Explanation The intensity of the light is, I = 1 ( f D ) 2 = D 2 f 2 I ∝ D 2 (1) Here, I is the intensity of light. f is the focal length of the lens. D is the diameter of the circular lens. From the above expression, the intensity of the light is proportional to the square of the diameter of the aperture. Therefore with the increase in the diameter by factor of 3, the intensity of light increased by a factor of 9. Conclusion: The intensity of the light is directly proportion to the square of the diameter of the aperture, with the increase in the diameter by a factor of 3, the intensity of light increases by a factor of 9

Physics for Scientists and Engineers, Technology Update, Hybrid Edition (with Enhanced WebAssign Multi-Term LOE Printed Access Card for Physics)

9th Edition

ISBN: 9781305116429

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 36, Problem 36.8OQ

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The change in the intensity of light with change in the aperture diameter.

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The change in the intensity of light with change in the aperture diameter.

Solution Summary: The author explains that the intensity of light increases by a factor of 9 with the increase in the diameter of the aperture.

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