Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Question
Chapter 4, Problem 4.7.14P
To determine
(a)
Use A992 steel and selecting a
To determine
(b)
Use A992 steel and selecting a
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The rigid frame shown in Figure is unbraced in the plane of the frame. In the direction perpendicular to the frame, the frame is braced at the joints. The connections at these points of bracing are simple (moment-free) connections. Roof girders are W14 x 30, and floor girders are W16 x 36. Member BC is a W10 x 45. Use A992 steel and select a W-shape for AB. Assume that the controlling load combination causes no moment in AB. The service dead load is 25 kips and the service live load is 75 kips. a. Use LRFD. b. Use ASD
The steel is supported by the steel tie rod in AB beam B. Steel connection tension rod is placed 2 meters to the left of B and C sliding bracket is placed and P is loaded between AC It is. By ignoring the weights of beams and connecting rods, they can be determine the largest P load it can carry. The diameter of the BD rod is 16 mm. E = 200GPa I = 150x(10^6)mm^4
A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long, pinned at the top fixed at bottom, and has additional support in the weak direction 3 m from the top. Properties of the section are as follows:
A = 14,500 mm^2
Ix = 258.6 x 10^6 mm^4
Iy = 84.375 x 10^6 mm^4
1. Calculate the critical slenderness ratio of the member.
a. 26.208
b. 45.882
c. 36.706
d. 27.529
2. calculate the nominal axial load capacity of the column
a. 3104 kN
b. 4851 kN
c. 4213 kN
d. 5344 kN
3. calculalte the service axial dead load if the service axial live load is twice as that of the dead load. Use LRFD.
a. 1354 kN
b. 992 kN
c. 1093 kN
d. 634 kN
Chapter 4 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 4 - Prob. 4.3.1PCh. 4 - Prob. 4.3.2PCh. 4 - Prob. 4.3.3PCh. 4 - Prob. 4.3.4PCh. 4 - Prob. 4.3.5PCh. 4 - Prob. 4.3.6PCh. 4 - Prob. 4.3.7PCh. 4 - Prob. 4.3.8PCh. 4 - Prob. 4.4.1PCh. 4 - Prob. 4.4.2P
Ch. 4 - Prob. 4.6.1PCh. 4 - Prob. 4.6.2PCh. 4 - Prob. 4.6.3PCh. 4 - Prob. 4.6.4PCh. 4 - Prob. 4.6.5PCh. 4 - Prob. 4.6.6PCh. 4 - Prob. 4.6.7PCh. 4 - Prob. 4.6.8PCh. 4 - Prob. 4.6.9PCh. 4 - Prob. 4.7.1PCh. 4 - Prob. 4.7.2PCh. 4 - Prob. 4.7.3PCh. 4 - Use A992 steel and select a W14 shape for an...Ch. 4 - Prob. 4.7.5PCh. 4 - Prob. 4.7.6PCh. 4 - Prob. 4.7.7PCh. 4 - The frame shown in Figure P4.7-8 is unbraced, and...Ch. 4 - Prob. 4.7.9PCh. 4 - Prob. 4.7.10PCh. 4 - Prob. 4.7.11PCh. 4 - Prob. 4.7.12PCh. 4 - Prob. 4.7.13PCh. 4 - Prob. 4.7.14PCh. 4 - Prob. 4.8.1PCh. 4 - Prob. 4.8.2PCh. 4 - Prob. 4.8.3PCh. 4 - Prob. 4.8.4PCh. 4 - Prob. 4.9.1PCh. 4 - Prob. 4.9.2PCh. 4 - Prob. 4.9.3PCh. 4 - Prob. 4.9.4PCh. 4 - Prob. 4.9.5PCh. 4 - Prob. 4.9.6PCh. 4 - Prob. 4.9.7PCh. 4 - Prob. 4.9.8PCh. 4 - Prob. 4.9.9PCh. 4 - Prob. 4.9.10PCh. 4 - Prob. 4.9.11PCh. 4 - Prob. 4.9.12P
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- The T-beam in the floor system has a slab thickness of 90 mm and supported by beams 6.5 m span. The beam is casts monolithically with the slab. The spacing of beams is 2 m on centers and width the web is 400 mm. The effective depth of the beam is 600 mm. It is reinforced at tension side with 8-28mm Φ bars. fc’ = 28 MPa, fy = 415 MPa 1. Which of the following most nearly give the effective width of the flange? a. 1565 mm b. 1305 mm c. 1275 mm d. 1625 mm 2. Which of the following most nearly gives the depth of compression block? a. 62.25 mm b. 52.86 mm c. 60.26 mm d. 58.29 mm 3. Which of the following gives the nominal moment capacity of the beam? a. 1461.25 kN/m b. 1156.36 kN/m c. 1163.15 kN/m d. 1172.58 kN/marrow_forwardA W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 6.6 m long, fixed at the top and bottom, and has additional support in the weak direction at mid-height. Properties of the section are as follows: A = 14,500 mm^2 Ix = 258.6 x 10^6 mm^4 Iy = 84.375 x 10^6 mm^4 Calculate the effective slenderness ratio with respect to strong axis buckling using theoretical value of k.arrow_forwardA built up I-section is formed from plates welded together as shown in the figure. It is to be used as a column L = 4.8 m long. All elements are A36 steel and connected such the section is fully effective. Using the following properties, calculate the flexural buckling stress, Fcr, in MPa using theoretical k. Flanges: b = 190 mm, tf = 16 mm Web: h = 340 mm, tw = 7 mmarrow_forward
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