Fundamentals of Physics, Volume 1, Chapter 1-20
10th Edition
ISBN: 9781118233764
Author: David Halliday
Publisher: WILEY
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Chapter 38, Problem 47P
To determine
To find:
De Broglie wavelength of electron.
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An electron is accelerated from rest through a potential difference of 3.19 x 102 V. Determine the following for the electron.
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An electron has a de Broglie wavelength λ = 4.5×10−10 m . h=6.626×10−34 J⋅s, e=1.602×10−19 C, me=9.109×10−31 kg. What is its momentum? (p =h/)
Chapter 38 Solutions
Fundamentals of Physics, Volume 1, Chapter 1-20
Ch. 38 - Prob. 1QCh. 38 - Prob. 2QCh. 38 - Prob. 3QCh. 38 - Prob. 4QCh. 38 - Prob. 5QCh. 38 - Prob. 6QCh. 38 - Prob. 7QCh. 38 - Prob. 8QCh. 38 - Prob. 9QCh. 38 - Prob. 10Q
Ch. 38 - Prob. 11QCh. 38 - Prob. 12QCh. 38 - Prob. 13QCh. 38 - Prob. 14QCh. 38 - Prob. 15QCh. 38 - Prob. 16QCh. 38 - Prob. 1PCh. 38 - Prob. 2PCh. 38 - Prob. 3PCh. 38 - Prob. 4PCh. 38 - Prob. 5PCh. 38 - Prob. 6PCh. 38 - Prob. 7PCh. 38 - Prob. 8PCh. 38 - Prob. 9PCh. 38 - Prob. 10PCh. 38 - Prob. 11PCh. 38 - Prob. 12PCh. 38 - Prob. 13PCh. 38 - Prob. 14PCh. 38 - Prob. 15PCh. 38 - Prob. 16PCh. 38 - Prob. 17PCh. 38 - Prob. 18PCh. 38 - Prob. 19PCh. 38 - Prob. 20PCh. 38 - Prob. 21PCh. 38 - Prob. 22PCh. 38 - Prob. 23PCh. 38 - Prob. 24PCh. 38 - Prob. 25PCh. 38 - Prob. 26PCh. 38 - Prob. 27PCh. 38 - Prob. 28PCh. 38 - Prob. 29PCh. 38 - Prob. 30PCh. 38 - Prob. 31PCh. 38 - Prob. 32PCh. 38 - Prob. 33PCh. 38 - Prob. 34PCh. 38 - Prob. 35PCh. 38 - Prob. 36PCh. 38 - Prob. 37PCh. 38 - Prob. 38PCh. 38 - Prob. 39PCh. 38 - Prob. 40PCh. 38 - Prob. 41PCh. 38 - Prob. 42PCh. 38 - Prob. 43PCh. 38 - Prob. 44PCh. 38 - Prob. 45PCh. 38 - Prob. 46PCh. 38 - Prob. 47PCh. 38 - Prob. 48PCh. 38 - Prob. 49PCh. 38 - Prob. 50PCh. 38 - Prob. 51PCh. 38 - Prob. 52PCh. 38 - Prob. 53PCh. 38 - Prob. 54PCh. 38 - Prob. 55PCh. 38 - Prob. 56PCh. 38 - Prob. 57PCh. 38 - Prob. 58PCh. 38 - Prob. 59PCh. 38 - Prob. 60PCh. 38 - Prob. 61PCh. 38 - Prob. 62PCh. 38 - Prob. 63PCh. 38 - Prob. 64PCh. 38 - Prob. 65PCh. 38 - Prob. 66PCh. 38 - Prob. 67PCh. 38 - Prob. 68PCh. 38 - Prob. 69PCh. 38 - Prob. 70PCh. 38 - Prob. 71PCh. 38 - Prob. 72PCh. 38 - Prob. 73PCh. 38 - Prob. 74PCh. 38 - Prob. 75PCh. 38 - Prob. 76PCh. 38 - Prob. 77PCh. 38 - Prob. 78PCh. 38 - Prob. 79PCh. 38 - Prob. 80PCh. 38 - Prob. 81PCh. 38 - Prob. 82PCh. 38 - Prob. 83PCh. 38 - Prob. 84PCh. 38 - Prob. 85PCh. 38 - Prob. 86PCh. 38 - Prob. 87PCh. 38 - Prob. 88PCh. 38 - Prob. 89PCh. 38 - Prob. 90P
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- What is the de Brogue wavelength of an electron that is accelerated from rest through a potential difference of 20 keV?arrow_forwardWhat is the wavelength of (a) a 12-keV X-ray photon; (b) a 2.O-MeV y -ray photon?arrow_forwardAt what velocity will an electron have a wavelength of 1.00 m?arrow_forward
- What is the de Brogue wavelength of a proton whose kinetic energy is 2.0 MeV? 10.0 MeV?arrow_forwardDuring a certain experiment, the de Broglie wavelength of an electron is 460 nm = 4.6 ✕ 10−7 m, which is the same as the wavelength of blue light. How fast (in m/s) is the electron moving?arrow_forwardA) Calculate the de Broglie wavelength of a neutron (mn = 1.67493×10-27 kg) moving at one six hundredth of the speed of light (c/600). (Enter at least 4 significant figures.) B) Calculate the velocity of an electron (me = 9.10939×10-31 kg) having a de Broglie wavelength of 230.1 pm.arrow_forward
- Starting from rest, an electron accelerates through a potential difference of 49 V. What is its de Broglie wavelength? ( h = 6.63 × 10 −34 J ⋅s, m e = 9.11 × 10 −31 kg, and 1 eV = 1.60 × 10 −19 J)arrow_forwardWhen an electron is accelerated through a potential difference Δφ it acquires a kinetic energy eΔφ. Calculate the momentum, and hence the de Broglie wavelength, of an electron accelerated from rest through (a) 1.00 V. (b) 1.00 kV. (c) 100 kVarrow_forward(a) What is the de Broglie wavelength (in m) of a proton moving at a speed of 3.30 × 104 m/s? m (b) What is the de Broglie wavelength (in m) of a proton moving at a speed of 1.92 × 108 m/s? m m (c) What is the de Broglie wavelength for an electron having a kinetic energy of 3.15 MeV?arrow_forward
- Calculate the de Broglie wavelength of a proton moving at 3.09 ✕ 104 m/s and 2.28 ✕ 108 m/s. (a) 3.09 ✕ 104 m/s (b) 2.28 ✕ 108 m/sarrow_forwardA) Calculate the de Broglie wavelength of a neutron (mn = 1.67493×10-27 kg) moving at one six hundredth of the speed of light (c/600). Enter at least 4 significant figures. (I got the answer 949.4 pm but it is wrong, please help) B) Calculate the velocity of an electron (me = 9.10939×10-31 kg) having a de Broglie wavelength of 230.1 pm.arrow_forward(b) An electron confined in a one dimensional box emits a 200 nm photon in a quantum jump from n = 2 to n = 1. What is the length of the box? The mass of an electron is 9.11 x 1031 kg. (c) A proton confined in a one dimensional box emits a 2.0 MeV gamma-ray photon in a quantum jump from n = 2 to n = 1. What is the length of the box? The mass of a proton is 1.67 x 1027 kg.arrow_forward
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