   Chapter 32, Problem 43PE

Chapter
Section
Textbook Problem

(a) Calculate the energy released in the neutron−induced fission (similar to the spontaneous fission in Example 32.3) n + 238 U → 96 Sr + 140 Xe + 3 n ,given m ( 96 Sr ) = 95.921750   u and m ( 140 Xe ) = 139.92164 . (b) This result is about 6 MeV greater than the result for spontaneous fission. Why? (c) Con?rm that the total number at nucleons and total charge are conserved in this reaction.

(a)

To determine

The energy released in the neutron-induced fission.

Explanation

Given info:

m(n)=1.0086649 um(U238)=238.05078826um(S96r)=95.921750 um(X140e)=139.92164uEnergy of 1 u = 931

(b)

To determine

The reason the result is about 6 MeV greater than the result for spontaneous fission.

(c)

To determine

The total number of nucleons and total charge are conserved in this reaction.

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