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Balance the following equations, and name each reactant and product: (a) Fe 2 O 3 (s) + Mg(s) → MgO(s) + Fe(s) (b) AlC1 3 (s) + NaOH(aq) → Al(OH) 3 (s) + NaCl(aq) (c) NaNO 3 (s) + H 2 SO 4 (aq) →Na 2 SO 4 (S) HNO 3 (aq) (d) NiCO 3 (s) + HNO 3 (aq) → Ni(NO 3 ) 2 (aq) + CO 2 (g) + H 2 O( ℓ )

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Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

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Chapter
Section
BuyFindarrow_forward

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 3, Problem 5PS
Textbook Problem
15 views

Balance the following equations, and name each reactant and product:

(a) Fe2O3(s) + Mg(s) → MgO(s) + Fe(s)

(b) AlC13(s) + NaOH(aq) → Al(OH)3(s) + NaCl(aq)

(c) NaNO3(s) + H2SO4(aq) →Na2SO4(S) HNO3(aq)

(d) NiCO3(s) + HNO3(aq) → Ni(NO3)2(aq) + CO2(g) + H2O()

(a)

Interpretation Introduction

Interpretation:

The balanced equation and name of the reactant and product should be given.

Concept introduction:

The law of conservation of mass states that no atoms can be created or destroyed in a chemical reaction, therefore, the number of atoms present in the reactants is equal to the number of atoms present in the products.

Explanation of Solution

Iron (III) oxide reacts with magnesium which yields the magnesium oxide and iron, the unbalanced equation is given below using correct molecular formula,

  

Balance the iron atom in the given equation, when balancing the equation, we should not alter the subscripts and we can change coefficients.  There is two iron atom in the left side and one iron in the right side.  Two molecule of iron atom is added to the right side of the reaction.  Therefore according to the iron atom the balanced equation is given below.

  

Next, balance the oxygen atom in the equation, there are three oxygen atom in the left side.  For the balancing the oxygen atom, three molecules of magnesium oxide is added to the left side of the reaction.  Therefore the balanced equation is given below

  

(b)

Interpretation Introduction

Interpretation:

The balanced equation and name of the reactant and product should be given.

Concept introduction:

The law of conservation of mass states that no atoms can be created or destroyed in a chemical reaction, therefore, the number of atoms present in the reactants is equal to the number of atoms present in the products.

(c)

Interpretation Introduction

Interpretation:

The balanced equation and name of the reactant and product should be given.

Concept introduction:

The law of conservation of mass states that no atoms can be created or destroyed in a chemical reaction, therefore, the number of atoms present in the reactants is equal to the number of atoms present in the products.

(d)

Interpretation Introduction

Interpretation:

The balanced equation and name of the reactant and product should be given.

Concept introduction:

The law of conservation of mass states that no atoms can be created or destroyed in a chemical reaction, therefore, the number of atoms present in the reactants is equal to the number of atoms present in the products.

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Chapter 3 Solutions

Chemistry & Chemical Reactivity
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Ch. 3.5 - In each of the following cases, aqueous solutions...Ch. 3.5 - Aqueous solutions of the two reactants listed...Ch. 3.5 - What is the net ionic equation for the reaction of...Ch. 3.6 - (a) Write a balanced equation for the reaction...Ch. 3.6 - Write the balanced, overall equation and the net...Ch. 3.6 - Which of the following is a strong add in aqueous...Ch. 3.6 - 2. The hydrogen phosphate ion is amphiprotic....Ch. 3.6 - What is the net ionic equation for the reaction of...Ch. 3.6 - Identify the basic oxide from those listed below....Ch. 3.7 - Barium carbonate, BaC0)3, is used in the brick,...Ch. 3.7 - Which of the following compounds, when treated...Ch. 3.8 - Assign an oxidation number to the underlined atom...Ch. 3.8 - The following reaction is used in a device for...Ch. 3.8 - 1. What is the oxidation number of Mn in...Ch. 3.8 - 2. Which of the following reactions are...Ch. 3.8 - 3. 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