Mastering Physics with Pearson eText -- Standalone Access Card -- for University Physics with Modern Physics (14th Edition)
14th Edition
ISBN: 9780133978216
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 39, Problem 39.67P
(a)
To determine
Expression for the energy of the photon in terms of the kinetic energy of one of the electron.
(b)
To determine
Which is greater the energy of the photon or kinetic energy of the electron.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
What are the energy and momentum of a photon of red light of wavelength
620 nanometers (nm)? What is the wavelength (in nm) of photons of energy 2.40 eV?
Coherent light is passed through two narrow slits whose separation is 20.0 mm. The second-order bright fringe in the interference pattern is located at an angle of 0.0300 rad. If electrons are used instead of light, what must the kinetic energy (in electron volts) of the electrons be if they are to produce an interference pattern for which the second-order maximum is also at 0.0300 rad?
Suppose you need to image the structure of a virus with a diameter of 50 nm. For a sharp image, the wavelength of the probing wave must be 5.0 nm or less. We have seen that, for imaging such small objects, this short wavelength is obtained by using an electron beam in an electron microscope. Why don’t we simply use short-wavelength electromagnetic waves? There’s a problem with this approach: As the wavelength gets shorter, the energy of a photon of light gets greater and could damage or destroy the object being studied. Let’s compare the energy of a photon and an electron that can provide the same resolution.
For the electron with a de broglie wavelength of 3.5 nm, what is the kinetic energy (in eV)?
Chapter 39 Solutions
Mastering Physics with Pearson eText -- Standalone Access Card -- for University Physics with Modern Physics (14th Edition)
Ch. 39.2 - Prob. 39.2TYUCh. 39.3 - Prob. 39.3TYUCh. 39.4 - Prob. 39.4TYUCh. 39.5 - Prob. 39.5TYUCh. 39.6 - Prob. 39.6TYUCh. 39 - Prob. 39.1DQCh. 39 - Prob. 39.2DQCh. 39 - Prob. 39.3DQCh. 39 - When an electron beam goes through a very small...Ch. 39 - Prob. 39.5DQ
Ch. 39 - Prob. 39.6DQCh. 39 - Prob. 39.7DQCh. 39 - Prob. 39.8DQCh. 39 - Prob. 39.9DQCh. 39 - Prob. 39.10DQCh. 39 - Prob. 39.11DQCh. 39 - Prob. 39.12DQCh. 39 - Prob. 39.13DQCh. 39 - Prob. 39.14DQCh. 39 - Prob. 39.15DQCh. 39 - Prob. 39.16DQCh. 39 - Prob. 39.17DQCh. 39 - Prob. 39.18DQCh. 39 - Prob. 39.19DQCh. 39 - Prob. 39.20DQCh. 39 - Prob. 39.21DQCh. 39 - When you check the air pressure in a tire, a...Ch. 39 - Prob. 39.1ECh. 39 - Prob. 39.2ECh. 39 - Prob. 39.3ECh. 39 - Prob. 39.4ECh. 39 - Prob. 39.5ECh. 39 - Prob. 39.6ECh. 39 - Prob. 39.7ECh. 39 - Prob. 39.8ECh. 39 - Prob. 39.9ECh. 39 - Prob. 39.10ECh. 39 - Prob. 39.11ECh. 39 - Prob. 39.12ECh. 39 - Prob. 39.13ECh. 39 - Prob. 39.14ECh. 39 - Prob. 39.15ECh. 39 - Prob. 39.16ECh. 39 - Prob. 39.17ECh. 39 - Prob. 39.18ECh. 39 - Prob. 39.19ECh. 39 - Prob. 39.20ECh. 39 - Prob. 39.21ECh. 39 - Prob. 39.22ECh. 39 - Prob. 39.23ECh. 39 - Prob. 39.24ECh. 39 - Prob. 39.25ECh. 39 - Prob. 39.26ECh. 39 - Prob. 39.27ECh. 39 - Prob. 39.28ECh. 39 - Prob. 39.29ECh. 39 - Prob. 39.30ECh. 39 - Prob. 39.31ECh. 39 - Prob. 39.32ECh. 39 - Prob. 39.33ECh. 39 - Prob. 39.34ECh. 39 - Prob. 39.35ECh. 39 - Prob. 39.36ECh. 39 - Prob. 39.37ECh. 39 - Prob. 39.38ECh. 39 - Prob. 39.39ECh. 39 - Prob. 39.40ECh. 39 - Prob. 39.41ECh. 39 - Prob. 39.42ECh. 39 - Prob. 39.43ECh. 39 - Prob. 39.44ECh. 39 - Prob. 39.45ECh. 39 - Prob. 39.46ECh. 39 - Prob. 39.47ECh. 39 - Prob. 39.48ECh. 39 - Prob. 39.49ECh. 39 - Prob. 39.50PCh. 39 - Prob. 39.51PCh. 39 - Prob. 39.52PCh. 39 - Prob. 39.53PCh. 39 - Prob. 39.54PCh. 39 - Prob. 39.55PCh. 39 - Prob. 39.56PCh. 39 - Prob. 39.57PCh. 39 - Prob. 39.58PCh. 39 - Prob. 39.59PCh. 39 - An Ideal Blackbody. A large cavity that has a very...Ch. 39 - Prob. 39.61PCh. 39 - Prob. 39.62PCh. 39 - Prob. 39.63PCh. 39 - Prob. 39.64PCh. 39 - Prob. 39.65PCh. 39 - Prob. 39.66PCh. 39 - Prob. 39.67PCh. 39 - Prob. 39.68PCh. 39 - Prob. 39.69PCh. 39 - Prob. 39.70PCh. 39 - Prob. 39.71PCh. 39 - Prob. 39.72PCh. 39 - Prob. 39.73PCh. 39 - Prob. 39.74PCh. 39 - Prob. 39.75PCh. 39 - Prob. 39.76PCh. 39 - Prob. 39.77PCh. 39 - Prob. 39.78PCh. 39 - Prob. 39.79PCh. 39 - Prob. 39.80PCh. 39 - A particle with mass m moves