Physics (5th Edition)
5th Edition
ISBN: 9780321976444
Author: James S. Walker
Publisher: PEARSON
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Question
Chapter 31, Problem 78GP
To determine
The approximate wavelength of
K β
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The x-ray spectrum is for 35.0 keV electrons striking a molybdenum (Z= 42) target. If you substitute a silver (Z = 47) target for the molybdenum target, will (a) lmin, (b) the wavelength for the Ka line, and (c) the wavelength for the Kb line increase, decrease, or remain unchanged?
What would the wavelength in m of the emitted radiation be if a hydrogen atom was placed in an external uniform magnetic field of 240 T and transitioned from a spin-up to a spin-down state?
The electron, in a hydrogen atom, is in its second excited state.
Calculate the wavelength of the lines in the Lyman series, that can be emitted through the permissible transitions of this electron.
(Given the value of Rydberg constant, R = 1.1 × 107 m-1 )
Chapter 31 Solutions
Physics (5th Edition)
Ch. 31.1 - Prob. 1EYUCh. 31.2 - Prob. 2EYUCh. 31.3 - Prob. 3EYUCh. 31.4 - Prob. 4EYUCh. 31.5 - Prob. 5EYUCh. 31.6 - Prob. 6EYUCh. 31.7 - Prob. 7EYUCh. 31 - Prob. 1CQCh. 31 - Prob. 2CQCh. 31 - Prob. 3CQ
Ch. 31 - Prob. 4CQCh. 31 - Prob. 5CQCh. 31 - Prob. 6CQCh. 31 - Prob. 7CQCh. 31 - Prob. 8CQCh. 31 - Prob. 9CQCh. 31 - Prob. 1PCECh. 31 - Prob. 2PCECh. 31 - Prob. 3PCECh. 31 - Prob. 4PCECh. 31 - Prob. 5PCECh. 31 - Prob. 6PCECh. 31 - Prob. 7PCECh. 31 - Prob. 8PCECh. 31 - Prob. 9PCECh. 31 - Prob. 10PCECh. 31 - Prob. 11PCECh. 31 - Prob. 12PCECh. 31 - Prob. 13PCECh. 31 - Prob. 14PCECh. 31 - Prob. 15PCECh. 31 - Prob. 16PCECh. 31 - Prob. 17PCECh. 31 - Prob. 18PCECh. 31 - Prob. 19PCECh. 31 - Prob. 20PCECh. 31 - Prob. 21PCECh. 31 - Prob. 22PCECh. 31 - Prob. 23PCECh. 31 - Prob. 24PCECh. 31 - Prob. 25PCECh. 31 - Prob. 26PCECh. 31 - Prob. 27PCECh. 31 - Prob. 28PCECh. 31 - Prob. 29PCECh. 31 - Prob. 30PCECh. 31 - Prob. 31PCECh. 31 - Prob. 32PCECh. 31 - Prob. 33PCECh. 31 - Prob. 34PCECh. 31 - Prob. 35PCECh. 31 - Prob. 36PCECh. 31 - Prob. 37PCECh. 31 - Prob. 38PCECh. 31 - Prob. 39PCECh. 31 - Prob. 40PCECh. 31 - Prob. 41PCECh. 31 - Prob. 42PCECh. 31 - Prob. 43PCECh. 31 - Prob. 44PCECh. 31 - Prob. 45PCECh. 31 - Prob. 46PCECh. 31 - Prob. 47PCECh. 31 - Prob. 48PCECh. 31 - Prob. 49PCECh. 31 - Prob. 50PCECh. 31 - Prob. 51PCECh. 31 - Prob. 52PCECh. 31 - Give the electronic configuration for the ground...Ch. 31 - Prob. 54PCECh. 31 - Prob. 55PCECh. 31 - Prob. 56PCECh. 31 - The configuration of the outer electrons in Ni is...Ch. 31 - Prob. 58PCECh. 31 - Prob. 59PCECh. 31 - Prob. 60PCECh. 31 - Prob. 61PCECh. 31 - Prob. 62PCECh. 31 - Prob. 63PCECh. 31 - Prob. 64PCECh. 31 - Prob. 65PCECh. 31 - Prob. 66PCECh. 31 - Prob. 67PCECh. 