Concept explainers
Graph each equation by making a table.
Answer to Problem 29PPS
The line
Explanation of Solution
Given:
The equation:
Concept Used:
The equation of line parallel to y-axis:
Let AB be a straight line parallel to y-axis at a distance
Thus, AB can be considered as the locus of a point at a distance
Thus, if P(x, y) is any point on AB, then |
Hence, the equation of a straight line parallel to y-axis at a distance a from it is
To graph the equation make y as subject and make a table by choosing random value of y and find the corresponding value of x.
Calculation:
Step 1: in this equation
Take random value of y and find the value of corresponding x
Make a table:
y | (x, y) | |
– 4 | ||
0 | ||
4 |
The points are:
Graph of the equation:
Thus, the points on the graph are:
Chapter 3 Solutions
Algebra 1
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