in a potential U(x) =...Ch. 39 - Prob. 39.82PCh. 39 - Prob. 39.83PCh. 39 - DATA In the crystallography lab where you work,...Ch. 39 - Prob. 39.85PCh. 39 - Prob. 39.86CPCh. 39 - Prob. 39.87CPCh. 39 - Prob. 39.88PPCh. 39 - Prob. 39.89PPCh. 39 - Prob. 39.90PPCh. 39 - Prob. 39.91PP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- In a beam of white light (wavelengths from 400 to 750 nm), what range of momentum can the photons have?arrow_forwardWhat is the change in wavelength when monochromatic X-rays are scattered by electrons through an angle of 30∘?arrow_forwardWhen a beam of electrons is directed at a suitably narrow pair of slits, a)one bright region with intensity decreasing exponentially on each side is observed at a screen behind the double slit. b)alternating areas of bright intensity and low intensity are observed behind the double slit. c)all the electrons pass through one slit and a single, sharply defined region of bright intensity is observed. b)two areas of bright, sharply defined intensity are observed, one behind each slit.arrow_forward
- need help with this question, thanks: The maximum change in wavelength during Compton scattering occurs when a the photon scatters at an angle of 90°. b the electron scatters at an angle of 90°. c the photon scatters at an angle of 180°. d the electron scatters at an angle of 180°.arrow_forwardIn attempting to reconcile the wave and particle models of light, some people have suggested that the photon rides up and down on the crests and troughs of the electromagnetic wave. What things are wrong with this description?arrow_forwardA beam of light or electrons passes through two closely spaced slits to create an interference pattern consisting of fringes. Which of the following statements is true about the relationship between the properties of the beam and the spacing of the interference fringes. a)When the light become more red, the interference fringes become spaced closer together. b)When the light become more blue, the interference fringes become spaced closer together. c)When the energy of the electrons decreases, the interference fringes become spaced closer together. d)When the light become more blue, the interference fringes become spaced further apart.arrow_forward
- Why go through the expense of building an electron microscope for studying very small objects such as organic molecules? Why not just use extremely short electromagnetic waves, which are much cheaper to generate?arrow_forwardX-rays with a wavelength of 1.43 Å scatter at an angle of 34.0 ∘ from a crystal. If n=1 , what is the distance between planes of atoms in the crystal that give rise to this scattering?arrow_forwardThe maximum distance between Jupiter and Earth is about 968 million km. How long will a photon of light take to travel from Jupiter to Earth?arrow_forward
- A laser used for lunar range-finding shoots a laser pulse with E0�0 = 0.12 JJ of energy. The reflectors on the moon are 45cm×45cm45cm×45cm. If we assume that the laser beam energy is uniformly distributed – a rather poor assumption but adequate for making an estimate – how much laser-light energy hits the reflector?arrow_forwardIf you shine light on a conducting metallic surface, the light can impart energy to electrons in the conductor, potentially freeing them from the surface if the energy is higher than the so-called "work function", which is the energy required to free the electron from the surface. If you place another conducting surface in a position at which it can catch these electrons, and connect these two conductors by another conductor such as a wire, you can generate a so-called photoelectric current. Suppose the work function of a particular metal is 4.8 x 10-19 J. If light can impart an energy of 14.4 x 10-19 J to each electron, what must be the potential difference of the two conducting surfaces in order to stop a photoelectric current? Which conducting surface should be at the higher potential?arrow_forwardAssuming that the smallest measurable wavelength in an experiment is 0.730 fm , what is the maximum mass of an object traveling at 465 m⋅ s^−1 for which the de Broglie wavelength is observable? ?=arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningUniversity Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax