Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)
9th Edition
ISBN: 9781305266292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 43, Problem 25P
To determine
The ionic cohesive energy for NaCl.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The density of solid KCl is about 1980 kg/m3. Compute the nearest-neighbor distance in KCl, that is, the distance between neighboring K+ and Cl- ions. Note that KCl has the same lattice structure as NaCl.
At 300K, the intrinsic concentration of Ge is 2.5 × 1019 m-3. Given thet
m?
and 0.18
V. Sec
m?
respectively.
V. Sec
the mobility of electron and hole are 0.38
Find the conductivity of pure Ge semiconductor.
2.24 (Ω. m) - 1
2.24 (Ω. m)
0.4464 (Q. m)-1
1.24 (Q. m)
Other:
The parameters o and & in Lennard-Jones potential in Argon (Ar) crystals are o =
3.40 x 10-10 m and ɛ = 1.67 x 10-21 J. The lattice sums for the BCC (body-centered cubic)
structures are E C" Pī12 = 9.11418, ECC Pī = 12.2533, and the lattice sums for the FCC
structures are 2CC Pī12 =
potential, calculate the equilibrium separation and cohesive energies (in unit of electron voltage
or eV) for BCC and FCC configurations.
-6
%3|
12.13188, ECC Pi = 14.45392. Using the Lennard-Jones
%3D
Chapter 43 Solutions
Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)
Ch. 43.1 - For each of the following atoms or molecules,...Ch. 43.2 - Prob. 43.2QQCh. 43.2 - Prob. 43.3QQCh. 43 - Prob. 1OQCh. 43 - Prob. 2OQCh. 43 - Prob. 3OQCh. 43 - Prob. 4OQCh. 43 - Prob. 5OQCh. 43 - Prob. 6OQCh. 43 - Prob. 7OQ
Ch. 43 - Prob. 1CQCh. 43 - Prob. 2CQCh. 43 - Prob. 3CQCh. 43 - Prob. 4CQCh. 43 - Prob. 5CQCh. 43 - Prob. 6CQCh. 43 - Prob. 7CQCh. 43 - Prob. 8CQCh. 43 - Discuss models for the different types of bonds...Ch. 43 - Prob. 10CQCh. 43 - Prob. 1PCh. 43 - Prob. 2PCh. 43 - Prob. 3PCh. 43 - Prob. 4PCh. 43 - Prob. 5PCh. 43 - Prob. 6PCh. 43 - Prob. 7PCh. 43 - Prob. 8PCh. 43 - Prob. 9PCh. 43 - Prob. 10PCh. 43 - Prob. 12PCh. 43 - Prob. 13PCh. 43 - Prob. 14PCh. 43 - Prob. 15PCh. 43 - Prob. 16PCh. 43 - The nuclei of the O2 molecule are separated by a...Ch. 43 - Prob. 18PCh. 43 - Prob. 19PCh. 43 - Prob. 20PCh. 43 - Prob. 21PCh. 43 - Prob. 22PCh. 43 - Prob. 23PCh. 43 - Prob. 24PCh. 43 - Prob. 25PCh. 43 - Prob. 27PCh. 43 - Prob. 28PCh. 43 - Prob. 29PCh. 43 - Prob. 30PCh. 43 - Prob. 31PCh. 43 - Prob. 32PCh. 43 - Prob. 33PCh. 43 - Prob. 34PCh. 43 - Prob. 35PCh. 43 - Prob. 36PCh. 43 - Prob. 37PCh. 43 - Prob. 38PCh. 43 - Prob. 39PCh. 43 - Prob. 40PCh. 43 - Prob. 41PCh. 43 - Prob. 42PCh. 43 - Prob. 43PCh. 43 - Prob. 44PCh. 43 - Prob. 45PCh. 43 - Prob. 46PCh. 43 - Prob. 47PCh. 43 - Prob. 49PCh. 43 - Prob. 50PCh. 43 - Prob. 51PCh. 43 - A direct and relatively simple demonstration of...Ch. 43 - Prob. 53PCh. 43 - Prob. 54APCh. 43 - Prob. 55APCh. 43 - Prob. 56APCh. 43 - Prob. 57APCh. 43 - Prob. 58APCh. 43 - Prob. 59APCh. 43 - Prob. 61APCh. 43 - Prob. 62APCh. 43 - Prob. 63CPCh. 43 - As an alternative to Equation 43.1, another useful...
