Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 4.6.2P
To determine
(a)
A W12 section of A992 steel using column load tables.
To determine
(b)
A W18 section of A592 steel using trial and error method.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
4.4-2 A W21 × 101 is used as a compression member with one end fixed and the other endfree. The length is 10 feet. What is the nominal compressive strength if Fy = 50 ksi?Note that this is a slender-element compression member, and the equations of AISCSection E7 must be used.
4.6-2 A 15-foot long column is pinned at the bottom and fixed against rotation but free totranslate at the top. It must support a service dead load of 100 kips and a service liveload of 100 kips.a. Select a W12 of A992 steel. Use the column load tables.1. Use LRFD.2. Use ASD.b. Select a W16 of A992 steel. Use the trial-and-error approach covered in Section 4.6.1. Use LRFD.2. Use ASD.
A column is to support an axial dead load of 900 kN and an axial live load of 1240 kN. Use fy = 414 MPa and f’c = 27.6 MPa. Assume 2% steel ratio and use 28 mm main bars and 10 mm ties/ spiral. Use NSCP 2015- and a 30-mm steel cover
Design the column shown in Figure using ASD method, which is subjected to a service deadload of 200 kips and a service live load of 530 kips. Use A992 steel and select a W-shape.
Chapter 4 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 4 - Prob. 4.3.1PCh. 4 - Prob. 4.3.2PCh. 4 - Prob. 4.3.3PCh. 4 - Prob. 4.3.4PCh. 4 - Prob. 4.3.5PCh. 4 - Prob. 4.3.6PCh. 4 - Prob. 4.3.7PCh. 4 - Prob. 4.3.8PCh. 4 - Prob. 4.4.1PCh. 4 - Prob. 4.4.2P
Ch. 4 - Prob. 4.6.1PCh. 4 - Prob. 4.6.2PCh. 4 - Prob. 4.6.3PCh. 4 - Prob. 4.6.4PCh. 4 - Prob. 4.6.5PCh. 4 - Prob. 4.6.6PCh. 4 - Prob. 4.6.7PCh. 4 - Prob. 4.6.8PCh. 4 - Prob. 4.6.9PCh. 4 - Prob. 4.7.1PCh. 4 - Prob. 4.7.2PCh. 4 - Prob. 4.7.3PCh. 4 - Use A992 steel and select a W14 shape for an...Ch. 4 - Prob. 4.7.5PCh. 4 - Prob. 4.7.6PCh. 4 - Prob. 4.7.7PCh. 4 - The frame shown in Figure P4.7-8 is unbraced, and...Ch. 4 - Prob. 4.7.9PCh. 4 - Prob. 4.7.10PCh. 4 - Prob. 4.7.11PCh. 4 - Prob. 4.7.12PCh. 4 - Prob. 4.7.13PCh. 4 - Prob. 4.7.14PCh. 4 - Prob. 4.8.1PCh. 4 - Prob. 4.8.2PCh. 4 - Prob. 4.8.3PCh. 4 - Prob. 4.8.4PCh. 4 - Prob. 4.9.1PCh. 4 - Prob. 4.9.2PCh. 4 - Prob. 4.9.3PCh. 4 - Prob. 4.9.4PCh. 4 - Prob. 4.9.5PCh. 4 - Prob. 4.9.6PCh. 4 - Prob. 4.9.7PCh. 4 - Prob. 4.9.8PCh. 4 - Prob. 4.9.9PCh. 4 - Prob. 4.9.10PCh. 4 - Prob. 4.9.11PCh. 4 - Prob. 4.9.12P
Knowledge Booster
Similar questions
- Design a square tied column of smallest cross-section to carry an axial dead load of 600 kN and an axiallive load of 500 kN. Assume fc = 21 MPa and fy = 276 MPa. Use 20 mm main bars and 10 mm ties.Pu =A g =t =A st =No. of bars =Maximum steel ratio = Iti s safe ? ___arrow_forwardQ. The (10+0.5R)-ft-long steel column is an W8 x 40 section that is fixed at both ends. The midpoint of the column is braced by two cables that prevent displacement in the x-direction. Determine the critical value of the axial load P. Use E = 29 x 106 psi for steel. Where R=37 Kindly answer this question as soon as. Figures are attachedarrow_forward1.Select a W12 of A992 steel. Use the column load tables. Use LRFD.2. For the conditions shown in Figure, use LRFD and select a W10 of A992 steel. Use LRFD.arrow_forward
