Concepts of Genetics (11th Edition)
11th Edition
ISBN: 9780321948915
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Chapter 4, Problem 40ESP
The following pedigree is characteristic of an inherited condition known as male precocious puberty, where affected males show signs of puberty by age 4. Propose a genetic explanation of this
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Chapter 4 Solutions
Concepts of Genetics (11th Edition)
Ch. 4 - In the guinea pig, one locus involved in the...Ch. 4 - In some plants a red flower pigment, cyanidin, is...Ch. 4 - Below are three pedigrees. For each trait,...Ch. 4 - Prob. 1CSCh. 4 - Prob. 2CSCh. 4 - Prob. 3CSCh. 4 - HOW DO WE KNOW? In this chapter, we focused on...Ch. 4 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 4 - In shorthorn cattle, coat color may be red, white,...Ch. 4 - In foxes, two alleles of a single gene, P and p,...
Ch. 4 - In mice, a short-tailed mutant was discovered....Ch. 4 - List all possible genotypes for the A, B, AB, and...Ch. 4 - With regard to the ABO blood types in humans,...Ch. 4 - In a disputed parentage case, the child is blood...Ch. 4 - The A and B antigens in humans may be found in...Ch. 4 - In chickens, a condition referred to as creeper...Ch. 4 - In rabbits, a series of multiple alleles controls...Ch. 4 - Three gene pairs located on separate autosomes...Ch. 4 - As in Problem 12, flower color may be red, white,...Ch. 4 - Horses can be cremello (a light cream color),...Ch. 4 - With reference to the eye color phenotypes...Ch. 4 - Pigment in mouse fur is only produced when the C...Ch. 4 - In rats, the following genotypes of two...Ch. 4 - Given the inheritance pattern of coat color in...Ch. 4 - In a species of the cat family, eye color can be...Ch. 4 - In a plant, a tall variety was crossed with a...Ch. 4 - In a unique species of plants, flowers may be...Ch. 4 - Five human matings (15), identified by both...Ch. 4 - A husband and wife have normal vision, although...Ch. 4 - In humans, the ABO blood type is under the control...Ch. 4 - In Drosophila, an X-linked recessive mutation,...Ch. 4 - Another recessive mutation in Drosophila, ebony...Ch. 4 - In Drosophila, the X-linked recessive mutation...Ch. 4 - While vermilion is X-linked in Drosophila and...Ch. 4 - In a cross in Drosophila involving the X-linked...Ch. 4 - Consider the three pedigrees below, all involving...Ch. 4 - In goats, the development of the beard is due to a...Ch. 4 - Predict the F1 and F2 results of crossing a male...Ch. 4 - Two mothers give birth to sons at the same time at...Ch. 4 - Discuss the topic of phenotypic expression and the...Ch. 4 - Prob. 35PDQCh. 4 - Labrador retrievers may be black, brown...Ch. 4 - A true-breeding purple-leafed plant isolated from...Ch. 4 - In Dexter and Kerry cattle, animals may be polled...Ch. 4 - A geneticist from an alien planet that prohibits...Ch. 4 - The following pedigree is characteristic of an...Ch. 4 - Students taking a genetics exam were expected to...Ch. 4 - In four oclock plants, many flower colors are...Ch. 4 - Proto-oncogenes stimulate cells to progress...Ch. 4 - Below is a partial pedigree of hemophilia in the...
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- A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?arrow_forwardA couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?arrow_forwardA couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?arrow_forward
- Pedigree Analysis Is a Basic Method in Human Genetics Using the pedigree provided, answer the following questions. a. Is the proband male or female? b. Is the grandfather of the proband affected? c. How many siblings does the proband have, and where is he or she in the birth order?arrow_forwardThe gene controlling ABO blood type and the gene underlying nail-patella syndrome are said to show linkage. What does that mean in terms of their relative locations in the genome? What does it mean in terms of how the two traits are inherited with respect to each other?arrow_forwardWhich members of the pedigree could have been carriers, and which might have been the source of the mutation?arrow_forward
- Phenylketonuria and alkaptonuria are both autosomal recessive diseases. If a person with PKU marries a person with AKU, what will the phenotype of their children be?arrow_forwardA rare blinding disease that has a relation to dengenerative factors is partially penetrant. In the following pedigrees for two families, the affected symptomatic individuals (black circles and squares) have been diagnosed with this disease due to the mutation in mitochondrial DNA m.14484T>C. If III.4 is homoplasmic for m.14484T>C in hair, blood, urine and other tissues examined. What will occur with IV.7 then?arrow_forwardChands syndrome is an autosomal recessive condition characterized by very curly hair, underdeveloped nails, and abnormally shaped eyelids. In the pedigree below: Which individuals must be carriers (heterozygotes)? ----- arrow_forward
- The following Pedigree shows an unknown genetic disorder. The disorder is believed to be caused by single gene mutations. For the following disorder, determine whether the mutant gene is located on an autosome or X chromosome. arrow_forwardThe following pedigree describes the inheritance of Lesch-Nyhan syndrome, an x-linked recessive disease. Affected individuals are shaded. what is the probability, that the indicated child (IV.1) will be affected by Lesch-Nyhan syndrome? show solutionarrow_forwardShown below is a pedigree for Phenylketonuria (PKU), an autosomal recessive metabolic disorder. The characteristic feature of PKU is severe mental retardation A) What is the probability that individual II-1 is heterozygous for this gene? B) What is the probability that individual III-4 is heterozygous for this gene? C) If individuals III-3 and III-4 were to marry, what is the probability that their child would express PKU?arrow_forward
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