MYPROGRAMMINGLAB WITH PEARSON ETEXT
MYPROGRAMMINGLAB WITH PEARSON ETEXT
8th Edition
ISBN: 9780134225340
Author: Deitel
Publisher: PEARSON
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Chapter 4, Problem 4.30E

(Replacing switch with if ... else)Rewrite the program of Fig. 4.7 by replacing the switch statement with a nested if ... else statement; be careful to deal with the default case properly Then rewrite this new version by replacing the nested if ... else statement with a series of if statements; here, too, be careful to deal with the default case properly (this is more difficult than in the nested if … else version). This exercise demonstrates that switch is a convenience and that any switch statement can be written with only single-selection statements.

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Code conversions Re-write the following program by changing ternary / conditionaloperator to if-else statement.
Which statement is false? O a. The if selection statement can have only one statement in its body. O b. A compound statement can be placed anywhere in a program that a single statement can b placed O c. A set of statements contained within a pair of braces ({ and }) is calleda compound statement. d. An if slection statement can have a compound statement in its body. Next
Question #1 Study the following C program and answer the below questions Hint: you might run it in Dev C++ before starting answering the questions! #include int main(void) { int number; char choice; printf("Please enter an integer number: " ) ; scanf("%d" , &number); printf("\nTo check whether the number is even or odd, press e \n"); printf("To check whether the number is positive or negative, press p \n"); printf("To check whether the number is multiple of 10, press m \n"); printf("\nPlease enter your choice: "); scanf(" %c" , &choice); switch(choice) { case 'e': case 'E': if (number % 2 == 0){ printf("\n%d is even \n" , number); } else { printf("\n%d is odd \n" , number); break; case 'p': case 'P': if (number > 0){ printf"\n%d is positive \n" , number); else if (number < 0){ printf("\n%d is negative \n" , number); } else { printf"\n%d is zero! \n" , number); break; case 'm': case 'M': if (number % 10 == 0){ printf("\n%d is a multiple of 10 \n" , number); } else { printf"\n%d is NOT a…

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