Knowledge Booster
Similar questions
- The bond length in the BrF molecule is 178 pm and the measured dipole moment is 1.29 D (debyes). What is the magnitude of the negative charge (in units of the electronic charge e) on F in BrF? (1 debye = 3.34 × 10−30 coulomb-meters; electronic charge = e = 1.6 × 10−19 coulombs). A. 0.15 B. 0.24 C. 0.33 D. 1.00 E. 1.6 × 10−19arrow_forwardThe ionic crystal of NaCl has an fcc structure as shown below with the position of the Cl atom located at : (0 0 0); (½ ½ 0); ( ½ 0 %) and (0 ½) and Na atom is located at : (½ ½½) + fcc translation. The following are the physical data of NaCl: - Ionic radius Na = 0.98 A, Cl ion radius 1.81 A Atomic mass of Na = 22.99 amu, Atomic mass of Cl = 35.45 amu NaCl bulk modulus = 2.40 x 1010 N/m - Madelung's constant = 1.75 Young's modulus in the direction [100] = 5 x 1010 Nm-2 Debye temperature = 281 K - State the structural factors of NaCl, F in fNa and fCl (f = atomic scattering factor). Also determine the condition (h k 1) so that the value of F = 0.arrow_forwardGiven that the spacing of lines in the microwave spectrum of 35C1¹⁹F, which may be considered as a rigid rotator, is constant at 1.033 cm¹, calculate the following properties of the molecule: b. The bond length. a. The moment of inertia [Note: m(³5Cl) = 34.9688 u, m(¹⁹F) = 18.9984 u.]arrow_forward
- a. The term linear atomic density is derived for FCC [111], [100] the vectors in terms of radius b. Calculate the linear density of the two vectors of copper. 19:43 /arrow_forwardIn solid KCI the smallest distance between the centers of a. potassium ion and a chloride ion is 314 pm. Calculate the length of the edge of the unit cell and the density of KCI, assuming it has the same structure as sodium chloride.arrow_forwardA sample of copper has a mass of 10.68 g when measured in air. It has a mass of 9.47 g when measured in water. Answer these three questions: How many atoms are in the sample? What is the simple volume of the space including and surrounding each atom? Assume the atoms are evenly distributed throughout the sample. That is no FCC, BCC, or HCP crystal structure. What is the diameter of each atom?arrow_forward
- The spacing between two adjacent lines in the pure rotational spectrum of a diatomic molecule is 20.0 cm ¹. Given KBT = 200 cm-¹ (at a specific temperature), calculate the relative population of the J-6 level O 1.6 O 3.8 O 2.7 O 2.4arrow_forward11. a) Determine which planes in an fcc structure have the highest density of atoms. b) Evaluate this density in atoms/cm² for Cu. 12. Repeat Problem 11 for Fe, which has a bcc structure. 13. Show that the maximum packing ratio in the diamond structure is n/3/16. [Hint: The structure may be viewed as two interpenetrating fcc lattices, arranged such that each atom is surrounded by four other atoms, forming a regular tetrahedron.]arrow_forwardThe internuclear distance (bond length) of carbon monoxide molecule is 1.13 Å. Calculate the energy (in joules and eV) of this molecule in the first excited rotational level. Also calculate the angular velocity of the molecule. Given atomic masses of 12^C = 1.99x10^-26 kg; 16^O = 2.66x10^-26 kg.arrow_forward
- The equilibrium dissociation energy of O2 is De = 4.314 ev. The basic vibration frequency of O2 is f = 1620.0 cm -1. So how much energy is actually needed to dissociate O2 molecules at n = 3 vibrational level? Give your answer in EV.arrow_forwardThe general expression for the Fermi energy of a metal at OK is 3.65X10-19x n2/3ev more 3.65X1019Xn?eV O 3.65X1019Xn2/3eV 3.65X1019Xn1/3eVarrow_forwardSuppose the temperature is T = 300 *. Determine the probabilitytrat a state 3kt above the Fermi energy level is occupied by an electron. а. 47.4% O b. 7.44% О с. 74.4% d. 4.74%arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning