Concept explainers
To find:
(a) in which square in Fig 42.6 of the textbook does the radionuclide 196I transform when it decays by an electron.
(b) if any further decays occur, by looking at Fig 42.6 of the textbook.
Answer to Problem 1Q
Solution:
(a) When the radionuclide 196I decays by an electron, it transforms into 196Pt.
(b) No further decay occurs after 196I decays by an electron, and transforms into 196Pt, because 196Pt is a stable nucleus.
Explanation of Solution
Given:
i. A radionuclide 196I decays by emitting an electron.
ii. Refer to Fig 42.6 of the textbook to know how this nuclide is transformed.
Concept
When a nuclide decays via an electron, a neutron is changing or transforming into a proton, hence the new nuclide will have the same mass A, but a higher Z, that is Z will be transformed to Z+1.
From Fig 42.6 of the textbook, we get
The Z of Ir is 77, and Z of Pt is 78; when 196I decays by emitting an electron, we get
From Fig 42.6 of the textbook, we can say that
Conclusion
When a nuclide decays by an electron (β- - decay), its Z transforms to Z+1, but it’s mass A remains unchanged.
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Chapter 42 Solutions
FUND.OF PHYSICS
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