(a)
To explain:- The reasons for different properties shared between cellulose and starch made up of the same repeating subunits.
Introduction: Starch and cellulose are
(b)
To explain: The advantages of α and β linkages in starch and cellulose respectively.
Introduction: Starch and cellulose are polymers of made up of repeating subunits of D-glucose. Cellulose is made up of β 1-4 linkage present in the repeating subunits of D-glucose while starch is made up of α 1-4 linkage present in the repeating subunits of D glucose.
Want to see the full answer?
Check out a sample textbook solutionChapter 3 Solutions
Becker's World of the Cell (9th Edition)
- Reposting - What would the tertiary structure of the dipeptide Asp-Ser be if it was made into a polypeptide chain? (Would it form a beta pleated sheet, an alpha helix, etc) Why would it do this? What properties of this polypeptide causes this? This sub part still needs to be solved - What would the tertiary structure of Pro-ala and Glycl-L-alanine be?arrow_forwardBIOMOLECULES - MULTIPLE CHOICE - Please answer properly QUESTION : In human beings, what is the major control of de novo pyrimidine nucleotide synthesis? A. substrate availability B. competitive inhibition of carbamoyl phosphate synthetase II C. feedback inhibition of glutamine-PRPP amidotransferase D. vailability of N-acetyl glutamatearrow_forwardExponential expansion? Compare the amount of information inherent in the genome, the proteome, and the glycome.arrow_forward
- α -Amylose is an unbranched glucose polymer. Why would this polymer not be as effective a storage form of glucose as glycogen?arrow_forwardTru or false 1. Every time our sugar level drops, glycogen is broken down to provide glucose in a process called syneresis. 2. If plants store glucose in the form of starch, animals store glucose in the form of glycogen. 3. Maltose is the most abundant biopolymer and is the basic component of cell wall of plants. 4. A long chain of monosaccharides linked by glycosidic bonds is known as a monosaccharide. 5. People who suffer from lactose intolerance do not produce lactase necessary to break down glucose and galactose.arrow_forwardATP yield. Each of the following molecules is processed by glycolysis to lactate. How much ATP is generated from each molecule?arrow_forward
- Briefly explain why chicken fat, which largely consists of various triacylglycerols, has such a higher energy content per mole compared to sucrose.arrow_forwardBIOMOLECULES - Please answer the questions properly. - Multiple choice 1. In human beings, what is the major control of de novo pyrimidine nucleotide synthesis? A. substrate availability B. feedback inhibition of glutamine-PRPP amidotransferase C. competitive inhibition of carbamoyl phosphate synthetase II D. availability of N-acetyl glutamate 2. In patients with Lesch Nyhan Syndrome, purine nucleotides are overproduced and over excreted. The hypoxanthine analogue Allopurinol, which effectively treats gout , has no effect on the severe neurological symptoms of Lesch- Nyhan patients because it does not? A. decrease de novo pyrimidine synthesis B. increase PRPP levels (Phosphoribosyl pyrophosphate) C. Decrease urate synthesis D. decrease de novo purine synthesisarrow_forwardGlycerophospholipids Phosphatidylethanolamine 3. In case the cell is in a state requiring large amount of ATP to support energy-requiring reactions/pathways, assuming that you have 1 mole of each of the said lipids are catabolized and complete oxidized, will the total net ATP yield from these two lipids be higher or lower than the sum of the net ATPs generated from each fatty acid components? Justify your answer in biochemical terms and using 5 sentences or less.arrow_forward
- BIOMOLECULES - MULTIPLE CHOICE - Please answer properly QUESTION : In patients with Lesch Nyhan Syndrome, purine nucleotides are overproduced and over excreted. The hypoxanthine analogue Allopurinol, which effectively treats gout , has no effect on the severe neurological symptoms of Lesch- Nyhan patients because it does not? A. decrease de novo pyrimidine synthesis B. decrease de novo purine synthesis C. decrease urate synthesis D. increase PRPP levels (Phosphoribosyl pyrophosphate)arrow_forwardIn α-helices - what is the length of the hydrogen bonds between: TYR41H and GLU37O ALA39H and MET35O GLU38H and ILE34O THR36H and ARG32O. ARG32H and TYR28Oarrow_forwardAssignment on KetohexosesConstruct the structure of the following enantiomers or mirror images:1. D and L Fructose2. D and L Allulose3. D and L Sorbose4. D and L Tagatosearrow_forward
- BiochemistryBiochemistryISBN:9781305577206Author:Reginald H. Garrett, Charles M. GrishamPublisher:Cengage Learning