World of Chemistry
World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
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Chapter 5, Problem 3A

(a)

Interpretation Introduction

Interpretation: The given number 6.235×102 needs to be written as an ordinary decimal number.

Concept introduction: The expression of a number as a product of a number between 1 and 10 and appropriate

Conversion from scientific notation to real number is as follows:

If n>0 then, N×10n=N×10×10×.......n(Exponent)times

If n<0 then, N×10n=N10×10×.......n(Exponent)times

(a)

Expert Solution
Check Mark

Answer to Problem 3A

The ordinary decimal number is 0.06235.

Explanation of Solution

The given number is 6.235×102 . Scientific notation exists of a 6.235 coefficient that is multiplied by 10 raised to an exponent -2.

Move the decimal point in the base 2 places to left, adding extra zeros as needed.

Conversions of real numbers that starts with base and divide by 2 tens is as follows:

  6.23510×10=0.06235

Thus ordinary decimal number is 0.06235.

(b)

Interpretation Introduction

Interpretation: The given number 7.229×103 needs to be written as an ordinary decimal number.

Concept introduction: The expression of a number as a product of a number between 1 and 10 and appropriate

Conversion from scientific notation to real number is as follows:

If n>0 then, N×10n=N×10×10×.......n(Exponent)times

If n<0 then, N×10n=N10×10×.......n(Exponent)times

(b)

Expert Solution
Check Mark

Answer to Problem 3A

The ordinary decimal number is 7229.

Explanation of Solution

The given number is 7.229×103 . Scientific notation exists of a 7.229 coefficient that is multiplied by 10 raised to an exponent 3.

Move the decimal point in the base 3 places to left, adding extra zeros as needed.

Conversions of real numbers that starts with base and divide by 3 tens is as follows:

  7.229×10×10×10=7229

Thus ordinary decimal number is 7229.

(c)

Interpretation Introduction

Interpretation: The given number 5.001×106 needs to be written in ordinary decimal number.

Concept introduction: The expression of a number as a product of a number between 1 and 10 and appropriate

Conversion from scientific notation to real number is as follows:

If n>0 then, N×10n=N×10×10×.......n(Exponent)times

If n<0 then, N×10n=N10×10×.......n(Exponent)times

(c)

Expert Solution
Check Mark

Answer to Problem 3A

The ordinary decimal number is 0.000005.

Explanation of Solution

The given number is 5.001×106 . Scientific notation exists of a 5.001 coefficient that is multiplied by 10 raised to an exponent -6.

Move the decimal point in the base 6 places to left, adding extra zeros as needed.

Conversions of real numbers that starts with base and divide by 6 tens is as follows:

  5.00110×10×10×10×10×10=0.000005

Thus ordinary decimal number is 0.000005.

(d)

Interpretation Introduction

Interpretation: The given number 8.621×104 needs to be converted into an ordinary decimal number. Concept introduction: The expression of a number as a product of a number between 1 and 10 and appropriate

Conversion from scientific notation to real number is as follows:

If n>0 then, N×10n=N×10×10×.......n(Exponent)times

If n<0 then, N×10n=N10×10×.......n(Exponent)times

(d)

Expert Solution
Check Mark

Answer to Problem 3A

The ordinary decimal number is 86210.

Explanation of Solution

The given number is 8.621×104 . Scientific notation exists of an 8.621 coefficient that is multiplied by 10 raised to an exponent 4.

Move the decimal point in the base 4 places to left, adding extra zeros as needed.

Conversions of real numbers that starts with base and divide by 4 tens is as follows:

  8.621×10×10×10×10=86210

Thus ordinary decimal number is 86210.

Chapter 5 Solutions

World of Chemistry

Ch. 5.2 - Prob. 6RQCh. 5.2 - Prob. 7RQCh. 5.3 - Prob. 1RQCh. 5.3 - Prob. 2RQCh. 5.3 - Prob. 3RQCh. 5.3 - Prob. 4RQCh. 5.3 - Prob. 5RQCh. 5.3 - Prob. 6RQCh. 5.3 - Prob. 7RQCh. 5 - Prob. 1ACh. 5 - Prob. 2ACh. 5 - Prob. 3ACh. 5 - Prob. 4ACh. 5 - Prob. 5ACh. 5 - Prob. 6ACh. 5 - Prob. 7ACh. 5 - Prob. 8ACh. 5 - Prob. 9ACh. 5 - Prob. 10ACh. 5 - Prob. 11ACh. 5 - Prob. 12ACh. 5 - Prob. 13ACh. 5 - Prob. 14ACh. 5 - Prob. 15ACh. 5 - Prob. 16ACh. 5 - Prob. 17ACh. 5 - Prob. 18ACh. 5 - Prob. 19ACh. 5 - Prob. 20ACh. 5 - Prob. 21ACh. 5 - Prob. 22ACh. 5 - Prob. 23ACh. 5 - Prob. 24ACh. 5 - Prob. 25ACh. 5 - Prob. 26ACh. 5 - Prob. 27ACh. 5 - Prob. 28ACh. 5 - Prob. 29ACh. 5 - Prob. 30ACh. 5 - Prob. 31ACh. 5 - Prob. 32ACh. 5 - Prob. 33ACh. 5 - Prob. 34ACh. 5 - Prob. 35ACh. 5 - Prob. 36ACh. 5 - Prob. 37ACh. 5 - Prob. 38ACh. 5 - Prob. 39ACh. 5 - Prob. 40ACh. 5 - Prob. 41ACh. 5 - Prob. 42ACh. 5 - Prob. 43ACh. 5 - Prob. 44ACh. 5 - Prob. 45ACh. 5 - Prob. 46ACh. 5 - Prob. 47ACh. 5 - Prob. 48ACh. 5 - Prob. 49ACh. 5 - Prob. 50ACh. 5 - Prob. 51ACh. 5 - Prob. 52ACh. 5 - Prob. 53ACh. 5 - Prob. 54ACh. 5 - Prob. 55ACh. 5 - Prob. 56ACh. 5 - Prob. 57ACh. 5 - Prob. 58ACh. 5 - Prob. 59ACh. 5 - Prob. 60ACh. 5 - Prob. 61ACh. 5 - Prob. 62ACh. 5 - Prob. 63ACh. 5 - Prob. 64ACh. 5 - Prob. 65ACh. 5 - Prob. 66ACh. 5 - Prob. 67ACh. 5 - Prob. 68ACh. 5 - Prob. 69ACh. 5 - Prob. 70ACh. 5 - Prob. 71ACh. 5 - Prob. 72ACh. 5 - Prob. 73ACh. 5 - Prob. 74ACh. 5 - Prob. 75ACh. 5 - Prob. 1STPCh. 5 - Prob. 2STPCh. 5 - Prob. 3STPCh. 5 - Prob. 4STPCh. 5 - Prob. 5STPCh. 5 - Prob. 6STPCh. 5 - Prob. 7STPCh. 5 - Prob. 8STPCh. 5 - Prob. 9STP
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