Mastering Physics with Pearson eText -- Standalone Access Card -- for University Physics with Modern Physics (14th Edition)
14th Edition
ISBN: 9780133978216
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Chapter 39, Problem 39.86CP
(a)
To determine
To show: That the frequency of revolution of an electron is in its circular orbit around a stationary hydrogen nucleus is
(b)
To determine
To show: That when
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Consider the electron of a Li2+ ion that undergoes a transition from a higher energy state n to its adjacent lower energy state n – 1 (e.g. n = 2→1, 3→2, 4→3, etc) and emits a photon. Suppose the emitted photon is used to strike the surface of potassium, which has a threshold frequency of 5.464 × 10^14 s–1.a) Whatisthemaximuminitialquantumnumber,n, that is required in order to emit a photon with high enough energy to generate a photocurrent from the metal surface?b) Usingthenvaluesolvedinpart(a), calculate the maximum speed of the photoelectron from potassium. If you couldn’t solve for n in part (a), use n = 3.
Light with a frequency of 2.89×10152.89×1015 Hz ejects electrons from the surface of aluminum, which has a work function of 4.28 eV. What is the minimum de Broglie wavelength of the ejected electrons?
The light observed that is emitted by a hydrogen atom is explained by a simple model of its structure with one proton in its nucleus and an electron bound to it, but only with internal energies of the atom satisfying
EH=−RH/n2EH=−RH/n2
where RHRH is the Rydberg constant and nn is an integer such as 1, 2, 3 ... and so on. When a hydrogen atom in an excited state emits light, the photon carries away energy and the atom goes into a lower energy state.
Be careful about units. The Rydberg constant in eV is
13.605693009 eV
That would be multiplied by the charge on the electron 1.602× 10-19 C to give
2.18× 10-18 J
A photon with this energy would have a frequency f such that E=hf. Its wavelength would be λ = c/f = hc/E. Sometimes it is handy to measure the Rydberg constant in units of 1/length for this reason. You may see it given as 109737 cm-1 if you search the web, so be aware that's not joules.
The following questions are intended to help you understand the connection between…
Chapter 39 Solutions
Mastering Physics with Pearson eText -- Standalone Access Card -- for University Physics with Modern Physics (14th Edition)
Ch. 39.2 - Prob. 39.2TYUCh. 39.3 - Prob. 39.3TYUCh. 39.4 - Prob. 39.4TYUCh. 39.5 - Prob. 39.5TYUCh. 39.6 - Prob. 39.6TYUCh. 39 - Prob. 39.1DQCh. 39 - Prob. 39.2DQCh. 39 - Prob. 39.3DQCh. 39 - When an electron beam goes through a very small...Ch. 39 - Prob. 39.5DQ
Ch. 39 - Prob. 39.6DQCh. 39 - Prob. 39.7DQCh. 39 - Prob. 39.8DQCh. 39 - Prob. 39.9DQCh. 39 - Prob. 39.10DQCh. 39 - Prob. 39.11DQCh. 39 - Prob. 39.12DQCh. 39 - Prob. 39.13DQCh. 39 - Prob. 39.14DQCh. 39 - Prob. 39.15DQCh. 39 - Prob. 39.16DQCh. 39 - Prob. 39.17DQCh. 39 - Prob. 39.18DQCh. 39 - Prob. 39.19DQCh. 39 - Prob. 39.20DQCh. 39 - Prob. 39.21DQCh. 39 - When you check the air pressure in a tire, a...Ch. 39 - Prob. 39.1ECh. 39 - Prob. 39.2ECh. 39 - Prob. 39.3ECh. 39 - Prob. 39.4ECh. 39 - Prob. 39.5ECh. 39 - Prob. 39.6ECh. 39 - Prob. 39.7ECh. 39 - Prob. 39.8ECh. 39 - Prob. 39.9ECh. 39 - Prob. 39.10ECh. 39 - Prob. 39.11ECh. 39 - Prob. 39.12ECh. 39 - Prob. 39.13ECh. 39 - Prob. 39.14ECh. 39 - Prob. 39.15ECh. 39 - Prob. 39.16ECh. 39 - Prob. 39.17ECh. 39 - Prob. 39.18ECh. 39 - Prob. 39.19ECh. 39 - Prob. 39.20ECh. 39 - Prob. 39.21ECh. 39 - Prob. 39.22ECh. 39 - Prob. 39.23ECh. 39 - Prob. 39.24ECh. 39 - Prob. 39.25ECh. 39 - Prob. 39.26ECh. 39 - Prob. 39.27ECh. 39 - Prob. 39.28ECh. 39 - Prob. 39.29ECh. 39 - Prob. 39.30ECh. 39 - Prob. 39.31ECh. 39 - Prob. 39.32ECh. 39 - Prob. 39.33ECh. 39 - Prob. 39.34ECh. 39 - Prob. 39.35ECh. 39 - Prob. 39.36ECh. 39 - Prob. 39.37ECh. 39 - Prob. 39.38ECh. 39 - Prob. 39.39ECh. 39 - Prob. 39.40ECh. 39 - Prob. 39.41ECh. 39 - Prob. 39.42ECh. 39 - Prob. 39.43ECh. 39 - Prob. 39.44ECh. 39 - Prob. 39.45ECh. 39 - Prob. 39.46ECh. 39 - Prob. 39.47ECh. 39 - Prob. 39.48ECh. 39 - Prob. 39.49ECh. 39 - Prob. 39.50PCh. 39 - Prob. 39.51PCh. 39 - Prob. 39.52PCh. 39 - Prob. 39.53PCh. 39 - Prob. 39.54PCh. 39 - Prob. 39.55PCh. 39 - Prob. 39.56PCh. 39 - Prob. 39.57PCh. 39 - Prob. 39.58PCh. 39 - Prob. 39.59PCh. 39 - An Ideal Blackbody. A large cavity that has a very...Ch. 39 - Prob. 39.61PCh. 39 - Prob. 39.62PCh. 39 - Prob. 39.63PCh. 39 - Prob. 39.64PCh. 39 - Prob. 39.65PCh. 39 - Prob. 39.66PCh. 39 - Prob. 39.67PCh. 39 - Prob. 39.68PCh. 39 - Prob. 39.69PCh. 39 - Prob. 39.70PCh. 39 - Prob. 39.71PCh. 39 - Prob. 39.72PCh. 39 - Prob. 39.73PCh. 39 - Prob. 39.74PCh. 39 - Prob. 39.75PCh. 39 - Prob. 39.76PCh. 39 - Prob. 39.77PCh. 39 - Prob. 39.78PCh. 39 - Prob. 39.79PCh. 39 - Prob. 39.80PCh. 39 - A particle with mass m moves in a potential U(x) =...Ch. 39 - Prob. 39.82PCh. 39 - Prob. 39.83PCh. 39 - DATA In the crystallography lab where you work,...Ch. 39 - Prob. 39.85PCh. 39 - Prob. 39.86CPCh. 39 - Prob. 39.87CPCh. 39 - Prob. 39.88PPCh. 39 - Prob. 39.89PPCh. 39 - Prob. 39.90PPCh. 39 - Prob. 39.91PP
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- When an electron of an excited hydrogen atom descends, from an initial energy level (ni) to a lower (nf), characteristic electromagnetic radiation is emitted. The Bohr model of the H-atom allows the calculation of ΔE for any pair of energy levels. ΔE is related to the wavelength (λ) of the radiation according to Einstein's equation ( ΔE = [(hc)/λ]). Distinct series of spectral lines have been classified according to nf: Lyman series:nf=1 (91<λ<123 nm; near-UV). Balmer series:nf=2 (365<λ<658 nm; visible). Paschen series:nf=3 (819<λ<1877 nm; near-IR). Brackett series:nf=4 (1.456<λ<4.054 μm; short-to-mid-λ-IR) One of the lines in the emission spectrum of the hydrogen atom has a wavelength of λ = 434.3 nm. Identify the value of ninitial. Identify the value of nfinal .arrow_forwardWhen an electron of an excited hydrogen atom descends, from an initial energy level (ni) to a lower (nf), characteristic electromagnetic radiation is emitted. The Bohr model of the H-atom allows the calculation of ΔE for any pair of energy levels. ΔE is related to the wavelength (λ) of the radiation according to Einstein's equation ( ΔE = [(hc)/λ]). Distinct series of spectral lines have been classified according to nf: Lyman series:nf=1 (91<λ<123 nm; near-UV). Balmer series:nf=2 (365<λ<658 nm; visible). Paschen series:nf=3 (819<λ<1877 nm; near-IR). Brackett series:nf=4 (1.456<λ<4.054 μm; short-to-mid-λ-IR) One of the lines in the emission spectrum of the hydrogen atom has a wavelength of λ = 93.11 nm.: Identify the value of ninitial.: Identify the value of nfinal . hello, you submitted an answer to this question but It was still not clear to me how you got n intial from the bohr model equation. Can you please provide me with a more clear…arrow_forwardWhen an electron of an excited hydrogen atom descends, from an initial energy level (ni) to a lower (nf), characteristic electromagnetic radiation is emitted. The Bohr model of the H-atom allows the calculation of ΔE for any pair of energy levels. ΔE is related to the wavelength (λ) of the radiation according to Einstein's equation ( ΔE = [(hc)/λ]). Distinct series of spectral lines have been classified according to nf: Lyman series:nf=1 (91<λ<123 nm; near-UV). Balmer series:nf=2 (365<λ<658 nm; visible). Paschen series:nf=3 (819<λ<1877 nm; near-IR). Brackett series:nf=4 (1.456<λ<4.054 μm; short-to-mid-λ-IR) One of the lines in the emission spectrum of the hydrogen atom has a wavelength of λ = 121.6 nm. Identify the value of ninitial.arrow_forward
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