University Physics with Modern Physics (14th Edition)
University Physics with Modern Physics (14th Edition)
14th Edition
ISBN: 9780321973610
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Chapter 38, Problem 38.16DQ
To determine

The things wrong with considering the photon to be riding up and down on the crests and troughs of the electromagnetic wave.

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In attempting to reconcile the wave and particle models of light, some people have suggested that the photon rides up and down on the crests and troughs of the electromagnetic wave. What things are wrong with this description?
If you shine light on a conducting metallic surface, the light can impart energy to electrons in the conductor, potentially freeing them from the surface if the energy is higher than the so-called "work function", which is the energy required to free the electron from the surface. If you place another conducting surface in a position at which it can catch these electrons, and connect these two conductors by another conductor such as a wire, you can generate a so-called photoelectric current. Suppose the work function of a particular metal is 4.8 x 10-19 J. If light can impart an energy of 14.4 x 10-19 J to each electron, what must be the potential difference of the two conducting surfaces in order to stop a photoelectric current? Which conducting surface should be at the higher potential?
Suppose you need to image the structure of a virus with a diameter of 50 nm. For a sharp image, the wavelength of the probing wave must be 5.0 nm or less. We have seen that, for imaging such small objects, this short wavelength is obtained by using an electron beam in an electron microscope. Why don’t we simply use short-wavelength electromagnetic waves? There’s a problem with this approach: As the wavelength gets shorter, the energy of a photon of light gets greater and could damage or destroy the object being studied. Let’s compare the energy of a photon and an electron that can provide the same resolution. For the electron with a de broglie wavelength of 3.5 nm, what is the kinetic energy (in eV)?

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University Physics with Modern Physics (14th Edition)

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