To: (a) show that the disintegration energy Q for the process 11 C 11 B + e + + ν is given by Q = (m C – m B - 2 m e ) c 2 (b) claculate the Q of the process, given the masses involved. Then compare Q with the maximum energy of the positron (which is given as 0.960 MeV)

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Answer 1

Question

Chapter 42, Problem 57P

To determine

To:

(a) show that the disintegration energy Q for the process ¹¹C ¹¹B + e⁺ + ν

is given by Q = (m_C– m_B- 2 m_e) c²

(b) claculate the Q of the process, given the masses involved. Then compare Q with the maximum energy of the positron (which is given as 0.960 MeV)

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Consider the following decay: 232 U → 228 Th + a . 232 U has a mass of 232.0371562 u, 228 Th has a mass of 228.0287411 u, and a has a mass of 4.002603 u. 92 90 92 90 Determine the disintegration energy (Q-value) in MeV. Q = Determine the KE of the daughter in MeV. KED = Determine the KE of the a particle in MeV & as a factor of Q. KE, = KEa = Qx Determine the speed of the a particle in terms of c. For an a particle, E. = 3.727 GeV. [NOTE: G stands for giga- which means 109 & M stands for mega- which means 10°.] Valpha = XC

Consider the following decay: 232 U 92 a mass of 4.002603 u. 228 Th+ a. 232 U has a mass of 232.0371562 u, 228 Th has a mass of 228.0287411 u, and a has 90 92 90 A.) Determine the disintegration energy (Q-value) in MeV. Q= B.) Determine the KE of the daughter in MeV. KED= C.) Determine the KE of the a particle in MeV & as a factor of Q. KE= KE=Qx D.) Determine the speed of the particle in terms of c. For an a particle, E = 3.727 GeV. [NOTE: G stands for giga- which means 10º & M stands for mega- which means 106.] Vα = XC

Known the rest energy for (233,92 U) is E_u=233.039u, with 1u=931.5MeV. he rest energies for one proton and one neutron are 938.27 MeV, 939.56 MeV, respectively.Compute the binding energy of (233,92 U) and the binding energy per nucleon.

Answer 2

Question

Chapter 42, Problem 57P

To determine

To:

(a) show that the disintegration energy Q for the process ¹¹C ¹¹B + e⁺ + ν

is given by Q = (m_C– m_B- 2 m_e) c²

(b) claculate the Q of the process, given the masses involved. Then compare Q with the maximum energy of the positron (which is given as 0.960 MeV)

Expert Solution & Answer

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Answer 3

Question

Chapter 42, Problem 57P

To determine

To:

(a) show that the disintegration energy Q for the process ¹¹C ¹¹B + e⁺ + ν

is given by Q = (m_C– m_B- 2 m_e) c²

(b) claculate the Q of the process, given the masses involved. Then compare Q with the maximum energy of the positron (which is given as 0.960 MeV)

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 42, Problem 57P

To determine

To:

(a) show that the disintegration energy Q for the process ¹¹C ¹¹B + e⁺ + ν

is given by Q = (m_C– m_B- 2 m_e) c²

(b) claculate the Q of the process, given the masses involved. Then compare Q with the maximum energy of the positron (which is given as 0.960 MeV)

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 42, Problem 57P

To determine

To:

(a) show that the disintegration energy Q for the process ¹¹C ¹¹B + e⁺ + ν

is given by Q = (m_C– m_B- 2 m_e) c²

(b) claculate the Q of the process, given the masses involved. Then compare Q with the maximum energy of the positron (which is given as 0.960 MeV)

Answer 6

Chapter 42, Problem 57P

To determine

To:

(a) show that the disintegration energy Q for the process ¹¹C ¹¹B + e⁺ + ν

is given by Q = (m_C– m_B- 2 m_e) c²

(b) claculate the Q of the process, given the masses involved. Then compare Q with the maximum energy of the positron (which is given as 0.960 MeV)

Answer 7

Chapter 42, Problem 57P

To determine

To:

(a) show that the disintegration energy Q for the process ¹¹C ¹¹B + e⁺ + ν

is given by Q = (m_C– m_B- 2 m_e) c²

(b) claculate the Q of the process, given the masses involved. Then compare Q with the maximum energy of the positron (which is given as 0.960 MeV)

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

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Answer 11

Ch. 42 - Prob. 1Q Ch. 42 - Prob. 2Q Ch. 42 - Prob. 3Q Ch. 42 - Prob. 4Q Ch. 42 - Prob. 5Q Ch. 42 - Prob. 6Q Ch. 42 - Prob. 7Q Ch. 42 - Prob. 8Q Ch. 42 - Prob. 9Q Ch. 42 - Prob. 10Q

To: (a) show that the disintegration energy Q for the process 11 C 11 B + e + + ν is given by Q = (m C – m B - 2 m e ) c 2 (b) claculate the Q of the process, given the masses involved. Then compare Q with the maximum energy of the positron (which is given as 0.960 MeV)

Solution Summary: The author explains that the disintegration energy Q for the process 11 C 11 B + e + + is given by Q = 0.960 MeV, which is the maximum energy of the positron.

Concept explainers

To:

(a) show that the disintegration energy Q for the process ¹¹C ¹¹B + e⁺ + ν

is given by Q = (m_C– m_B- 2 m_e) c²

(b) claculate the Q of the process, given the masses involved. Then compare Q with the maximum energy of the positron (which is given as 0.960 MeV)

Want to see the full answer?

Chapter 42 Solutions

To: (a) show that the disintegration energy Q for the process 11 C 11 B + e + + ν is given by Q = (m C – m B - 2 m e ) c 2 (b) claculate the Q of the process, given the masses involved. Then compare Q with the maximum energy of the positron (which is given as 0.960 MeV)

Solution Summary: The author explains that the disintegration energy Q for the process 11 C 11 B + e + + is given by Q = 0.960 MeV, which is the maximum energy of the positron.

Concept explainers