Sales and Advertising Suppose that a kitchen appliance company’s monthly sales and advertising expenses are approximately related by the equation x y − 6 x + 20 y = 0 , where x is thousands of dollars spent on advertising and y is thousands of dishwashers sold. Currently, the company is spending 10 thousand dollars on advertising and is selling 2 thousand dishwashers each month. If the company plans to increase monthly advertising expenditure at the rate of $ 1.5 thousands per month, how fast will sales rise? Use implicit differentiation to answer the question.
Sales and Advertising Suppose that a kitchen appliance company’s monthly sales and advertising expenses are approximately related by the equation x y − 6 x + 20 y = 0 , where x is thousands of dollars spent on advertising and y is thousands of dishwashers sold. Currently, the company is spending 10 thousand dollars on advertising and is selling 2 thousand dishwashers each month. If the company plans to increase monthly advertising expenditure at the rate of $ 1.5 thousands per month, how fast will sales rise? Use implicit differentiation to answer the question.
Solution Summary: The author explains how a kitchen appliance company's monthly sales and advertising expenses are approximately related by the equation xy-6x+20y=0.
Sales and Advertising Suppose that a kitchen appliance company’s monthly sales and advertising expenses are approximately related by the equation
x
y
−
6
x
+
20
y
=
0
, where
x
is thousands of dollars spent on advertising and
y
is thousands of dishwashers sold. Currently, the company is spending
10
thousand dollars on advertising and is selling
2
thousand dishwashers each month. If the company plans to increase monthly advertising expenditure at the rate of
$
1.5
thousands per month, how fast will sales rise? Use implicit differentiation to answer the question.
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