University Physics with Modern Physics (14th Edition)
14th Edition
ISBN: 9780321973610
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Chapter 38, Problem 38.43PP
To determine
The loss of energy of photon.
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Compton scattering can also occur if a photon collides with a proton (mass 1.673 * 10-27 kg) at rest. If you do an experiment of this kind using gamma-ray photons with wavelength 2.50 * 10-12 m = 2.50 pm, for what scattering angle is the wavelength of the scattered gamma rays longer than the wavelength of the incident gamma rays by (a) 0.0100% and (b) 0.0800%?
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Chapter 38 Solutions
University Physics with Modern Physics (14th Edition)
Ch. 38.1 - Silicon films become better electrical conductors...Ch. 38.2 - Prob. 38.2TYUCh. 38.3 - Prob. 38.3TYUCh. 38.4 - Prob. 38.4TYUCh. 38 - Prob. 38.1DQCh. 38 - Prob. 38.2DQCh. 38 - Prob. 38.3DQCh. 38 - Prob. 38.4DQCh. 38 - Prob. 38.5DQCh. 38 - Prob. 38.6DQ
Ch. 38 - Prob. 38.7DQCh. 38 - Prob. 38.8DQCh. 38 - Prob. 38.9DQCh. 38 - Prob. 38.10DQCh. 38 - Prob. 38.11DQCh. 38 - Prob. 38.12DQCh. 38 - Prob. 38.13DQCh. 38 - Prob. 38.14DQCh. 38 - Prob. 38.15DQCh. 38 - Prob. 38.16DQCh. 38 - Prob. 38.17DQCh. 38 - Prob. 38.1ECh. 38 - Prob. 38.2ECh. 38 - Prob. 38.3ECh. 38 - Prob. 38.4ECh. 38 - Prob. 38.5ECh. 38 - Prob. 38.6ECh. 38 - Prob. 38.7ECh. 38 - Prob. 38.8ECh. 38 - Prob. 38.9ECh. 38 - Prob. 38.10ECh. 38 - Prob. 38.11ECh. 38 - Prob. 38.12ECh. 38 - Prob. 38.13ECh. 38 - Prob. 38.14ECh. 38 - Prob. 38.15ECh. 38 - Prob. 38.16ECh. 38 - Prob. 38.17ECh. 38 - Prob. 38.18ECh. 38 - Prob. 38.19ECh. 38 - Prob. 38.20ECh. 38 - Prob. 38.21ECh. 38 - An electron and a positron are moving toward each...Ch. 38 - Prob. 38.23ECh. 38 - Prob. 38.24ECh. 38 - Prob. 38.25ECh. 38 - Prob. 38.26PCh. 38 - Prob. 38.27PCh. 38 - Prob. 38.28PCh. 38 - Prob. 38.29PCh. 38 - Prob. 38.30PCh. 38 - Prob. 38.31PCh. 38 - Prob. 38.32PCh. 38 - Prob. 38.33PCh. 38 - Prob. 38.34PCh. 38 - Prob. 38.35PCh. 38 - Prob. 38.36PCh. 38 - Prob. 38.37PCh. 38 - Prob. 38.38PCh. 38 - Prob. 38.39PCh. 38 - Prob. 38.40CPCh. 38 - Prob. 38.41PPCh. 38 - Prob. 38.42PPCh. 38 - Prob. 38.43PPCh. 38 - Prob. 38.44PPCh. 38 - Prob. 38.45PP
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- For collisions with free electrons, compare the Compton shift of a photon scattered as an angle of 30° to that of a photon scattered at 45Carrow_forwardIn the Compton scattering, the photon of energy 8,4 MeV is scattered from a free electron of mass 9.1×10−319.1×10−31 kg, What is the recoil angle of the electron, if the scattering angle is 52∘52∘?arrow_forwardPhotons of energy 0.7 MeV are scattered from electrons initially at rest. If the energy of the scattered photons is 0.5 MeV, find (a) the wave shift, (b) the angle at which the photons scatter, (c) the angle at which the electrons recoil, and (d) the kinetic energy of the recoiling electrons.arrow_forward
- How many x-ray photons per second are created by an x- ray tube that produces a flux of x rays having a power of 1.00 W? Assume the average energy per photon is 75.0 keV.arrow_forwardA photon collides with an electron, and is scattered in a direction 90.0∘ from its original direction. If the photon loses 28.0% of its momentum in the process, what was the photon's initial wavelength?arrow_forwardConsider a photon with wavelength 0.011 nm. l = 0.011 nm What is the momentum of the photon in kg m/s? What is its energy in MeV?arrow_forward
- A 700 keV gamma ray is incident on an electron at rest. If the scattered photon has a scattering angle of115° with respect to the direction of the incident photon, determine the following.(a) Energy (in keV) of the scattered photonkeV(b) Kinetic energy (in keV) of the scattered electronkeV(c) Recoil angle (in degrees) of the scattered electronarrow_forwardAn argon laser emits a beam of light of wavelength 4.88 × 10-7 m, the power in the beam being 100mW. How many photons per second are emitted by the laser? If the beam falls on the cesium cathode of a photocell, what photoelectric current would be observed, assuming 10% of the photons are able to eject an electron?Given that the limiting frequency v0 of cesium is 5.2 × 1014Hz, what reverse potential difference between the cell electrodes is needed to suppress the photocell current?arrow_forward
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