31 - Prob. 68GPCh. 31 - Prob. 69GPCh. 31 - Prob. 70GPCh. 31 - Prob. 71GPCh. 31 - Prob. 72GPCh. 31 - Prob. 73GPCh. 31 - Prob. 74GPCh. 31 - Prob. 75GPCh. 31 - Prob. 76GPCh. 31 - Prob. 77GPCh. 31 - Prob. 78GPCh. 31 - Prob. 79GPCh. 31 - Prob. 80GPCh. 31 - Prob. 81GPCh. 31 - Prob. 82GPCh. 31 - Prob. 83GPCh. 31 - Prob. 84PPCh. 31 - Prob. 85PPCh. 31 - Prob. 86PPCh. 31 - Prob. 87PPCh. 31 - Prob. 88PPCh. 31 - Prob. 89PP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Can a hydrogen atom absorb a photon whose energy is greater than 13.6 eV?arrow_forwardExplain how a hydrogen atom in the ground state (l = 0) can interact magnetically with an external magnetic field.arrow_forwardWhat is the probability of finding a hydrogen electron (n=2, l=1, ml =-1) within three bohr radii of the nucleus?arrow_forward
- Estimate the energy of the characteristic x-ray emitted from a tungsten target when an electron drops from an M shell (n = 3 state) to a vacancy in the K shell (n = 1 state). The atomic number for tungsten is Z = 74.arrow_forwardConsider the electron of a Li2+ ion that undergoes a transition from a higher energy state n to its adjacent lower energy state n – 1 (e.g. n = 2→1, 3→2, 4→3, etc) and emits a photon. Suppose the emitted photon is used to strike the surface of potassium, which has a threshold frequency of 5.464 × 10^14 s–1.a) Whatisthemaximuminitialquantumnumber,n, that is required in order to emit a photon with high enough energy to generate a photocurrent from the metal surface?b) Usingthenvaluesolvedinpart(a), calculate the maximum speed of the photoelectron from potassium. If you couldn’t solve for n in part (a), use n = 3.arrow_forwardFor a tungsten target, the electron binding energies for K- shell is 69.5 keV and that of the L-subshells are 12.1 keV, 11.5 keV, and 10.2 keV. Calculate the energy of the characteristic Kα X-rays that would be produced due to all possible electron transitions between the K-shell and L-subshells.arrow_forward
- Consider only the Lyman, Balmer and Paschen series for the energy diagram provided for an unknown element. If the visible spectrum Lies between 370 nm to 750 nm, determine the number of different energies that would be observed from the unknown element which ally in the infra rated spectrum. Provide full solutionarrow_forwardWhat is the wavelength (in nm) of the least energetic spectralline in the infrared series of the H atom?arrow_forwardWhy does the energy of characteristic x rays become increasingly greater for heavier atoms?arrow_forward
- A new atom is discovered. If it has a visible emission for the transition n = 5 to n = 3, according to the Bohr Model, would n = 5 to n =1 be infrared or ultraviolet? Why?arrow_forwardFor a hydrogen atom, the transition to a state of excitation energy (10.19 eV) emits a photon of wavelength 4890 A. Estimate the binding energy of the initial state.arrow_forwardThe energy difference between the two levels arising from the spin-orbit coupling in a d-orbital is 0.6463 eV. Consider the splitting for one electron. Calculate the spin-orbit coupling constant in cm-1. please show all calculations. What atom could that be? (Hint: calculate the spin-orbit coupling constant in Ry and look for a matching number in the last column that provides experimental values) constant : 1 eV = 1.60217646 × 10-19 J 1Ry = 2.1798741 × 10-18 Jarrow_forward
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