- If the beam in Problem 5.5-9 i5 braced at A, B, and C, compute for the unbr Cb aced length AC (same as Cb for unbraced length CB). Do not include the beam weight in the loading. a. Use the unfactored service loads. b. Use factored loads.arrow_forwardA 20-foot long column is pinned at the bottom and fixed against rotation but free to translate at the top. It must support a service dead load of 110 kips and a service live load of 110 kips. a. Select a W12 of A992 steel. Use the column load tables. 1. Use LRFD. 2. Use ASD. b. Select a W18 of A529 Grade 55 steel. Use the trial-and-error approach covered in Section 4.6. 1. Use LRFD. 2. Use ASD.arrow_forwardDoes the column shown below have enough available strength to support the given working loads?Use LRFD. Take E=20,232 ksi ,ry=2.3 in, K=1,Fy=59.0 ksi, Ag=32.7 inarrow_forward
- Use A992 steel, select a W-shape for the upper girder that spans left to right and picks up the loading from the three floor beams. Assume the beam is simply supported. The maximum permissible live load deflection is L/360. The service dead loads consist of a 5-inch thick reinforced concrete floor slab (normal weight concrete), a partitionload of 25 psf, and 20 psf to account for suspended ceiling and mechanical equipment. Don’t forget to check with self-weight. The service live load is 100 psf. You may use AISC Table 3-2 and/or Table 3-10 to check for bending and shear. Use LRFD only. Take Cb = 1.0. Please show all work to verify that this beam is adequate for bending, shear and deflectionarrow_forwardA W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom. The properties are as follows: Ag = 14,968 sq.mm. rx= 133.65 mm, Ty = 77.47 mm Calculate the critical slenderness ratio if there is an additional lateral support in the weak direction at mid-height. If the columns sustains a service axial live load of 990 kN calculate the safe service axial dead load in kN by URFD. Calculate the allowable axial strength (kN) by ASD Calculate the allowable axial strength (kN) by ASD Calculate the design axial strength (kN) of the colurn by LRFD.arrow_forwardA built-up section consisting of W 350 x 90 with two 12 – mm plates welded to form a box section as shown in figure. The section is used as a column 10 meters long. The column is fixed at both ends, and braced at mid height about the weak axis (Y-axis). Use Fy = 248 MPa. Determine the axial load capacity of the column in kN.arrow_forward
- A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom with additional lateral support at mid height in the weak direction. The properties are as follows: Ag = 14,500 sq.mm, Ix= 258.6 x10^6 mm ^4 Iy=84.375 x 10^6 mm^4. 60. If the columns sustains a service axial live load of 990 KN calculate the safe service axial dead load in KN by LRFDarrow_forwardDetermine the critical buckling load for each of the columns, using the Euler equation. E = 29,000 ksi. Proportional limit = 36,000 psi. Assume simple ends and maximum permissible L/r = 200. The pipe section shown:a. L = 22 ft 0 inb. L = 18 ft 0 inc. L = 12 ft 0 inarrow_forwardP10.10. A W27×94 section of A572 Grade 50 steel 34 feet long, it is used as a simply supported beam. It is subjected to a factored concentrated load of 90 kips at 12 feet from each support. In addition, the beam is subjected to a factored moment of 340 kips-ft at its left end (counterclockwise). Neglect the self-weight of the beam in the calculations, and check whether the beam is safe according to the LRFD. Lateral support is only provided at the ends and load points.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning