Biology - Study Guide
8th Edition
ISBN: 9780321501561
Author: Martha R. Taylor
Publisher: PEARSON EDUCATION (COLLEGE)
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Chapter 36, Problem 6TYK
Summary Introduction
Introduction: Flaccidity is the condition of a plant cell in which its plasma membrane is not tightly pressed against its cell wall. This condition is observed when the plant is placed in an isotonic solution where the inside and outside concentration of the solutes remains constant. In this state, the plants look weak, soft, and lack vigor.
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Imagine a cell with a water potential of –0.1 MPa being placed in a beaker of solution that also has a water potential of –0.1 MPa. Are the two water potentials in equilibrium? Would any water molecules be moving between the cell and the solution? Would there be a net movement of water? Now imagine a root in moist soil, and imagine that the root cortex cells have a water potential of –0.1 MPa and that the soil solution also has a water potential of –0.1 MPa. Would there be any net movement of water into the root?
Consider a plant cell. The value for solute concentration in a plant cell is -0.12 MPa and the turgor pressure is 0.12 MPa.
1- What is the water potential in this plant cell?
2- If this plant cell were placed in a solution with water potential of -0.1 MPa, what would happen to the cell? (Hint: explain where the water goes and what that does to the cell).
Turgor pressure can be measured, in part, by determining the ____________.
A. external force of water applied to a bacterial cell's membrane
B. external force of water applied to animal cell's membrane
C. internal force of water applied to a plant cell's vesicle
D. internal force of water applied to a fungal cell's wall
Chapter 36 Solutions
Biology - Study Guide
Ch. 36 - Prob. 1IQCh. 36 - a. A flaccid plant cell has a water potential of...Ch. 36 - Prob. 3IQCh. 36 - Prob. 4IQCh. 36 - Prob. 5IQCh. 36 - Prob. 6IQCh. 36 - Prob. 1SYKCh. 36 - Prob. 2SYKCh. 36 - If a plant has a phyllotaxy of alternate leaves...Ch. 36 - Prob. 2TYK
Ch. 36 - Prob. 3TYKCh. 36 - Prob. 4TYKCh. 36 - Prob. 5TYKCh. 36 - Prob. 6TYKCh. 36 - Prob. 7TYKCh. 36 - Prob. 8TYKCh. 36 - Prob. 9TYKCh. 36 - Prob. 10TYKCh. 36 - Prob. 11TYKCh. 36 - Prob. 12TYKCh. 36 - Prob. 13TYKCh. 36 - Prob. 14TYKCh. 36 - Prob. 15TYKCh. 36 - Your favorite houseplant is wilting. Which of the...Ch. 36 - Prob. 17TYKCh. 36 - Which of the following mechanisms explains the...Ch. 36 - Prob. 19TYKCh. 36 - Prob. 20TYK
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- plant cells with an aqueous potential of -600kPa were placed in different aqueous potentials. Determine in which of the following cases after 10 minutes the cells were blocked, started plasmolysis or completely subjected to the latter. Solution A is -400kPa, solution B is - 600kPa, solution C is -900kPa and solution D is distilled waterarrow_forwardIf you place a flaccid plant cell with ΨS = -0.4 MPa in pure water, which of the following will occur? A. Water will not enter the cell because the flaccid cell has solutes and low water potential. B. Water enters the cell because the flaccid cell has solutes and low water potential. C. Water enters the cell because the flaccid cell has solutes and high water potential. D. Water will not enter the cell because the flaccid cell has solutes and high water potential.arrow_forwardYou place a flaccid plant cell (Ψ = -0.7 MPa) into an environment (beaker) of sucrose solution (Ψ = -0.9 MPa). Compare the initial conditions of the flaccid cell and the environment (beaker of sucrose solution) in terms of: A) Water potential (high or low) of the environment B) Solute concentration (high or low) of the environment C) Tonicity (hypertonic, hypotonic, or isotonic) of the environment D) Water potential (high or low) of the cell E) Solute concentration (high or low) of the cell F) Tonicity (hypertonic, hypotonic, or isotonic) of the cell G) Predict the direction of water movement (into the cell, out of the cell, or no net movement) H) Predict the change in turgor pressor of the cell (increase turgor pressure or decrease turgor pressure) I) Predict the fate of the cell (plasmolyzed, turgid, or lysed)arrow_forward
- During an experiment, a student covers all the stomata of a plant with nail polish, sealing them shut a)Predict how this would affect water transport b)How would this affect transport in the phloem?arrow_forwardIn a beaker containing 0% NaCl, you place a cell which contains 0.9% NaCl. NaCl doesn t cross the membrane. What will be the result?" a There will be net movement of water into the cell. b There will be net movement of NaCl into the cell. c There will be net movement of water out of the cell. d There will be net movement of NaCl out of the cell. e The cell will swell.arrow_forwardThe water potential of three adjacent plant cells are as follows: X 0kPa Y -1000kPa Z -4000kPa In which direction will water move?arrow_forward
- You place a flaccid plant cell (Ψ = -0.7 MPa) into an environment (beaker) of sucrose solution (Ψ = -0.9 MPa). Compare the initial conditions of the flaccid cell and the environment (beaker of sucrose solution) in terms of: D) Water potential (high or low) of the cell E) Solute concentration (high or low) of the cell F) Tonicity (hypertonic, hypotonic, or isotonic) of the cell G) Predict the direction of water movement (into the cell, out of the cell, or no net movement)arrow_forwardThe osmotic potential of the plant cell is -0.1 MPa and it is placed in an 9 mM sorbitol solution (21 °C). Calculate the turgor pressure of the cell when the water potential of the cell has equilibrated to the same as that of the solution.arrow_forwardExplain what would happen if a plant cell was placed in a hypotonic environment and why (be sure to include solute concentrations, water movement and turgor pressure in your explanation)?arrow_forward
- The following figure shows a plant cell immediately after it has been placed in distilled water (A) and a plant cell that has been in distilled water for several minutes (B). Determine whether each of the following statements is true or false based on this figure.arrow_forward1) A plant cell with a pressure potential of 5 bars and an osmotic potential of -9 bars is in equilibrium with a surrounding solution that is open to the air. What is the water potential of the surrounding solution? 2) A plant cell, when initially placed in pure water, has an osmotic potential of -4 bars and a pressure potential of +2 bars. a) Which way will water diffuse? b) When will net diffusion stop? c) When equilibrium is reached, what are the cell's osmotic potential and pressure potential values?arrow_forwardYou place a flaccid plant cell (Ψ = -0.7 MPa) into an environment (beaker) of pure (deionized) water (Ψ = 0 MPa). Compare the initial conditions of the flaccid cell and the environment (beaker of pure water) in terms of: D) Water potential (high or low) of the cell E) Solute concentration (high or low) of the cell F) Tonicity (hypertonic, hypotonic, or isotonic) of the cellarrow_forward
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