Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 4, Problem 9P
To determine

The average force applied by the ball on the glove.

Expert Solution & Answer
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Answer to Problem 9P

Solution:

The average force exerted by the ball is 780.2N

Explanation of Solution

The concept we must use to solve this problem is average acceleration and force. The average acceleration is the change in velocity with respect to the elapsed time. So, the expression for the average acceleration is given as below:

aavg=vut…… (1)

Here, v is the final velocity, u is the initial velocity and t is the time.

The force on an object is calculated by using the Newton’s second law of motion as given below:

Favg=maavg…… (2)

Given:

Mass of the baseball m=0.140 kg

Distance s=11.0 cm

Initial speed u=0 m/s

Initial speed vi=35.0 m/s

Formula used:

aavg=vutFavg=maavg

Calculation:

Initially, we must find a time by using the expression of average speed as given below:

vavg=352=17.5 m/s

Thus, the time is –

t=dvavg=0.1117.5 m/s=6.28×103 s

Now, substitute, v=35 m/s, u=0 m/s and t=6.28×103 s in the equation (1)so the average acceleration is given as below:

aavg=vut=35 m/s-06.28×103 s=5573.2 m/s2

Now we can find the magnitude of force exerted by car by substituting m=0.140 kg and aavg=5573.2 m/s2 in equation (2)as given below:

Favg=maavg

        =(0.140 kg)(aavg=5573.2 m/s2)=780.2 N

Chapter 4 Solutions

Physics: Principles with Applications

Ch. 4 - Prob. 11QCh. 4 - Prob. 12QCh. 4 - Prob. 13QCh. 4 - Prob. 14QCh. 4 - Prob. 15QCh. 4 - Prob. 16QCh. 4 - Prob. 17QCh. 4 - Prob. 18QCh. 4 - A block is given a brief push so that it slides up...Ch. 4 - Prob. 20QCh. 4 - Prob. 21QCh. 4 - What force is needed to accelerate a sled (mass =...Ch. 4 - Prob. 2PCh. 4 - How much tension must a rope withstand if it is...Ch. 4 - According to a simplified model of a mammalian...Ch. 4 - Superman must stop a 120-km/h train in 150 m to...Ch. 4 - A person has a reasonable chance of surviving an...Ch. 4 - What average force is required to stop a 950-kg...Ch. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10PCh. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - A box weighing 77.0 N rests on a table. A rope...Ch. 4 - Figure 4-46 Problem 21. 21. (I) Draw the free-body...Ch. 4 - Prob. 21PCh. 4 - Arlene is to walk across a “high wire" strung...Ch. 4 - A window washer pulls herself upward using the...Ch. 4 - One 3.2-kg paint bucket is hanging by a massless...Ch. 4 - Prob. 25PCh. 4 - A train locomotive is pulling two cars of the same...Ch. 4 - Prob. 27PCh. 4 - A 27-kg chandelier hangs from a ceiling on a...Ch. 4 - Prob. 29PCh. 4 - Figure 4-53 [shows a block (mass mA) on a smooth...Ch. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - 35. (Ill) Suppose the pulley in Fig. 4-55 is...Ch. 4 - Prob. 34PCh. 4 - A force of 35.0 N is required to start a 6.0-kg...Ch. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - A box is given a push so that it slides across the...Ch. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - 46. (II) For the system of Fig. 4-32 (Example...Ch. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - A person pushes a 14.0-kg lawn mower at constant...Ch. 4 - Prob. 49PCh. 4 - (a) A box sits at rest on a rough 33° inclined...Ch. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 53PCh. 4 - A 25.0-kg box is released on a 27° incline and...Ch. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - The crate shown in Fig. 4-60 lies on a plane...Ch. 4 - A crate is given an initial speed of 3.0 m/s up...Ch. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - The coefficient of kinetic friction for a 22-kg...Ch. 4 - On an icy day, you worry about parking your car in...Ch. 4 - Two masses mA= 2.0 kg and mB= 5.0 kg are on...Ch. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 66GPCh. 4 - Prob. 67GPCh. 4 - Prob. 68GPCh. 4 - Prob. 69GPCh. 4 - Prob. 70GPCh. 4 - Prob. 71GPCh. 4 - Prob. 72GPCh. 4 - Prob. 73GPCh. 4 - Prob. 74GPCh. 4 - Prob. 75GPCh. 4 - Prob. 76GPCh. 4 - Prob. 77GPCh. 4 - Prob. 78GPCh. 4 - Prob. 79GPCh. 4 - Prob. 80GPCh. 4 - Prob. 81GPCh. 4 - Prob. 82GPCh. 4 - Prob. 83GPCh. 4 - Prob. 84GPCh. 4 - Prob. 85GPCh. 4 - Prob. 86GPCh. 4 - Prob. 87GPCh. 4 - Prob. 88GPCh. 4 - Prob. 89GP
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Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY