Chapter 32, Problem 43PE

### College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000

Chapter
Section

### College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000
Textbook Problem

# (a) Calculate the energy released in the neutron−induced fission (similar to the spontaneous fission in Example 32.3) n + 238 U → 96 Sr + 140 Xe + 3 n ,given m ( 96 Sr ) = 95.921750   u and m ( 140 Xe ) = 139.92164 . (b) This result is about 6 MeV greater than the result for spontaneous fission. Why? (c) Con?rm that the total number at nucleons and total charge are conserved in this reaction.

(a)

To determine

The energy released in the neutron-induced fission.

Explanation

Given info:

â€ƒâ€ƒm(n)=1.0086649Â um(U238)=238.05078826um(S96r)=95.921750Â um(X140e)=139.92164uEnergyÂ ofÂ 1Â uÂ =Â 931

(b)

To determine

The reason the result is about 6 MeV greater than the result for spontaneous fission.

(c)

To determine

The total number of nucleons and total charge are conserved in this reaction.

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started