Explanation 1) Concept: Determine the energy loss of photon from Compton shift, and find the fraction of loss of energy. 2) Formula: i) E = h f ii) ∆ λ = h m c ( 1 - c o s ∅ ) 3) Given: i) Energy of incident photon E ii) Frequency of scattered photon f ' iii) Scattering angle ∅ 4) Calculation: The photon energy is given as E = h f Frequency and wavelength is related as c = λ f Hence, f = c λ From conservation of energy, E = E ' + K Here E ' is energy of scattered photon, and energy loss of scattered photon is ∆ E = E - E ' The fraction loss of photon energy during collision is given by ∆ E E = E - E E = h f - h f ' h f Here f ' is the frequency of scattered wave, and it is less than the incident ray frequency f . ∆ E E = f - f ' f = c λ - c λ ' c λ ∆ E E = 1

Fundamentals of Physics, Volume 1, Chapter 1-20

10th Edition

ISBN: 9781118233764

Author: David Halliday

Publisher: WILEY

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Chapter 38, Problem 87P

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The fractional loss of energy of a photon during a collision is

∆EE=hf'mc2(1-cos∅)

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Chapter 38, Problem 86P

Chapter 38, Problem 88P

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Chapter 38 Solutions

Fundamentals of Physics, Volume 1, Chapter 1-20

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The fractional loss of energy of a photon during a collision is ∆ E E = h f ' m c 2 ( 1 - c o s ∅ )

Solution Summary: The author explains how the tional loss of energy of a photon is given by E=hf and the frequency of scattered wave, which is less than the incident ray frequency.

Concept explainers

To show:

The fractional loss of energy of a photon during a collision is

∆EE=hf'mc2(1-cos∅)

Want to see the full answer?

Chapter 38 Solutions

The fractional loss of energy of a photon during a collision is ∆ E E = h f ' m c 2 ( 1 - c o s ∅ )

Solution Summary: The author explains how the tional loss of energy of a photon is given by E=hf and the frequency of scattered wave, which is less than the incident ray frequency.

Concept explainers

To show: The fractional loss of energy of a photon during a collision is ∆EE=hf'mc2(1-cos∅)

Want to see the full answer?

Chapter 38 Solutions

To show:

The fractional loss of energy of a photon during a collision is

∆EE=hf'mc2(1-cos∅)