Explanation The principal quantum number which is denoted by n can take any integer values ( 1 , 2 , 3 , ...... ) . The orbital quantum number which is denoted by l can take any integer values from 0 up to n − 1 . Write the expression to obtain all possible values of orbital quantum number. l = n − 1 (I) Conclusion: Thus, the possible values of l for n = 7 are, Substitute 1 for n in equation (I) to calculate the value of l . l = 1 − 1 = 0 Substitute 2 for n in equation (I) to calculate the value of l . l = 2 − 1 = 1 Substitute 3 for n in equation (I) to calculate the value of l . l = 3 − 1 = 2 Substitute 4 for n in equation (I) to calculate the value of l

Modified Mastering Physics with Pearson eText -- Standalone Access Card -- for Physics for Scientists & Engineers with Modern Physics

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ISBN: 9780133882261

Author: Douglas C. Giancoli

Publisher: PEARSON

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Chapter 39, Problem 1P

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The values that l can have for n=7.

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Chapter 39, Problem 29Q

Chapter 39, Problem 2P

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Chapter 39 Solutions

Modified Mastering Physics with Pearson eText -- Standalone Access Card -- for Physics for Scientists & Engineers with Modern Physics

Ch. 39.2 - Prob. 1AE Ch. 39.2 - Prob. 1BE Ch. 39.3 - Prob. 1CE Ch. 39.4 - Prob. 1DE Ch. 39.4 - Prob. 1EE Ch. 39.5 - Prob. 1FE Ch. 39.7 - Prob. 1GE Ch. 39 - Prob. 1Q Ch. 39 - Prob. 2Q Ch. 39 - Prob. 3Q

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