob. 25SRCh. 3.6 - Prob. 26SRCh. 3.6 - Prob. 27SRCh. 3.6 - Prob. 28SRCh. 3.6 - Prob. 29SRCh. 3.6 - Prob. 30SCh. 3.6 - Prob. 31SCh. 3.6 - Prob. 32SCh. 3.6 - Prob. 33SCh. 3.6 - Prob. 34SCh. 3.6 - Prob. 35SCh. 3 - Prob. 1QCCh. 3 - Prob. 2QCCh. 3 - Prob. 3QCCh. 3 - Prob. 4QCCh. 3 - Prob. 5QCCh. 3 - Prob. 6QCCh. 3 - Prob. 13QCCh. 3 - Prob. 14QCCh. 3 - Prob. 15QCCh. 3 - Prob. 16QCCh. 3 - Prob. 17QCCh. 3 - Prob. 18QCCh. 3 - Prob. 19QCCh. 3 - Prob. 20QCCh. 3 - Prob. 21QCCh. 3 - Prob. 22QCCh. 3 - Prob. 23QCCh. 3 - Prob. 1MCQCh. 3 - Prob. 2MCQCh. 3 - Prob. 3MCQCh. 3 - Prob. 4MCQCh. 3 - Prob. 5MCQCh. 3 - Prob. 6MCQCh. 3 - Prob. 9MCQCh. 3 - Prob. 10MCQCh. 3 - Prob. 11MCQCh. 3 - Prob. 12MCQCh. 3 - 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