Chapter 4.4, Problem 2WE

To determine

Value of x in the given figure.

Answer to Problem 2WE

Value of $x={45}^o$

Explanation of Solution

Given:

The given figure is,

  

The figure is,

  

As given, side $AB=BC,\angle ACB=x$ and $\angle ABC={90}^o$

So, the given triangle is right isosceles triangle.

So, $\angle ACB=\angle BAC=x^o$

Therefore,

  $\begin{array}{l}\angle ABC+ACB+\angle BAC={180}^o\\ {90}^o+x+x={180}^o\\ \Rightarrow x={45}^o\end{array}$

Therefore, $x={45}^o$