Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337671729
Author: SERWAY
Publisher: Cengage
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Chapter 41, Problem 46AP
To determine
The energy level diagram.
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A photoelectron is emitted from K shell (n = 1) of a carbon atom, and an election in L shell (n = 2) moves down to the vacancy in K shell. What is the wavelength, in the unit of nm, of the photon emitted during this transition?
Use for the energy difference between two states in an atom.
E0 = 13.6 eV and atomic number of carbon is Z = 12.
Use σ = 1 for the transition to K shell and σ = 7.4 for the transition to L shell
A visible (violet) emission spectral line for chromium (Cr) occurs at wavelength λ = 425.435 nm.What is the frequency (ν) of this light?(Mind the units carefully. Give your answers to six significant figures.)What is the magnitude of the energy change associated with the emission of one mole of photons of light with this wavelength?
Consider the atomic spectra for the H-atom: the Lyman series emits UV photons, the Balmer series emits visible photons, the Paschen series emits IR photons, and the Brackett series emits far IR photons. What type of photons would you expect from the next series? Briefly explain.
Chapter 41 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 41.3 - Prob. 41.1QQCh. 41.3 - Prob. 41.2QQCh. 41.4 - Prob. 41.3QQCh. 41.4 - Prob. 41.4QQCh. 41.8 - Prob. 41.5QQCh. 41 - Prob. 1PCh. 41 - Prob. 2PCh. 41 - Prob. 3PCh. 41 - Prob. 4PCh. 41 - Prob. 5P
Ch. 41 - Prob. 6PCh. 41 - Prob. 7PCh. 41 - Prob. 8PCh. 41 - Prob. 9PCh. 41 - Prob. 10PCh. 41 - Prob. 11PCh. 41 - Prob. 13PCh. 41 - Prob. 14PCh. 41 - Prob. 15PCh. 41 - Prob. 16PCh. 41 - Prob. 17PCh. 41 - Prob. 18PCh. 41 - Prob. 19PCh. 41 - Prob. 20PCh. 41 - Prob. 21PCh. 41 - Prob. 23PCh. 41 - Prob. 24PCh. 41 - Prob. 25PCh. 41 - Prob. 26PCh. 41 - Prob. 27PCh. 41 - Prob. 28PCh. 41 - Prob. 29PCh. 41 - Prob. 30PCh. 41 - Prob. 31PCh. 41 - Prob. 32PCh. 41 - Prob. 33PCh. 41 - Prob. 34PCh. 41 - Prob. 35PCh. 41 - Prob. 36PCh. 41 - Prob. 37APCh. 41 - Prob. 39APCh. 41 - Prob. 40APCh. 41 - Prob. 41APCh. 41 - Prob. 42APCh. 41 - Prob. 44APCh. 41 - Prob. 45APCh. 41 - Prob. 46APCh. 41 - Prob. 47APCh. 41 - Prob. 49APCh. 41 - Prob. 50APCh. 41 - Prob. 51CPCh. 41 - Prob. 52CP
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- Derive an expression for the ratio of X-ray photon frequency for two elements with atomic numbers Z1 and Z2.arrow_forwardSuppose the ionization energy of an atom is 4.10 eV. In the spectrum of this same atom, we observe emission lines with wavelengths 310 nm, 400 nm, and 1 377.8 nm. Use this information to construct the energy-level diagram with the fewest levels. Assume the higher levels are closer together.arrow_forwardThe following image is an energy level diagram for a simple atom, where E1 0.00 ev, E2 = 1.34 ev, and E3 3.95 ev. %3D n=3 E3=? n=2 E,=? n=1 - Ez=? What wavelengths appear in the atom's emission spectrum? (Enter your wavelengths in the order of smallest to largest.) 3.14x10-7 m 4.75×10-7 m 9.25x10-7 m You are correct. Your receipt no. is 162-5156 ? Previous Tries What wavelengths appear in the atom's absorption spectrum? (Enter your wavelengths in the order of smallest to largest.)arrow_forward
- The first five energy levels of the hydrogen atom are at −13.6 eV, −3.4 eV,−1.51 eV, −0.85 eV, and −0.54 eV. The emission spectrum of a hydrogen plasma lamp is a set of bright lines corresponding to all the possible transitions between these five levels.Sketch the far ultraviolet part of the spectrum you would expect from 80 nm wavelength to 130 nm. You should provide an x-axis with tickmarks and labels in nm, and label each brightline with its wavelength. Show your calculations of the wavelengths.arrow_forwardIf you look at it, there is an Ag atom with an atomic number of 47. Then, there are electrons from outside hitting electrons in the base shell (n=1) : a. how much energy does the electron need to bounce off? and is there any energy absorbed by the electrons? b. How much the radiation energy and wavelength produced by the transition of electrons from the L shell (n=2) to the ground shell (n=1) in filling the electron holes?arrow_forwardThe light observed that is emitted by a hydrogen atom is explained by a simple model of its structure with one proton in its nucleus and an electron bound to it, but only with internal energies of the atom satisfying EH=−RH/n2EH=−RH/n2 where RHRH is the Rydberg constant and nn is an integer such as 1, 2, 3 ... and so on. When a hydrogen atom in an excited state emits light, the photon carries away energy and the atom goes into a lower energy state. Be careful about units. The Rydberg constant in eV is 13.605693009 eV That would be multiplied by the charge on the electron 1.602× 10-19 C to give 2.18× 10-18 J A photon with this energy would have a frequency f such that E=hf. Its wavelength would be λ = c/f = hc/E. Sometimes it is handy to measure the Rydberg constant in units of 1/length for this reason. You may see it given as 109737 cm-1 if you search the web, so be aware that's not joules. The following questions are intended to help you understand the connection between…arrow_forward
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