Concept explainers
(a)
The location of the image, the nature of the image and the magnification of the image when the object distance is
(a)
Answer to Problem 46P
The location of the image, the nature of the image and the magnification of the image when the object distance is
Explanation of Solution
Write the expression for mirror equation.
Here,
Write the expression for magnification.
Conclusion:
Substitute
Substitute
The object distance is negative, so the image is virtual. The magnification is positive, so the image is upright.
Therefore, the location of the image, the nature of the image and the magnification of the image when the object distance is
(b)
The location of the image, the nature of the image and the magnification of the image when the object distance is
(b)
Answer to Problem 46P
The location of the image, the nature of the image and the magnification of the image when the object distance is
Explanation of Solution
Write the expression for mirror equation.
Here,
Write the expression for magnification.
Conclusion:
Substitute
Substitute
The object distance is negative, so the image is virtual. The magnification is positive, so the image is upright.
Therefore, the location of the image, the nature of the image and the magnification of the image when the object distance is
(c)
The location of the image, the nature of the image and the magnification of the image when the object distance is
(c)
Answer to Problem 46P
The location of the image, the nature of the image and the magnification of the image when the object distance is
Explanation of Solution
Write the expression for mirror equation.
Here,
Write the expression for magnification.
Conclusion:
Substitute
Substitute
The object distance is negative, so the image is virtual. The magnification is positive, so the image is upright.
Therefore, the location of the image, the nature of the image and the magnification of the image when the object distance is
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Chapter 36 Solutions
Physics: for Science.. With Modern. -Update (Looseleaf)
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